COLLEGE PHYSICS-CONNECT ACCESS
COLLEGE PHYSICS-CONNECT ACCESS
5th Edition
ISBN: 9781260486834
Author: GIAMBATTISTA
Publisher: MCG
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Question
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Chapter 4, Problem 102P

(a)

To determine

Net force on the rocket during the first 1.5s after the lift off.

(a)

Expert Solution
Check Mark

Answer to Problem 102P

Net force is 1.5N_ in upward direction.

Explanation of Solution

Write the equation to find the net force on rocket.

    Fnet=ma        (I)

Here Fnet is the net force, m is the mass of the rocket and a is the acceleration.

Conclusion

Substitute 87g for m and 17.5m/s2 for a in (I)

    Fnet=87g(103kg1g)(17.5m/s2)=1.5N

Net force is 1.5N_ in upward direction.

(b)

To determine

The force exerted by the burning fuel on the rocket.

(b)

Expert Solution
Check Mark

Answer to Problem 102P

The force is 2.4N_ in upward direction.

Explanation of Solution

Write the equation to find the force exerted by the burning fuel on the rocket.

    Ffuel=Fnet+mg        (II)

Here Ffuel is the force exerted by the burning fuel and g is the acceleration due to gravity.

Conclusion

Substitute 1.5N for Fnet, 87g for m and 9.8m/s2 for g.

    Ffuel=1.5N+(87g(103kg1g)(9.8m/s2))=2.4N

The force is 2.4N_ in upward direction.

(c)

To determine

Distance travelled by the rocket.

(c)

Expert Solution
Check Mark

Answer to Problem 102P

Distance travelled is 55m_.

Explanation of Solution

Write the equation to calculate the distance travelled by rocket during the burning time.

    x1=ut+12at2        (III)

Here x1 is the distance travelled, u is the initial velocity, a is the acceleration and t is the time.

Write the equation for the upward speed.

    v=at        (IV)

Write the equation for time taken to reduce the velocity from v to zero in the free fall.

    tfree=vg        (V)

Write the equation to calculate the distance travelled by the rocket during the free fall period.

    x2=12(v1+v)tfree        (VI)

Here v1 the final speed of motion in free fall.

Write the equation for total distance travelled by the rocket.

    x=x1+x2        (VII)

Conclusion

Substitute 0m/s for u, 1.5s for t, 17.5m/s2 for a in (III)

    x1=(0m/s)(1.5s)+12(17.5m/s2)(1.5s)2=19.7m

Substitute 1.5s for t, 17.5m/s2 for a in (IV)

    v=17.5m/s21.5s=26.25m/s

Substitute 26.25m/s for v and 9.8m/s2 for g in (V)

    tfree=26.25m/s9.8m/s2=2.68s

Substitute 0m/s for v1, 26.25m/s for v and 2.68s for tfree in (VI)

    x2=12(0m/s+26.25m/s)2.68s=35.2m

Substitute 19.7m for x1 and 35.2m for x2

    x=19.7m+35.2m=55m

Distance travelled is 55m_.

(d)

To determine

Time taken by the rocket to return to the ground after lift-off.

(d)

Expert Solution
Check Mark

Answer to Problem 102P

Time taken is 3.35m_.

Explanation of Solution

Write the equation for time taken by the by the rocket to return to the ground to fall from rest from a height x.

    tele=2xg        (VIII)

Here the time taken by the rocket to fall from rest from height x is tele.

Write the equation to find the time taken by the rocket to return to the ground after lift-off.

    ttotal=t+tfree+tele        (IX)

Here ttotal the total time taken by the rocket to return to the ground after lift-off.

Conclusion

Substitute 55m for x and 9.8m/s2 for g in (VIII)

    tele=2(55m)9.8m/s2=3.35s

Substitute 3.35s for tele, 2.68s for tfree and 1.5s for t in (IX)

    ttotal=1.5s+2.68s+3.35s=7.5s

(e)

To determine

Plot the velocity-time relation of rocket for the entire level from the launch to the return back to the ground.

(e)

Expert Solution
Check Mark

Answer to Problem 102P

The graph has been plotted.

Explanation of Solution

The velocity time relation of rocket for the entire travel from the launch to return back to the ground is shown in figure 1.

COLLEGE PHYSICS-CONNECT ACCESS, Chapter 4, Problem 102P

Conclusion

The graph has been plotted.

(f)

To determine

Net force on rocket after the complete usage of fuel.

(f)

Expert Solution
Check Mark

Answer to Problem 102P

The net force is 0.85N_.

Explanation of Solution

Write the expression for the weight of the rocket.

    Fnet=mg        (X)

Conclusion

Substitute 87g for m and 9.8m/s2 for g in (X)

    Fnet=(87g(103kg1g))(9.8m/s2)=0.85N

The net force is 0.85N_.

