The final concentration of the calcium nitrate solution is to be calculated, which is formed by mixing a volume of 46.2 m L of a 0.568 M C a ( N O 3 ) 2 with 80.5 m L of a 1.396 M C a ( N O 3 ) 2 solution. Concept introduction: The concentration of a solution in terms of molarity of the solution is calculated by dividing the total number of moles of solute present in the given solution by the volume of the solution. The number of moles of solute present in a one-liter solution is equal to its molarity. The conversion of volume from mL to liter is done as: 1 mL = 10 − 3 L The number of moles of solute in the given solution is calculated as: Molarity of solute (M) = moles of solute (n) volume of solution (V) n = MV
The final concentration of the calcium nitrate solution is to be calculated, which is formed by mixing a volume of 46.2 m L of a 0.568 M C a ( N O 3 ) 2 with 80.5 m L of a 1.396 M C a ( N O 3 ) 2 solution. Concept introduction: The concentration of a solution in terms of molarity of the solution is calculated by dividing the total number of moles of solute present in the given solution by the volume of the solution. The number of moles of solute present in a one-liter solution is equal to its molarity. The conversion of volume from mL to liter is done as: 1 mL = 10 − 3 L The number of moles of solute in the given solution is calculated as: Molarity of solute (M) = moles of solute (n) volume of solution (V) n = MV
Solution Summary: The author explains how the final concentration of the calcium nitrate solution is calculated by dividing the total number of moles of solute present in a one-liter solution by its volume.
The final concentration of the calcium nitrate solution is to be calculated, which is formed by mixing a volume of 46.2mL of a 0.568MCa(NO3)2 with 80.5mL of a 1.396MCa(NO3)2 solution.
Concept introduction:
The concentration of a solution in terms of molarity of the solution is calculated by dividing the total number of moles of solute present in the given solution by the volume of the solution.
The number of moles of solute present in a one-liter solution is equal to its molarity.
The conversion of volume from mL to liter is done as: 1mL=10−3L
The number of moles of solute in the given solution is calculated as:
Molarity of solute (M)=moles of solute (n)volume of solution (V)n=MV
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Author:Steven D. Gammon, Ebbing, Darrell Ebbing, Steven D., Darrell; Gammon, Darrell Ebbing; Steven D. Gammon, Darrell D.; Gammon, Ebbing; Steven D. Gammon; Darrell
Author:Steven D. Gammon, Ebbing, Darrell Ebbing, Steven D., Darrell; Gammon, Darrell Ebbing; Steven D. Gammon, Darrell D.; Gammon, Ebbing; Steven D. Gammon; Darrell