Bundle: Physics for Scientists and Engineers with Modern Physics, Loose-leaf Version, 9th + WebAssign Printed Access Card, Multi-Term
9th Edition
ISBN: 9781305932302
Author: Raymond A. Serway, John W. Jewett
Publisher: Cengage Learning
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Chapter 33, Problem 6CQ
(a)
To determine
The rate at which the person is doing work on the cleaner.
(b)
To determine
The analogy between the power in the given situation and in an electric circuit.
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Number T16.941
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Chapter 33 Solutions
Bundle: Physics for Scientists and Engineers with Modern Physics, Loose-leaf Version, 9th + WebAssign Printed Access Card, Multi-Term
Ch. 33.2 - Consider the voltage phasor in Figure 32.4, shown...Ch. 33.3 - Consider the AC circuit in Figure 32.8. The...Ch. 33.4 - Consider the AC circuit in Figure 32.11. The...Ch. 33.4 - Consider the AC circuit in Figure 32.12. The...Ch. 33.5 - Label each part of Figure 32.16, (a), (b), and...Ch. 33.6 - Prob. 33.6QQCh. 33.7 - Prob. 33.7QQCh. 33 - Prob. 1OQCh. 33 - Prob. 2OQCh. 33 - Prob. 3OQ
Ch. 33 - Prob. 4OQCh. 33 - Prob. 5OQCh. 33 - Prob. 6OQCh. 33 - Prob. 7OQCh. 33 - A resistor, a capacitor, and an inductor are...Ch. 33 - Under what conditions is the impedance of a series...Ch. 33 - Prob. 10OQCh. 33 - Prob. 11OQCh. 33 - Prob. 12OQCh. 33 - Prob. 13OQCh. 33 - Prob. 1CQCh. 33 - Prob. 2CQCh. 33 - Prob. 3CQCh. 33 - Prob. 4CQCh. 33 - Prob. 5CQCh. 33 - Prob. 6CQCh. 33 - Prob. 7CQCh. 33 - Prob. 8CQCh. 33 - Prob. 9CQCh. 33 - Prob. 10CQCh. 33 - Prob. 1PCh. 33 - (a) What is the resistance of a lightbulb that...Ch. 33 - Prob. 3PCh. 33 - Prob. 4PCh. 33 - Prob. 5PCh. 33 - Prob. 6PCh. 33 - Prob. 7PCh. 33 - Prob. 8PCh. 33 - Prob. 9PCh. 33 - Prob. 10PCh. 33 - Prob. 11PCh. 33 - Prob. 12PCh. 33 - An AC source has an output rms voltage of 78.0 V...Ch. 33 - Prob. 14PCh. 33 - Prob. 15PCh. 33 - Prob. 16PCh. 33 - Prob. 17PCh. 33 - An AC source with an output rms voltage of 86.0 V...Ch. 33 - Prob. 19PCh. 33 - Prob. 20PCh. 33 - Prob. 21PCh. 33 - Prob. 22PCh. 33 - What is the maximum current in a 2.20-F capacitor...Ch. 33 - Prob. 24PCh. 33 - In addition to phasor diagrams showing voltages...Ch. 33 - Prob. 26PCh. 33 - Prob. 27PCh. 33 - Prob. 28PCh. 33 - Prob. 29PCh. 33 - Prob. 30PCh. 33 - Prob. 31PCh. 33 - A 60.0-ft resistor is connected in series with a...Ch. 33 - Prob. 33PCh. 33 - Prob. 34PCh. 33 - A series RLC circuit has a resistance of 45.0 and...Ch. 33 - Prob. 36PCh. 33 - Prob. 37PCh. 33 - An AC voltage of the form v = 90.0 sin 350t, where...Ch. 33 - Prob. 39PCh. 33 - Prob. 40PCh. 33 - Prob. 41PCh. 33 - A series RLC circuit has components with the...Ch. 33 - Prob. 43PCh. 33 - Prob. 44PCh. 33 - A 10.0- resistor, 10.0-mH inductor, and 100-F...Ch. 33 - Prob. 46PCh. 33 - Prob. 47PCh. 33 - Prob. 48PCh. 33 - The primary coil of a transformer has N1 = 350...Ch. 33 - A transmission line that has a resistance per unit...Ch. 33 - Prob. 51PCh. 33 - Prob. 52PCh. 33 - Prob. 53PCh. 33 - Consider the RC highpass filter circuit shown in...Ch. 33 - Prob. 55PCh. 33 - Prob. 56PCh. 33 - Prob. 57APCh. 33 - Prob. 58APCh. 33 - Prob. 59APCh. 33 - Prob. 60APCh. 33 - Prob. 61APCh. 33 - Prob. 62APCh. 33 - Prob. 63APCh. 33 - Prob. 64APCh. 33 - Prob. 65APCh. 33 - Prob. 66APCh. 33 - Prob. 67APCh. 33 - Prob. 68APCh. 33 - Prob. 69APCh. 33 - (a) Sketch a graph of the phase angle for an RLC...Ch. 33 - Prob. 71APCh. 33 - Prob. 72APCh. 33 - A series RLC circuit contains the following...Ch. 33 - Prob. 74APCh. 33 - Prob. 75APCh. 33 - A series RLC circuit in which R = l.00 , L = 1.00...Ch. 33 - Prob. 77CPCh. 33 - Prob. 78CPCh. 33 - Prob. 79CPCh. 33 - Figure P33.80a shows a parallel RLC circuit. The...Ch. 33 - Prob. 81CP
