Chapter 3.3, Problem 20SCP

a.

Explanation of Solution

Result of “str1.length()”:

• The function “length()”is used to return the number of characters in the given string.
• The variable “str1” is assigned the string value “Q.E...

b.

Explanation of Solution

Result of “str2.length()”:

• The function “length()”is used to return the number of characters in the given string.
• The variable “str2” is assigned the string value “Arcturan Megadonkey”...

c.

Explanation of Solution

Result of “str1.toUpperCase()”:

• The function “toUpperCase()”is used to return the string with all uppercase letters...

d.

Explanation of Solution

Result of “str2.toUpperCase()”:

• The function “toUpperCase()”is used to return the string with all uppercase letters...

e.

Explanation of Solution

Result of “str1.substring(2,4)”:

• The function “substring()”is used to return the substring for the specified index range.
• The variable “str1” is assigned the string value “Q.E.D.”.
• The starting index of the string is “0”...

f.

Explanation of Solution

Result of “str2.substring(10,14)”:

• The function “substring()”is used to return the substring for the specified index range.
• The variable “str2” is assigned the string value “Arcturan Megadonkey”.
• The starting index of the string is “0”...

g.

Explanation of Solution

Result of “str1.indexOf(“D”)”:

• The function “indexOf()”is used to return the index of the first occurrences of the given character “D”.
• The variable “str1” is assigned the string value “Q.E.D.”.
• The starting index of the string is “0”...

h.

Explanation of Solution

Result of “str1.indexOf(“.”)”:

• The function “indexOf()”is used to return the index of the first occurrences of the given character “.”.
• The variable “str1” is assigned the string value “Q.E.D.”.
• The starting index of the string is “0”...

i.

Explanation of Solution

Result of “str2.indexOf(“donkey”)”:

• The function “indexOf()”is used to return the index of the first occurrences of the given strinf “donkey”.
• The variable “str2” is assigned the string value “Arcturan Megadonkey”.
• The starting index of the string is “0”...

j.

Explanation of Solution

Result of “str3.indexOf(“X”)”:

• The function “indexOf()”is used to return the index of the first occurrences of the given character “X”.
• The variable “str3” is assigned the string value “Sirius Cybernetics Corporation”.
• The starting index of the string is “0”...

k.

Explanation of Solution

Result of “str2 + str3 . charAt(17)”:

• The function “charAt()”is used to return the character at the given index.
• The variable “str2” is assigned the string value “Arcturan Megadonkey”.
• The variable “str3” is assigned the string value “Sirius Cybernetics Corporation”...

l.

Explanation of Solution

Result of “str3.substring(9,str3.index0f("e"))”:

• The function “indexOf()” is used to return the index of the first occurrences of the given character.
• The variable “str3” is assigned the string value “Sirius Cybernetics Corporation”.
• The function “indexOf(“e”)” returns the index of first occurrence of the character “e”. Hence the index is “10”...

m.

Explanation of Solution

Result of “str3.substring(7,12)”:

• The function “substring()” is used to return the substring for the specified index range.
• The variable “str3” is assigned the string value “Sirius Cybernetics Corporation”.
• The starting index of the string is “0”...

n.

Explanation of Solution

Result of “str2.toLowerCase().substring(9,13) + str3. substring(18,str3.length() - 7)”:

• The function “substring()” is used to return the substring for the specified index range.
• The function “toLowerCase()” is used to return the string with all lowercase letters.
• The function “length()”is used to return the number of characters in the given string.
• The variable “str3” is assigned the string value “Sirius Cybernetics Corporation”.
• The variable “str2” is assigned the string value “Arcturan Megadonkey”.
• The starting index of the string is “0”.
• The expression “str2.toLowerCase()” returns the string “arcturan megadonkey”.
• The given expression “str2...