Algebra and Trigonometry: Structure and Method, Book 2
Algebra and Trigonometry: Structure and Method, Book 2
2000th Edition
ISBN: 9780395977255
Author: MCDOUGAL LITTEL
Publisher: McDougal Littell
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Chapter 3.9, Problem 9P

(a)

To determine

To find: The linear function Co .

(a)

Expert Solution
Check Mark

Answer to Problem 9P

Therefore, the equation of linear function Co(Fo)=59Fo1609 .

Explanation of Solution

Given information: The function Co at Fo=32 and Co at Fo=212 ,

  Co (32Fo)=0 and Co (212Fo)=100

Formula used: For calculation of equation of linear function,

  f(x)=mx+bwhere m is slope and b is yintercept.

Calculation: To calculate the equation of function using function Co (32Fo)=0 and Co (212Fo)=100 ,

  Putting value of Co(32Fo)in genral form,f(x)=mx+bNow, at Fo=32FoCo(32Fo)=m×32+b0=32m+bb=32mPutting value of Co(212Fo)in genral form,f(x)=mx+bNow, at Fo=212FoCo(212Fo)=m×212+b100=212m+bPutting value of b100=212m32mm=59Now,b=32mb=1609Co(Fo)=59Fo1609

Therefore, the equation of linear function Co(Fo)=59Fo1609 .

(b)

To determine

To calculate: The temperature Co corresponds to Fo .

(b)

Expert Solution
Check Mark

Answer to Problem 9P

Therefore, the temperature is Co(98.6Fo)=37Co .

Explanation of Solution

Given information: The function Co at Fo=32 and Co at Fo=212 ,

  Co (32Fo)=0 and Co (212Fo)=100

Formula used: For calculation of equation of linear function,

  f(x)=mx+bwhere m is slope and b is yintercept.

Calculation: To calculate the equation of function using function Co (32Fo)=0 and Co (212Fo)=100 ,

  Putting value of Co(32Fo)in genral form,f(x)=mx+bNow, at Fo=32FoCo(32Fo)=m×32+b0=32m+bb=32mPutting value of Co(212Fo)in genral form,f(x)=mx+bNow, at Fo=212FoCo(212Fo)=m×212+b100=212m+bPutting value of b100=212m32mm=59Now,b=32mb=1609Co(Fo)=59Fo1609

  Putting Fo=98.6Fo in equationCo(Fo)=59Fo1609Co(98.6Fo)=59×(98.6Fo)1609Co(98.6Fo)=37

Therefore, the temperatureis Co(98.6Fo)=37Co .

(c)

To determine

To calculate:The temperature at which both scales give same reading.

(c)

Expert Solution
Check Mark

Answer to Problem 9P

Therefore, the temperature at -40 Co both the scales have same reading.

Explanation of Solution

Given information: The function Co at Fo=32 and Co at Fo=212 ,

  Co (32Fo)=0 and Co (212Fo)=100

Formula used: For calculation of equation of linear function,

  f(x)=mx+bwhere m is slope and b is yintercept.

Calculation: To calculate the equation of function using function Co (32Fo)=0 and Co (212Fo)=100 ,

  Putting value of Co(32Fo)in genral form,f(x)=mx+bNow, at Fo=32FoCo(32Fo)=m×32+b0=32m+bb=32mPutting value of Co(212Fo)in genral form,f(x)=mx+bNow, at Fo=212FoCo(212Fo)=m×212+b100=212m+bPutting value of b100=212m32mm=59Now,b=32mb=1609Co(Fo)=59Fo1609

  Putting Fo=Co in equationCo(Fo)=59Fo1609Co=59×(Co)160959CoCo=1609Co=40Co

Therefore, the temperature at -40 Co both the scales have same reading.

