For Exercises 29–36, use the point-slope formula to write an equation of the line given the following information. (See Examples 3–4.) The line passes through the point ( 4 , 0 ) and is parallel to the line 3 x + 2 y = 8 .
For Exercises 29–36, use the point-slope formula to write an equation of the line given the following information. (See Examples 3–4.) The line passes through the point ( 4 , 0 ) and is parallel to the line 3 x + 2 y = 8 .
Solution Summary: The author calculates the equation of the line passing through (4,0) and parallel to line 3x+2y=8 using point-slope formula.
For Exercises 29–36, use the point-slope formula to write an equation of the line given the following information.(See Examples 3–4.)
The line passes through the point
(
4
,
0
)
and is parallel to the line
3
x
+
2
y
=
8
.
Formula Formula Point-slope equation: The point-slope equation of a line passing through the point (x 1 , y 1 ) with slope m , is given by the following formula: y - y 1 = m x - x 1 Example: The point-slope equation of a line passing through (2, -6) with slope 5 is given by: y - (-6) = 5(x - 2) y + 6 = 5(x - 2)
Exercises 83–86: The table lists data that are exactly linear.
a. Find the slope-intercept form of the line that passes through these
data points.
b. Predict y when x = -2.7 and 6.3. Decide if these calculations
involve interpolation or extrapolation.
-3
-2
-1
1
83.
y
-7.7
-6.2
-4.7
-3.2
-1.7
In Exercises 5–20, find the equation of each of the lines with the given
properties. Sketch the graph of each line.
For Exercises 25–36, determine the slope of the line passing through the given points. (See Example 2)
25. (4, –7) and (2, – 1)
26. (-3, –8) and (4, 6)
27. (17, 9) and (42, –6)
28. (-9, 4) and (-1, –6)
29. (30, –52) and (-22, –39)
30. (- 100, -16) and (84, 30)
31. (2.6, 4.1) аnd (9.5, —3.7)
32. (8.5, 6.2) аnd (-5.1, 7.9)
33.
6) and
35. (3 V6, 2V5) and (V6, V5)
36. (2VIT, –3V3) and (VTI, -5V3)
34.
-3,
and
4,
10
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Linear Equation | Solving Linear Equations | What is Linear Equation in one variable ?; Author: Najam Academy;https://www.youtube.com/watch?v=tHm3X_Ta_iE;License: Standard YouTube License, CC-BY