21ST CENTURY ASTRONOMY >CUSTOM<
6th Edition
ISBN: 9781324027836
Author: Kay
Publisher: NORTON
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Chapter 4, Problem 10QP
To determine
The change in the gravitational force between Earth and Moon, if the Moon is
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Currently, the moon goes around the earth once every 27.3 days. If the moon could be brought into a new circular orbit with a smaller radius, its orbital period would beA. More than 27.3 days.B. 27.3 days.C. Less than 27.3 days.
Quèstion 19
The weight of 2 kilograms of iron on Earth's surface is
OA. the same on the moon.
B. greater on the moon.
C. less on the moon.
D. zero.
E. None of them
The rotation of the planets around the sun is governed by:
A. The gravitational field of the sun.
B. The gravity of the stars.
C. The heat energy of the sun.
D. The gravity of the other planets of the solar system.
Kelper's second law relates between them:
O A. The time period of rotation of the orbiting planet around the sun and the average distance of the planet to the
sun.
OB. The time period of rotation of the orbiting planet around the sun and the average distance of the planet to the
earth.
C. The time period of rotation of the orbiting planet around the sun and the average distance of the planet to the
moon.
OD. The time period of rotation of the orbiting planet around the earth and the average distance of the planet to
the sun.
Chapter 4 Solutions
21ST CENTURY ASTRONOMY >CUSTOM<
Ch. 4.1 - Prob. 4.1ACYUCh. 4.1 - Prob. 4.1BCYUCh. 4.2 - Prob. 4.2CYUCh. 4.3 - Prob. 4.3CYUCh. 4.4 - Prob. 4.4CYUCh. 4 - Prob. 1QPCh. 4 - Prob. 2QPCh. 4 - Prob. 3QPCh. 4 - Prob. 4QPCh. 4 - Prob. 5QP
Ch. 4 - Prob. 6QPCh. 4 - Prob. 7QPCh. 4 - Prob. 8QPCh. 4 - Prob. 9QPCh. 4 - Prob. 10QPCh. 4 - Prob. 11QPCh. 4 - Prob. 12QPCh. 4 - Prob. 13QPCh. 4 - Prob. 14QPCh. 4 - Prob. 15QPCh. 4 - Prob. 16QPCh. 4 - Prob. 17QPCh. 4 - Prob. 18QPCh. 4 - Prob. 19QPCh. 4 - Prob. 20QPCh. 4 - Prob. 21QPCh. 4 - Prob. 22QPCh. 4 - Prob. 23QPCh. 4 - Prob. 24QPCh. 4 - Prob. 25QPCh. 4 - Prob. 26QPCh. 4 - Prob. 27QPCh. 4 - Prob. 28QPCh. 4 - Prob. 29QPCh. 4 - Prob. 30QPCh. 4 - Prob. 31QPCh. 4 - Prob. 32QPCh. 4 - Prob. 33QPCh. 4 - Prob. 34QPCh. 4 - Prob. 35QPCh. 4 - Prob. 36QPCh. 4 - Prob. 37QPCh. 4 - Prob. 38QPCh. 4 - Prob. 39QPCh. 4 - Prob. 40QPCh. 4 - Prob. 41QPCh. 4 - Prob. 42QPCh. 4 - Prob. 43QPCh. 4 - Prob. 44QPCh. 4 - Prob. 45QP
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- (a) One of the moons of Jupiter, named Io, has an orbital radius of 4.22 108 m and a period of 1.77 days. Assuming the orbit is circular, calculate the mass of Jupiter, (b) The largest moon of Jupiter, named Ganymede, has an orbital radius of 1.07 109 m and a period of 7.16 days. Calculate the mass of Jupiter from this data, (c) Are your results to parts (a) and (b) consistent? Explain.arrow_forwardThe orbit of a planet around the sun is : O A. hyperbolic. O B. parabolic. OC. elliptic. OD. circular.arrow_forwardWhich of the following is a measurable effect of the tidal interactions between the Earth and the moon? choose 1 of the following: a. The moon is constantly getting closer to the Earth, and will one day collide with our planet. b. The rotation rate of the Earth is gradually slowing down. c. The rotation rate of the moon is gradually speeding up. d. The moon pulls more strongly on the far side of the Earth than it does on the near side.arrow_forward
- 8. The mean distance of Earth from the Sun is 149.6 x 10° km and the mean distance of Mercury from the Sun is 57.9 x 10° km. The period of Earth's revolutions is 1 year, what is the period of Mercury's revolution? a. 0.24 year on Earth b. 0.42 year on Earth C. 1.13 year on Earth d. 1.31 year on Earth 9. The planet Delta has 2 times the gravitational field strength and 3 times the radius of Earth. How does the mass of the planet Delta compare with the mass of Earth?arrow_forward6. A synchronous orbit is an orbit about a planet's equator that always remains above the same spot of the planet because the synchronous orbit matches the planet's rotational period. The pilot of the Mars spacecraft (which was named Cheetah 1 and had a 9556 kg mass) asked Tarzan to calculate the altitude of a synchronous orbit so they could remain over a particular geological feature on the Martian equator. Calculate the altitude above the Martian equator using the data above and Johannes Kepler's genius.arrow_forwardA satellite orbits the earth instead of flying off into space because a. gravity continuously pulls it towards the earth. b. solar reflectors continuously push it towards the earth. c. wind sails continuously push it towards the earth. d. rocket thrusters continuously push it towards the earth.arrow_forward
- According to Lunar Laser Ranging experiments the average distance LM from the Earth to the Moon is approximately 3.85 × 10° km. The Moon orbits the Earth and completes one revolution in approximately 27.5 days (a sidereal month). How can the mass of the Earth be calculated using the information above? Select the correct statements. Select one or more: O a. Use Newton's third law. O b. Use Newton's first law. c. Use Coulombs law. O d. Use Newton's second law.arrow_forward27. Less force is required to launch a spaceship from the surface of the Moon than to launch an identical ship from the surface of Earth becauseA. the Moon has a smaller surface area than Earth.B. the mass of an object on Earth is greater than on the Moon.C. the gravitational field of the Moon is less than that of Earth.D. the atmosphere of the Moon is much thinner than that of Earth.arrow_forward2. An unknown planet was accidentally discovered by NASA. It has a mean distance of 2.15 E11 meters from the sun. Assuming it has a mass of 6.02 E24 kg, how long (in Earth Years) will it take for the said planet to revolve around the sun?arrow_forward
- 3. The period of rotation of Mars is 1 day and 37 minutes. Determine its frequency of rotation in Hertz.arrow_forwardEach year, the radius of the moon’s orbit increases by about 3.8 cm. How does this change affect the length of a month?A. A month gets longer.B. A month gets shorter.C. The length of a month stays the same.arrow_forward3. The gravitational acceleration at Earth's surface (ga) is about 10 m/s? and ge = GM/R2. What is g, at the surface of a planet with 2X Earth's mass and 3X Earth's radius?arrow_forward
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