Bundle: Physics for Scientists and Engineers with Modern Physics, Loose-leaf Version, 9th + WebAssign Printed Access Card, Multi-Term
9th Edition
ISBN: 9781305932302
Author: Raymond A. Serway, John W. Jewett
Publisher: Cengage Learning
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Chapter 32, Problem 65AP
(a)
To determine
The value of
(b)
To determine
The value of
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For the circuit shown in Fig. Q1(a), the capacitor is initially charged to 3.5 V with polarity shown.
compute the time constant, T of the circuit.
I = 5.5 mA
↑
R₁
R₂
2.6 ΚΩ
18.7 ΚΩ
Fig. Ql(a)
S
C = 3.3 uF
+
3.5 V
You have a circuit consisting of a power supply,
switch, resistor, two capacitors, and
voltage/current probes. The resistor has the
value R1 = (1.8 ± 10%) MQ. The capacitors have
%3D
the values C1 = (0.6 ± 20%) µF and C2 = (2.2 ±
20%) µF. The logger pro data resembles the plot
below.
40
35
30
25
20
15
10
1 2 3
5 6
8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25
a)
Label the title and all the axes on the
plot above. Identify which region corresponds
to the capacitors charging and discharging. Be
sure to include appropriate units (MKS).
Problem 4: The charge on a capacitor in a circuit is given by
q(t) = qmax cos(wt + q)
Enter an expression for the current flowing into the capacitor as a function of time.
I(t) = 1
Chapter 32 Solutions
Bundle: Physics for Scientists and Engineers with Modern Physics, Loose-leaf Version, 9th + WebAssign Printed Access Card, Multi-Term
Ch. 32.1 - A coil with zero resistance has its ends labeled a...Ch. 32.2 - Prob. 32.2QQCh. 32.3 - Prob. 32.3QQCh. 32.4 - Prob. 32.4QQCh. 32.5 - (i) At an instant of time during the oscillations...Ch. 32 - Prob. 1OQCh. 32 - Prob. 2OQCh. 32 - Prob. 3OQCh. 32 - Prob. 4OQCh. 32 - Prob. 5OQ
Ch. 32 - Prob. 6OQCh. 32 - Prob. 7OQCh. 32 - Prob. 1CQCh. 32 - Prob. 2CQCh. 32 - Prob. 3CQCh. 32 - Prob. 4CQCh. 32 - Prob. 5CQCh. 32 - Prob. 6CQCh. 32 - The open switch in Figure CQ32.7 is thrown closed...Ch. 32 - Prob. 8CQCh. 32 - Prob. 9CQCh. 32 - Prob. 10CQCh. 32 - Prob. 1PCh. 32 - Prob. 2PCh. 32 - Prob. 3PCh. 32 - Prob. 4PCh. 32 - Prob. 5PCh. 32 - Prob. 6PCh. 32 - Prob. 7PCh. 32 - Prob. 8PCh. 32 - Prob. 9PCh. 32 - Prob. 10PCh. 32 - Prob. 11PCh. 32 - Prob. 12PCh. 32 - Prob. 13PCh. 32 - Prob. 14PCh. 32 - Prob. 15PCh. 32 - Prob. 16PCh. 32 - Prob. 17PCh. 32 - Prob. 18PCh. 32 - Prob. 19PCh. 32 - Prob. 20PCh. 32 - Prob. 21PCh. 32 - Prob. 22PCh. 32 - Prob. 23PCh. 32 - Prob. 24PCh. 32 - Prob. 25PCh. 32 - Prob. 26PCh. 32 - Prob. 27PCh. 32 - Prob. 28PCh. 32 - Prob. 29PCh. 32 - Prob. 30PCh. 32 - Prob. 31PCh. 32 - Prob. 32PCh. 32 - Prob. 33PCh. 32 - Prob. 34PCh. 32 - Prob. 35PCh. 32 - Prob. 36PCh. 32 - Prob. 37PCh. 32 - Prob. 38PCh. 32 - Prob. 39PCh. 32 - Prob. 40PCh. 32 - Prob. 41PCh. 32 - Prob. 42PCh. 32 - Prob. 43PCh. 32 - Prob. 44PCh. 32 - Prob. 45PCh. 32 - Prob. 46PCh. 32 - Prob. 47PCh. 32 - Prob. 48PCh. 32 - Prob. 49PCh. 32 - Prob. 50PCh. 32 - Prob. 51PCh. 32 - Prob. 52PCh. 32 - Prob. 