BIG IDEAS MATH Algebra 2: Common Core Student Edition 2015

15th Edition

ISBN: 9781608408405

Author: HOUGHTON MIFFLIN HARCOURT

Publisher: Cengage Learning

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Equations and Inequations

Equations and inequalities describe the relationship between two mathematical expressions.

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A linear function can just be a constant, or it can be the constant multiplied with the variable like x or y. If the variables are of the form, x2, x1/2 or y2 it is not linear. The exponent over the variables should always be 1.

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Question

Chapter 3.4, Problem 66E

To determine

To calculate: The year in which the tablet computer sales reached 65 million.

Expert Solution

Answer to Problem 66E

The required for the arrow to hit a target that is 3 feet above the ground is 0.35 seconds.

Explanation of Solution

Given information:

The function: A=4.5t2+43.5t+17

Formula used:

Quadratic formula:

x=−b±b2−4ac2a

Calculation:

The given function is A=4.5t2+43.5t+17

Substitute 65 for A in the above equation.

65=4.5t2+43.5t+174.5t2+43.5t+17−65=04.5t2+43.5t−48=0

To solve the above equation, use the quadratic formula x=−b±b2−4ac2a and solve for t .

t=−43.5±(43.5)2−4(4.5)(−48)2(4.5)=−43.5±2756.259=−43.5±52.59

The year after 2010 is positive.

So, t=−43.5+52.59=99=1

Hence, the tablet computer sales reached 65 million in 1 year.

To determine

To calculate: The average rate of change from 2010 to 2012 and interpret the meaning in the context of the situation.

Expert Solution

Answer to Problem 66E

The model will no longer be accurate.

Explanation of Solution

Given information:

The function: A=4.5t2+43.5t+17

Calculation:

The given function is A=4.5t2+43.5t+17

For the year 2010; substitute 0 for t in the above equation.

A2010=4.5(0)2+43.5(0)+17=0+0+17=17

For the year 2012; substitute 2 for t in the above equation.

A2012=4.5(2)2+43.5(2)+17=4.5(4)+43.5(2)+17=18+87+17=122

To find the average rate of change, use the formula A2012−A20102012−2010 .

Substitute 122 for A2012 and 17 for A2010 in the above equation and simplify.

A2012−A20102012−2010=122−172012−2010=1052=52.5

Hence, the required average rate of change is 52.5 million dollars.

To determine

To determine: Whether the model will be accurate after a new, innovative computer is developed.

Expert Solution

Answer to Problem 66E

The model will no longer be accurate.

Explanation of Solution

Given information:

The function: A=4.5t2+43.5t+17

Calculation:

The given function is A=4.5t2+43.5t+17

If a new innovative computer is developed, people could change their preference from tablet computers to the new innovative computer which may cause the decrease of the sales of ntablet computers.

Hence, the model will no longer be accurate.

Chapter 3.4, Problem 65E

Chapter 3.4, Problem 67E

Chapter 3 Solutions

BIG IDEAS MATH Algebra 2: Common Core Student Edition 2015

Ch. 3.1 - Prob. 1E Ch. 3.1 - Prob. 2E Ch. 3.1 - Prob. 3E Ch. 3.1 - Prob. 4E Ch. 3.1 - Prob. 5E Ch. 3.1 - Prob. 6E Ch. 3.1 - Prob. 7E Ch. 3.1 - Prob. 8E Ch. 3.1 - Prob. 9E Ch. 3.1 - Prob. 10E