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- Why do we need to be careful about work done on the system versus work done by the system in calculations?arrow_forwardA particle moves in the xy plane (Fig. P9.30) from the origin to a point having coordinates x = 7.00 m and y = 4.00 m under the influence of a force given by F=3y2+x. a. What is the work done on the particle by the force F if it moves along path 1 (shown in red)? b. What is the work done on the particle by the force F if it moves along path 2 (shown in blue)? c. What is the work done on the particle by the force F if it moves along path 3 (shown in green)? d. Is the force F conservative or nonconservative? Explain. FIGURE P9.30 In each case, the work is found using the integral of Fdr along the path (Equation 9.21). W=rtrfFdr=rtrf(Fxdx+Fydy+Fzdz) (a) The work done along path 1, we first need to integrate along dr=dxi from (0,0) to (7,0) and then along dr=dyj from (7,0) to (7,4): W1=x=0;y=0x=7;y=0(3y2i+xj)(dxi)+x=7;y=0x=7;y=4(3y2i+xj)(dyj) Performing the dot products, we get W1=x=0;y=0x=7;y=03y2dx+x=7;y=0x=7;y=4xdy Along the first part of this path, y = 0 therefore the first integral equals zero. For the second integral, x is constant and can be pulled out of the integral, and we can evaluate dy. W1=0+x=7;y=0x=7;y=4xdy=xy|x=7;y=0x=7;y=4=28J (b) The work done along path 2 is along dr=dyj from (0,0) to (0,4) and then along dr=dxi from (0,4) to (7,4): W2=x=0;y=0x=0;y=4(3y2i+xj)(dyj)+x=0;y=4x=7;y=4(3y2i+xj)(dyi) Performing the dot product, we get: W2=x=0;y=0x=0;y=4xdy+x=0;y=4x=7;y=43y2dx Along the first part of this path, x = 0. Therefore, the first integral equals zero. For the second integral, y is constant and can be pulled out of the integral, and we can evaluate dx. W2=0+3y2x|x=0;y=4x=7;y=4=336J (c) To find the work along the third path, we first write the expression for the work integral. W=rtrfFdr=rtrf(Fxdx+Fydy+Fzdz)W=rtrf(3y2dx+xdy)(1) At first glance, this appears quite simple, but we cant integrate xdy=xy like we might have above because the value of x changes as we vary y (i.e., x is a function of y.) [In parts (a) and (b), on a straight horizontal or vertical line, only x or y changes]. One approach is to parameterize both x and y as a function of another variable, say t, and write each integral in terms of only x or y. Constraining dr to be along the desired line, we can relate dx and dy: tan=dydxdy=tandxanddx=dytan(2) Now, use equation (2) in (1) to express each integral in terms of only one variable. W=x=0;y=0x=7;y=43y2dx+x=0;y=0x=7;y=4xdyW=y=0y=43y2dytan+x=0x=7xtandx We can determine the tangent of the angle, which is constant (the angle is the angle of the line with respect to the horizontal). tan=4.007.00=0.570 Insert the value of the tangent and solve the integrals. W=30.570y33|y=0y=4+0.570x22|x=0x=7W=112+14=126J (d) Since the work done is not path-independent, this is non-conservative force. Figure P9.30ANSarrow_forwardRank the potential energies of the four systems of particles shown in Figure OQ20.6 from largest to smallest. Include equalities if appropriate. Figure OQ20.6arrow_forward
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