Chapter 3 Solutions

Algebra and Trigonometry: Structure and Method, Book 2

Ch. 3.1 - Prob. 11OECh. 3.1 - Prob. 1WECh. 3.1 - Prob. 2WECh. 3.1 - Prob. 3WECh. 3.1 - Prob. 4WECh. 3.1 - Prob. 5WECh. 3.1 - Prob. 6WECh. 3.1 - Prob. 7WECh. 3.1 - Prob. 8WECh. 3.1 - Prob. 9WECh. 3.1 - Prob. 10WECh. 3.1 - Prob. 11WECh. 3.1 - Prob. 12WECh. 3.1 - Prob. 13WECh. 3.1 - Prob. 14WECh. 3.1 - Prob. 15WECh. 3.1 - Prob. 16WECh. 3.1 - Prob. 17WECh. 3.1 - Prob. 18WECh. 3.1 - Prob. 19WECh. 3.1 - Prob. 20WECh. 3.1 - Prob. 21WECh. 3.1 - Prob. 22WECh. 3.1 - Prob. 23WECh. 3.1 - Prob. 24WECh. 3.1 - Prob. 25WECh. 3.1 - Prob. 26WECh. 3.1 - Prob. 27WECh. 3.1 - Prob. 28WECh. 3.1 - Prob. 29WECh. 3.1 - Prob. 30WECh. 3.1 - Prob. 31WECh. 3.1 - Prob. 32WECh. 3.1 - Prob. 33WECh. 3.1 - Prob. 34WECh. 3.1 - Prob. 35WECh. 3.1 - Prob. 36WECh. 3.1 - Prob. 37WECh. 3.1 - Prob. 38WECh. 3.1 - Prob. 39WECh. 3.1 - Prob. 40WECh. 3.1 - Prob. 1PCh. 3.1 - Prob. 2PCh. 3.1 - Prob. 3PCh. 3.1 - Prob. 4PCh. 3.1 - Prob. 5PCh. 3.1 - Prob. 6PCh. 3.1 - Prob. 7PCh. 3.1 - Prob. 8PCh. 3.1 - Prob. 9PCh. 3.1 - Prob. 10PCh. 3.1 - 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Prob. 2OECh. 3.9 - Prob. 3OECh. 3.9 - Prob. 4OECh. 3.9 - Prob. 5OECh. 3.9 - Prob. 6OECh. 3.9 - Prob. 7OECh. 3.9 - Prob. 8OECh. 3.9 - Prob. 1WECh. 3.9 - Prob. 2WECh. 3.9 - Prob. 3WECh. 3.9 - Prob. 4WECh. 3.9 - Prob. 5WECh. 3.9 - Prob. 6WECh. 3.9 - Prob. 7WECh. 3.9 - Prob. 8WECh. 3.9 - Prob. 9WECh. 3.9 - Prob. 10WECh. 3.9 - Prob. 11WECh. 3.9 - Prob. 12WECh. 3.9 - Prob. 13WECh. 3.9 - Prob. 14WECh. 3.9 - Prob. 15WECh. 3.9 - Prob. 16WECh. 3.9 - Prob. 17WECh. 3.9 - Prob. 18WECh. 3.9 - Prob. 19WECh. 3.9 - Prob. 20WECh. 3.9 - Prob. 21WECh. 3.9 - Prob. 22WECh. 3.9 - Prob. 23WECh. 3.9 - Prob. 24WECh. 3.9 - Prob. 25WECh. 3.9 - Prob. 26WECh. 3.9 - Prob. 27WECh. 3.9 - Prob. 28WECh. 3.9 - Prob. 29WECh. 3.9 - Prob. 30WECh. 3.9 - Prob. 31WECh. 3.9 - Prob. 32WECh. 3.9 - Prob. 33WECh. 3.9 - Prob. 1PCh. 3.9 - Prob. 2PCh. 3.9 - Prob. 3PCh. 3.9 - Prob. 4PCh. 3.9 - Prob. 5PCh. 3.9 - Prob. 6PCh. 3.9 - Prob. 7PCh. 3.9 - Prob. 8PCh. 3.9 - Prob. 9PCh. 3.9 - Prob. 10PCh. 3.9 - Prob. 11PCh. 3.9 - Prob. 1MRECh. 3.9 - Prob. 2MRECh. 3.9 - Prob. 3MRECh. 3.9 - Prob. 4MRECh. 3.9 - Prob. 5MRECh. 3.9 - Prob. 6MRECh. 3.9 - Prob. 7MRECh. 3.9 - Prob. 8MRECh. 3.9 - Prob. 9MRECh. 3.9 - Prob. 10MRECh. 3.9 - Prob. 11MRECh. 3.9 - Prob. 12MRECh. 3.9 - Prob. 13MRECh. 