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Why is the following situation impassible? A normally proportioned adult walks briskly along a straight line in the +x direction, standing straight up and holding his right arm vertical and next to his body so that the arm does not swing. His right hand holds a ball at his side a distance h above the floor. When the ball passes above a point marked as x = 0 on the horizontal floor, he opens his fingers to release the ball from rest relative to his hand. The ball strikes the ground for the first time at position x = 7.00h.
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Chapter 4 Solutions
Bundle: Physics for Scientists and Engineers with Modern Physics, Loose-leaf Version, 10th + WebAssign Printed Access Card for Serway/Jewett's Physics for Scientists and Engineers, 10th, Multi-Term
- The coordinates of a particle moving in the XY plane are given as function of time by: X = 3m + ( 4 m/s^4) t^4 Y = ( 5 m/s)t + (4 m/s^5)t^5. a. Find the position vector of the body at t = 4.5 sec. ( first answer is X, followed by Y) b. Find the instantaneous acceleration of the body at t = 3.5 sec c. Find the average velocity during the time interval from t 1 = 2 sec to t2 = 4.5 secarrow_forward1. The coordinates of a particle moving in the XY plane are given as function of time by: X = 5m + ( 7 m/s^4) t ^4 Y = ( 10 m/s)t + (3 m/s^5)t ^5 Find the position vector of the body at t = 3.5 sec. ( first answer is X, followed by Y) Your answerarrow_forwardThe velocity of a particle is V and is constant. It moves counterclockwise on a circle with center "O" and radius R. Draw the circle. When the particle is in the vector R position, draw vector R, vector V, vector A, and vector da/dt(time derivative of acceleration).arrow_forward
- A particle moves in the xy plane with constant acceleration. At time zero, the particle is at x = 7.0 m, y = 6.0 m, and has velocity v = 8.0 m/s î + -9.0 m/s j. The acceleration is given by the vector a = 5.0 m/s2 î + 0 m/s2 j. (a) Find the velocity vector at t = 6.0 s. m/s) î + ( m/s) ĵ (b) Find the position vector at t = 2.0 s. m) î + ( m) j (c) Give the magnitude and direction of the position vector in part (b). m • (counterclockwise from the +x-axis) еВookarrow_forwardProblem 5: While competing in the long jump, a person leaps over a smooth horizontal sand surface. She lands on the surface with speed vf = 8.5 m/s at an angle = 37° below horizontal. Assume that the person moves without air resistance. Use a Cartesian coordinate system with the origin at her final position. The positive x-axis is directed from her initial to her final position, and the positive y-axis is directed vertically upwards. Part (c) What x position, in meters, did the jumper begin her long jump? x0 = ||arrow_forwardThe velocity of a particle is V and is constant. It moves counterclockwise on a circle with center "O" and radius R. Derivative of acceleration with respect to time; Find as a function of Ɵ, R, V, and the unit vectors (x^ , y^) in the x and y directions. Hint: a = -V^2/R(cosƟx^+ sinƟy^) and dƟ/dt= V/Rarrow_forward
- The velocity of a particle moving in the x-y plane is given by (6.12i + 3.24j) m/s at time t = 3.65 s. Its average acceleration during the next 0.02 s is (4.0i + 6.0j) m/s². Determine the velocity v of the particle at t = 3.67 s and the angle between the average-acceleration vector and the velocity vector at t = 3.67 s. Answers: V = ( i 8= i it i j) m/sarrow_forwardThe cork from a champagne bottle slips through the hands of a waiter opening it, moving with an initial velocity v0 = 13.3m/s at an angle θ = 77.2° above horizontal. A diner is sitting a horizontal distance d away when this happens. Assume the cork leaves the waiter’s hands at the same vertical level as the diner and that the cork falls back to this vertical level when it reaches the diner. Use a Cartesian coordinate system with the origin at the cork's initial position. Calculate the time, td in seconds, for the cork to reach the diner. td = Reacting quickly to avoid being struck, the diner moves 2.00 m horizontally directly toward the waiter opening the champagne bottle. Determine the horizontal distance, d in meters, between the waiter and the diner at the time the cork reaches where the diner had previously been sitting. d =arrow_forwardThe cork from a champagne bottle slips through the hands of a waiter opening it, moving with an initial velocity v0 = 15.5 m/s at an angle θ = 75.8° above horizontal. A diner is sitting a horizontal distance d away when this happens. Assume the cork leaves the waiter’s hands at the same vertical level as the diner and that the cork falls back to this vertical level when it reaches the diner. Use a Cartesian coordinate system with the origin at the cork's initial position. a.) Calculate the time, td in seconds, for the cork to reach the diner. b.) Reacting quickly to avoid being struck, the diner moves 2.00 m horizontally directly toward the waiter opening the champagne bottle. Determine the horizontal distance, d in meters, between the waiter and the diner at the time the cork reaches where the diner had previously been sitting. Please explain how you got your answer in detailarrow_forward
- The cork from a champagne bottle slips through the hands of a waiter opening it, moving with an initial velocity v0 = 15.6 m/s at an angle θ = 77.4° above horizontal. A diner is sitting a horizontal distance d away when this happens. Assume the cork leaves the waiter’s hands at the same vertical level as the diner and that the cork falls back to this vertical level when it reaches the diner. Use a Cartesian coordinate system with the origin at the cork's initial position. Part (a) Calculate the time, td in seconds, for the cork to reach the diner. Part (b) Reacting quickly to avoid being struck, the diner moves 2.00 m horizontally directly toward the waiter opening the champagne bottle. Determine the horizontal distance, d in meters, between the waiter and the diner at the time the cork reaches where the diner had previously been sitting.arrow_forwardAn arrow is fired with an initial velocity v0 at an angle θ0 above horizontal. Assume the arrow moves without air resistance. Use a Cartesian coordinate system with the origin at the arrow's initial position to analyze the arrow's motion. Some time later the arrow makes an angle of θ = 15 degrees with respect to the horizontal. Write an expression for the time, t, that passes between when the arrow was fired and this later point. t = ?arrow_forwardA particle is performing uniform circular motion counterclockwise around the origin of an xy coordinate system. The period of the motion (time for one revolution) is 7 s. At some instant, its position vector is 7 = (2 m)î + (-3 m)§. At that instant, what is the velocity v of the particle in unit vector notation.arrow_forward
- College PhysicsPhysicsISBN:9781305952300Author:Raymond A. Serway, Chris VuillePublisher:Cengage LearningUniversity Physics (14th Edition)PhysicsISBN:9780133969290Author:Hugh D. Young, Roger A. FreedmanPublisher:PEARSONIntroduction To Quantum MechanicsPhysicsISBN:9781107189638Author:Griffiths, David J., Schroeter, Darrell F.Publisher:Cambridge University Press
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