(a)
To find: The value of c.
(a)
Answer to Problem 37AYU
0.112 and 81.92
Explanation of Solution
Given: A projectile fired from the point
Where,
A howitzer fires an artillery round with a muzzle velocity of 897 m/s
If the round must clear a hill 200 meters height at a distance of 2000 meters in front of the howitzer.
The equation of trajectory,
Put
Hence, the value of c are 0.112 and 81.92
(b)
To find:Themaximum distance round will travel.
(b)
Answer to Problem 37AYU
18.15 km
Explanation of Solution
Given: A projectile fired from the point
Where,
A howitzer fires an artillery round with a muzzle velocity of 897 m/s
If the goal in part (a) is to hit a target on the ground 75 km away.
In part (a) got two value of c
For
The horizontal distance on ground is 2002.5 m
So, Target will not hit for this value of c.
For
The horizontal distance on ground is 18145 meters or 18.15 km.
So, Target will not hit for this value of c.
Because the maximum distance travelled by round id 18.15 km.
Chapter 3 Solutions
Precalculus
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