3.10 - Prob. 1OECh. 3.10 - Prob. 2OECh. 3.10 - Prob. 3OECh. 3.10 - Prob. 4OECh. 3.10 - Prob. 5OECh. 3.10 - Prob. 6OECh. 3.10 - Prob. 7OECh. 3.10 - Prob. 8OECh. 3.10 - Prob. 9OECh. 3.10 - Prob. 10OECh. 3.10 - Prob. 11OECh. 3.10 - Prob. 12OECh. 3.10 - Prob. 13OECh. 3.10 - Prob. 14OECh. 3.10 - Prob. 15OECh. 3.10 - Prob. 16OECh. 3.10 - Prob. 17OECh. 3.10 - Prob. 18OECh. 3.10 - Prob. 19OECh. 3.10 - Prob. 20OECh. 3.10 - Prob. 21OECh. 3.10 - Prob. 22OECh. 3.10 - Prob. 23OECh. 3.10 - Prob. 24OECh. 3.10 - Prob. 1WECh. 3.10 - Prob. 2WECh. 3.10 - Prob. 3WECh. 3.10 - Prob. 4WECh. 3.10 - Prob. 5WECh. 3.10 - Prob. 6WECh. 3.10 - Prob. 7WECh. 3.10 - Prob. 8WECh. 3.10 - Prob. 9WECh. 3.10 - Prob. 10WECh. 3.10 - Prob. 11WECh. 3.10 - Prob. 12WECh. 3.10 - Prob. 13WECh. 3.10 - Prob. 14WECh. 3.10 - Prob. 15WECh. 3.10 - Prob. 16WECh. 3.10 - Prob. 17WECh. 3.10 - Prob. 18WECh. 3.10 - Prob. 19WECh. 3.10 - Prob. 20WECh. 3.10 - Prob. 21WECh. 3.10 - Prob. 22WECh. 3.10 - Prob. 23WECh. 3.10 - Prob. 24WECh. 3.10 - Prob. 25WECh. 3.10 - Prob. 26WECh. 3.10 - Prob. 27WECh. 3.10 - Prob. 28WECh. 3.10 - Prob. 29WECh. 3.10 - Prob. 30WECh. 3.10 - Prob. 31WECh. 3.10 - Prob. 32WECh. 3.10 - Prob. 33WECh. 3.10 - Prob. 34WECh. 3.10 - Prob. 35WECh. 3.10 - Prob. 36WECh. 3.10 - Prob. 37WECh. 3.10 - Prob. 1STCh. 3.10 - Prob. 2STCh. 3.10 - Prob. 3STCh. 3.10 - Prob. 4STCh. 3.10 - Prob. 5STCh. 3.10 - Prob. 6STCh. 3.10 - Prob. 7STCh. 3.10 - Prob. 8STCh. 3.10 - Prob. 9STCh. 3.10 - Prob. 1ECh. 3.10 - Prob. 2ECh. 3.10 - Prob. 3ECh. 3.10 - Prob. 4ECh. 3.10 - Prob. 5ECh. 3 - Prob. 1CRCh. 3 - Prob. 2CRCh. 3 - Prob. 3CRCh. 3 - Prob. 4CRCh. 3 - Prob. 5CRCh. 3 - Prob. 6CRCh. 3 - Prob. 7CRCh. 3 - Prob. 8CRCh. 3 - Prob. 9CRCh. 3 - Prob. 10CRCh. 3 - Prob. 11CRCh. 3 - Prob. 12CRCh. 3 - Prob. 13CRCh. 3 - Prob. 14CRCh. 3 - Prob. 15CRCh. 3 - Prob. 16CRCh. 3 - Prob. 17CRCh. 3 - Prob. 18CRCh. 3 - Prob. 1CTCh. 3 - Prob. 2CTCh. 3 - Prob. 3CTCh. 3 - Prob. 4CTCh. 3 - Prob. 5CTCh. 3 - Prob. 6CTCh. 3 - Prob. 7CTCh. 3 - Prob. 8CTCh. 3 - Prob. 9CTCh. 3 - Prob. 10CTCh. 3 - Prob. 11CTCh. 3 - Prob. 12CTCh. 3 - Prob. 13CTCh. 3 - Prob. 14CTCh. 3 - Prob. 15CTCh. 3 - Prob. 16CTCh. 3 - Prob. 1CLRCh. 3 - Prob. 2CLRCh. 3 - Prob. 3CLRCh. 3 - Prob. 4CLRCh. 3 - Prob. 5CLRCh. 3 - Prob. 6CLRCh. 3 - Prob. 7CLRCh. 3 - Prob. 8CLRCh. 3 - Prob. 9CLRCh. 3 - Prob. 10CLRCh. 3 - Prob. 11CLRCh. 3 - Prob. 12CLRCh. 3 - Prob. 13CLRCh. 3 - Prob. 14CLRCh. 3 - Prob. 15CLRCh. 3 - Prob. 16CLRCh. 3 - Prob. 17CLRCh. 3 - Prob. 18CLRCh. 3 - Prob. 19CLRCh. 3 - Prob. 20CLRCh. 3 - Prob. 21CLRCh. 3 - Prob. 22CLRCh. 3 - Prob. 23CLRCh. 3 - Prob. 24CLRCh. 3 - Prob. 25CLRCh. 3 - Prob. 26CLRCh. 3 - Prob. 27CLRCh. 3 - Prob. 28CLR
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