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A boy stands on a diving board and tosses a stone into a swimming pool. The stone is thrown from a height of 2.50 m above the water surface with a velocity of 4.00 m/s at an angle of 60.0° above the horizontal. As the stone strikes the water surface, it immediately slows down to exactly half the speed it had when it struck the water and maintains that speed while in the water. After the stone enters the water, it moves in a straight line in the direction of the velocity it had when it struck the water. If the pool is 3.00 m deep, how much tune elapses between when the stone is thrown and when it strikes the bottom of the pool?
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Chapter 4 Solutions
Bundle: Physics for Scientists and Engineers, Volume 2, Loose-leaf Version, 10th + WebAssign Printed Access Card for Serway/Jewett's Physics for Scientists and Engineers, 10th, Multi-Term
- If the vector components of the position of a particle moving in the xy plane as a function of time are x = (2.8 m/s2)t2 and y = (6.4 m/s3)t3, at what time t is the angle between the particle's velocity and the x axis equal to 45°?arrow_forwardA football is placed at rest on the field with initial coordinates x0 = 0 and y0 = 0. The ball is then kicked and thereby given an initial velocity of magnitude v0 = 23.6 m/s and direction θ0 = 36.3o above the horizontal. Ignore the effects of air resistance. Initial horizontal component of the velocity v0x = Initial vertical component of the velocity v0y = Horizontal component of the acceleration ax = Vertical component of the acceleration ay = Enter the equation for the horizontal position versus time, x(t) = Enter the equation for the vertical position versus time, y(t) = Enter the equation for the horizontal velocity versus time, vx(t) = Enter the equation for the vertical velocity versus time, vy(t) = Enter the equation for the total velocity versus time, v(t) = Enter the equation for the angle of the velocity vector versus time, θ(t)= Enter the maximum height of the football Enter the range of the football Enter the time it takes for the football to reach its maximum…arrow_forwardA projectile is projected from the origin with a velocity of 25.0 m/s at an angle of 50.0 degrees above the horizontal. What is the time of maximum height of the projectile? Multiple Choice 3.45 s 2.03 s 3.01 s 1.95 s 2.67 sarrow_forward
- A regulation volleyball court measures L = 18.0 meters in length and d = 2.43 meters in height. A volleyball player hits the ball from a height of h = 1.50 m just over the backline, and the initial velocity of the ball creates an angle of q = 30° with the ground. At what initial speed must the ball be struck such that it barely clears the net?arrow_forwardA machine launches a tennis ball at an angle of 25° above the horizontal at a speed of 14 meters per second and returns to level ground. Which combination of changes can produce an increase in the time of flight for the second launch? a. decrease the launch angle and decrease the ball's initial speed b. decrease the launch angle and increase the ball's initial speed c. increase the launch angle and decrease the ball's initial speed d. increase the launch angle and increase the ball's initial speedarrow_forwardAn object is thrown horizontally with an initial velocity of 10 m/s from the roof of a building 60 m tall. How far from the base of the building does it hit the ground? A. 15 m B. 25 m C. 35 m D. 60 marrow_forward
- A projectile, thrown horizontally, travels 100 m to hit back the ground. If its maximum height is S0 m then what is the initial velocity of the projectile? 3.19m/s 31.3m/s 10.2m/sarrow_forwardA brick is thrown upward from the top of a building at an angle of 15° to the horizontal and with an initial speed of 13 m/s. If the brick is in flight for 3.4 s, how tall is the building? =_____ m The best leaper in the animal kingdom is the puma, which can jump to a height of 13.1 ft when leaving the ground at an angle of 40°. With what speed, in SI units, must the animal leave the ground to reach that height? = ______ m/sarrow_forward"Which is an accurate statement for general projectile motion, when the projectile is at the highest point of its trajectory?" Its acceleration is zero. Its velocity is perpendicular to the acceleration. Its velocity and acceleration are both zero. The horizontal component of its velocity is zero.arrow_forward
- For general projectile motion, which of the following best describes the horizontal component of a projectile's velocity? Assume air resistance is negligible. 1) The horizontal component of a projectile's velocity continually decreases. 2) The horizontal component of a projectile's velocity continually increases. 3) The horizontal component of a projectile's velocity remains a nonzero constant. 4) The horizontal component of a projectile's velocity initially decreases and then increases. 5) The horizontal component of a projectile's velocity is zero.arrow_forwardA projectile is launched on the Earth with a certain initial velocity and moves without air resistance. Another projectile is launched with the same initial velocity on the Moon, where the acceleration due to gravity is one-sixth as large. How does the range of the projectile on the Moon compare with that of the projectile on the Earth? (a) It is one-sixth as large. (b) It is the same. (c) It is 6 times larger. (d) It is 6 times larger. (e) It is 36 times larger.arrow_forwardAs a projectile moves in its path, is there any point along the path where the velocity and acceleration vectors are parallel to each other? ( assume the object is thrown upward and forward, but not straight up.)arrow_forward
- Principles of Physics: A Calculus-Based TextPhysicsISBN:9781133104261Author:Raymond A. Serway, John W. JewettPublisher:Cengage Learning