21st Century Astronomy
6th Edition
ISBN: 9780393428063
Author: Kay
Publisher: NORTON
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Chapter 4, Problem 33QP
To determine
The mass of the Sun.
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Chapter 4 Solutions
21st Century Astronomy
Ch. 4.1 - Prob. 4.1ACYUCh. 4.1 - Prob. 4.1BCYUCh. 4.2 - Prob. 4.2CYUCh. 4.3 - Prob. 4.3CYUCh. 4.4 - Prob. 4.4CYUCh. 4 - Prob. 1QPCh. 4 - Prob. 2QPCh. 4 - Prob. 3QPCh. 4 - Prob. 4QPCh. 4 - Prob. 5QP
Ch. 4 - Prob. 6QPCh. 4 - Prob. 7QPCh. 4 - Prob. 8QPCh. 4 - Prob. 9QPCh. 4 - Prob. 10QPCh. 4 - Prob. 11QPCh. 4 - Prob. 12QPCh. 4 - Prob. 13QPCh. 4 - Prob. 14QPCh. 4 - Prob. 15QPCh. 4 - Prob. 16QPCh. 4 - Prob. 17QPCh. 4 - Prob. 18QPCh. 4 - Prob. 19QPCh. 4 - Prob. 20QPCh. 4 - Prob. 21QPCh. 4 - Prob. 22QPCh. 4 - Prob. 23QPCh. 4 - Prob. 24QPCh. 4 - Prob. 25QPCh. 4 - Prob. 26QPCh. 4 - Prob. 27QPCh. 4 - Prob. 28QPCh. 4 - Prob. 29QPCh. 4 - Prob. 30QPCh. 4 - Prob. 31QPCh. 4 - Prob. 32QPCh. 4 - Prob. 33QPCh. 4 - Prob. 34QPCh. 4 - Prob. 35QPCh. 4 - Prob. 36QPCh. 4 - Prob. 37QPCh. 4 - Prob. 38QPCh. 4 - Prob. 39QPCh. 4 - Prob. 40QPCh. 4 - Prob. 41QPCh. 4 - Prob. 42QPCh. 4 - Prob. 43QPCh. 4 - Prob. 44QPCh. 4 - Prob. 45QP
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- Calculate Venus's mass given the acceleration due to gravity (8.87 m/s2) and the radius of Venus (6052 km). (The 1st significant figure of the answer: 4.00*1024 kg)arrow_forwardA planet of mass m=8.15×1024 kg orbits a star of mass M=2.35×1029 kg in a circular path. The radius of the orbit is R=3.95×107 km. What is the orbital period Tplanet of the planet in Earth days?arrow_forwardthe mass of planet is 2.00 x 10 22 kg and the radius of the planet is 5.0 x 10 5 m what is the force of gravity on a 1.00 kg mass at the planets surface? What is the force of gravity on a 1.00 kg mass if it were 5.00 x 10 5 m above the planets surface?arrow_forward
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- In order to escape planet 1, you need an escape speed of 4.71×104 m/s. Planet 2 has the same radius as planet 1 but is twice as dense as planet 1. What is the escape speed to leave planet 2? 434 m/s 9.42×104 m/s 307 m/s 6.66×104 m/sarrow_forwardA newly discovered planet is in a circular orbit around a distant star with an orbital period of 325 Earth days. The planet also rotates on its axis, making one full rotation every 2.50 Earth days. The radius of the planet is rp = 8.00 ✕ 106 m and the radius of the planet's orbit about the star is rs = 4.50 ✕ 1011 m.Determine the ratio of the radial acceleration, due to the rotation of the planet, of an object at the equator of the planet (acp) to the radial acceleration of the planet in its orbit about the star (acs).arrow_forwardSaturn is approximately 10 times as far away from the sun as the earth. This means that its orbital acceleration is ________ that of the earth.A. 1/10B. 1/100C. 1/1000D. 1/10,000arrow_forward
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