Ch. 3.1 - Prob. 11E Ch. 3.1 - Prob. 12E Ch. 3.1 - Prob. 13E Ch. 3.1 - Prob. 14E Ch. 3.1 - Prob. 15E Ch. 3.1 - Prob. 16E Ch. 3.1 - Prob. 17E Ch. 3.1 - Prob. 18E Ch. 3.1 - Prob. 19E Ch. 3.1 - Prob. 20E Ch. 3.1 - Prob. 21E Ch. 3.1 - Prob. 22E Ch. 3.1 - Prob. 23E Ch. 3.1 - Prob. 24E Ch. 3.1 - Prob. 25E Ch. 3.1 - Prob. 26E Ch. 3.1 - Prob. 27E Ch. 3.1 - Prob. 28E Ch. 3.1 - Prob. 29E Ch. 3.1 - Prob. 30E Ch. 3.1 - Prob. 31E Ch. 3.1 - Prob. 32E Ch. 3.1 - Prob. 33E Ch. 3.1 - Prob. 34E Ch. 3.1 - Prob. 35E Ch. 3.1 - Prob. 36E Ch. 3.1 - Prob. 37E Ch. 3.1 - Prob. 38E Ch. 3.1 - Prob. 39E Ch. 3.1 - Prob. 40E Ch. 3.1 - Prob. 41E Ch. 3.1 - Prob. 42E Ch. 3.1 - Prob. 43E Ch. 3.1 - Prob. 44E Ch. 3.1 - Prob. 45E Ch. 3.1 - Prob. 46E Ch. 3.1 - Prob. 47E Ch. 3.1 - Prob. 48E Ch. 3.1 - Prob. 49E Ch. 3.1 - Prob. 50E Ch. 3.1 - Prob. 51E Ch. 3.1 - Prob. 52E Ch. 3.1 - Prob. 53E Ch. 3.1 - Prob. 54E Ch. 3.1 - Prob. 55E Ch. 3.1 - Prob. 56E Ch. 3.1 - Prob. 57E Ch. 3.1 - Prob. 58E Ch. 3.1 - Prob. 59E Ch. 3.1 - Prob. 60E Ch. 3.1 - 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Prob. 16E Ch. 3.5 - Prob. 17E Ch. 3.5 - Prob. 18E Ch. 3.5 - Prob. 19E Ch. 3.5 - Prob. 20E Ch. 3.5 - Prob. 21E Ch. 3.5 - Prob. 22E Ch. 3.5 - Prob. 23E Ch. 3.5 - Prob. 24E Ch. 3.5 - Prob. 25E Ch. 3.5 - Prob. 26E Ch. 3.5 - Prob. 27E Ch. 3.5 - Prob. 28E Ch. 3.5 - Prob. 29E Ch. 3.5 - Prob. 30E Ch. 3.5 - Prob. 31E Ch. 3.5 - Prob. 32E Ch. 3.5 - Prob. 33E Ch. 3.5 - Prob. 34E Ch. 3.5 - Prob. 35E Ch. 3.5 - Prob. 36E Ch. 3.5 - Prob. 37E Ch. 3.5 - Prob. 38E Ch. 3.5 - Prob. 39E Ch. 3.5 - Prob. 40E Ch. 3.5 - Prob. 41E Ch. 3.5 - Prob. 42E Ch. 3.5 - Prob. 43E Ch. 3.5 - Prob. 44E Ch. 3.5 - Prob. 45E Ch. 3.5 - Prob. 46E Ch. 3.5 - Prob. 47E Ch. 3.5 - Prob. 48E Ch. 3.5 - Prob. 49E Ch. 3.5 - Prob. 50E Ch. 3.5 - Prob. 51E Ch. 3.5 - Prob. 52E Ch. 3.5 - Prob. 53E Ch. 3.5 - Prob. 54E Ch. 3.5 - Prob. 55E Ch. 3.5 - Prob. 56E Ch. 3.5 - Prob. 57E Ch. 3.5 - Prob. 58E Ch. 3.5 - Prob. 59E Ch. 3.5 - Prob. 60E Ch. 3.5 - Prob. 61E Ch. 3.5 - Prob. 62E Ch. 3.5 - Prob. 63E Ch. 3.5 - Prob. 64E Ch. 3.5 - Prob. 65E Ch. 3.5 - 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