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Chapter 4 Solutions

COLLEGE PHYSICS-CONNECT ACCESS

Ch. 4.4 - Prob. 4.8PPCh. 4.5 - Prob. 4.5ACPCh. 4.5 - Prob. 4.10PPCh. 4.5 - Prob. 4.5BCPCh. 4.6 - Prob. 4.11PPCh. 4.6 - Prob. 4.6CPCh. 4 - Prob. 1CQCh. 4 - Prob. 2CQCh. 4 - Prob. 3CQCh. 4 - Prob. 4CQCh. 4 - Prob. 5CQCh. 4 - Prob. 6CQCh. 4 - Prob. 7CQCh. 4 - Prob. 8CQCh. 4 - Prob. 9CQCh. 4 - Prob. 10CQCh. 4 - Prob. 11CQCh. 4 - Prob. 12CQCh. 4 - Prob. 13CQCh. 4 - Prob. 14CQCh. 4 - Prob. 15CQCh. 4 - Prob. 16CQCh. 4 - Prob. 17CQCh. 4 - Prob. 18CQCh. 4 - Prob. 19CQCh. 4 - Prob. 1MCQCh. 4 - Prob. 2MCQCh. 4 - Prob. 3MCQCh. 4 - Prob. 4MCQCh. 4 - Prob. 5MCQCh. 4 - Prob. 6MCQCh. 4 - Prob. 7MCQCh. 4 - Prob. 8MCQCh. 4 - Prob. 9MCQCh. 4 - Prob. 10MCQCh. 4 - Prob. 11MCQCh. 4 - Prob. 12MCQCh. 4 - Prob. 13MCQCh. 4 - Prob. 14MCQCh. 4 - Prob. 15MCQCh. 4 - Prob. 16MCQCh. 4 - Prob. 17MCQCh. 4 - Prob. 18MCQCh. 4 - Prob. 19MCQCh. 4 - Prob. 20MCQCh. 4 - Prob. 21MCQCh. 4 - Prob. 1PCh. 4 - Prob. 4PCh. 4 - Prob. 5PCh. 4 - Prob. 6PCh. 4 - Prob. 7PCh. 4 - Prob. 8PCh. 4 - Prob. 9PCh. 4 - Prob. 10PCh. 4 - Prob. 11PCh. 4 - Prob. 12PCh. 4 - Prob. 14PCh. 4 - Prob. 15PCh. 4 - Prob. 16PCh. 4 - Prob. 17PCh. 4 - Prob. 18PCh. 4 - Prob. 19PCh. 4 - Prob. 20PCh. 4 - Prob. 21PCh. 4 - Prob. 22PCh. 4 - Prob. 23PCh. 4 - Prob. 24PCh. 4 - Prob. 25PCh. 4 - Prob. 26PCh. 4 - Prob. 27PCh. 4 - Prob. 28PCh. 4 - Prob. 29PCh. 4 - Prob. 30PCh. 4 - Prob. 31PCh. 4 - Prob. 32PCh. 4 - Prob. 33PCh. 4 - Prob. 34PCh. 4 - Prob. 35PCh. 4 - Prob. 36PCh. 4 - Prob. 37PCh. 4 - Prob. 38PCh. 4 - Prob. 39PCh. 4 - Prob. 40PCh. 4 - Prob. 41PCh. 4 - Prob. 42PCh. 4 - Prob. 43PCh. 4 - Prob. 44PCh. 4 - Prob. 45PCh. 4 - Prob. 46PCh. 4 - Prob. 47PCh. 4 - Prob. 49PCh. 4 - Prob. 50PCh. 4 - Prob. 51PCh. 4 - Prob. 52PCh. 4 - Prob. 53PCh. 4 - Prob. 54PCh. 4 - Prob. 55PCh. 4 - Prob. 56PCh. 4 - Prob. 57PCh. 4 - Prob. 58PCh. 4 - Prob. 59PCh. 4 - Prob. 60PCh. 4 - Prob. 61PCh. 4 - Prob. 62PCh. 4 - Prob. 63PCh. 4 - Prob. 64PCh. 4 - Prob. 65PCh. 4 - Prob. 67PCh. 4 - Prob. 68PCh. 4 - Prob. 69PCh. 4 - Prob. 70PCh. 4 - Prob. 71PCh. 4 - Prob. 72PCh. 4 - Prob. 73PCh. 4 - Prob. 74PCh. 4 - Prob. 75PCh. 4 - Prob. 76PCh. 4 - Prob. 77PCh. 4 - Prob. 78PCh. 4 - Prob. 79PCh. 4 - Prob. 80PCh. 4 - Prob. 81PCh. 4 - Prob. 82PCh. 4 - Prob. 83PCh. 4 - Prob. 84PCh. 4 - Prob. 85PCh. 4 - Prob. 86PCh. 4 - Prob. 87PCh. 4 - Prob. 88PCh. 4 - Prob. 90PCh. 4 - Prob. 91PCh. 4 - Prob. 92PCh. 4 - Prob. 93PCh. 4 - Prob. 94PCh. 4 - Prob. 95PCh. 4 - Prob. 97PCh. 4 - Prob. 98PCh. 4 - Prob. 99PCh. 4 - Prob. 100PCh. 4 - Prob. 101PCh. 4 - Prob. 102PCh. 4 - Prob. 103PCh. 4 - Prob. 104PCh. 4 - Prob. 105P
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