53PCh. 32 - Prob. 54PCh. 32 - Prob. 55PCh. 32 - Prob. 56PCh. 32 - Prob. 57PCh. 32 - Prob. 58PCh. 32 - Electrical oscillations are initiated in a series...Ch. 32 - Prob. 60APCh. 32 - Prob. 61APCh. 32 - Prob. 62APCh. 32 - A capacitor in a series LC circuit has an initial...Ch. 32 - Prob. 64APCh. 32 - Prob. 65APCh. 32 - At the moment t = 0, a 24.0-V battery is connected...Ch. 32 - Prob. 67APCh. 32 - Prob. 68APCh. 32 - Prob. 69APCh. 32 - Prob. 70APCh. 32 - Prob. 71APCh. 32 - Prob. 72APCh. 32 - Prob. 73APCh. 32 - Prob. 74APCh. 32 - Prob. 75APCh. 32 - Prob. 76APCh. 32 - Prob. 77APCh. 32 - Prob. 78CPCh. 32 - Prob. 79CPCh. 32 - Prob. 80CPCh. 32 - Prob. 81CPCh. 32 - Prob. 82CPCh. 32 - Prob. 83CP
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- For the circuit shown in Fig. Q1(a), the capacitor is initially charged to 3.5 V with polarity shown. compute the voltage vc(t) and the current ic (t) when the switch (S) is closed. I = 5.5 mA ↑ R₁ R₂ 2.6 ΚΩ • 8.7 ΚΩ Fig. Ql(a) S C = 3.3 uF + 3.5 Varrow_forwardThe voltage V in a simple electrical circuit is slowly decreasing as the battery wears out. The resistance R is slowly increasing as the resistor heats up. Use Ohm's Law, V = IR, to find how the current I is changing at the moment when R = 356 Ω, I = 0.02 A, dV/dt = −0.01 V/s, and dR/dt = 0.06 Ω/s. (Round your answer to six decimal places.)arrow_forwardThe following equations describe an electric circuit. −I1(247 Ω) + 5.80 V − I2(381 Ω) = 0 I2(381 Ω) + I3(150 Ω) − 3.10 V = 0 I1 + I3 − I2 = 0 Calculate the unknowns (in mA). With respect to the 5.8 V battery, consider current moving toward the positive pole as positive and current moving toward the negative pole as negative. THE FOLLOWING GIVEN ANSWERS WERE INCORRECT: I1= -10.008 mA I2= -0.868 mA I3= 0.139 mAarrow_forward
- The emf source, ɛ=4.5 V, of the circuit shown in the figure has negligible internal resistance. The resistors have resistances R1=2 Q and R2=4.7 Q. The capacitor has a capacitance C=4.9 µF. Determine the time constant t, in units of microseconds, for charging the capacitor. What is the charge Q on the capacitor in units of microcoulomb?arrow_forwardIn the figure ɛ1 = 6.88 V, ɛ2 = 12.7 V, R1 = 96.3 Q, R2 = 180 Q, and R3 = 318 Q. One point of the circuit is grounded (V = 0). What are the (a) size and (b) direction (up or down) of the current through resistance 1, the (c) size and (d) direction (left or right) of the current through resistance 2, and the (e) size and (f) direction of the current through resistance 3? (g) What is the electric potential at point A? R2arrow_forwardA circuit with a resistance R = 88 Ω is connected to a battery with potential difference across the terminals of ΔV = 6.5 V. a. Input an expression for the current passing through the circuit, I. (b) What is the current in milliamps, mA? (c) If the resistance of the circuit was increased by a factor of ten, Rnew = 10R, what is the new current in milliamps, mA?arrow_forward
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