Thermodynamics, Statistical Thermodynamics, & Kinetics
3rd Edition
ISBN: 9780321824004
Author: ENGEL, Thomas/ Reid
Publisher: Pearson College Div
expand_more
expand_more
format_list_bulleted
Question
Chapter 4, Problem 4.13NP
Interpretation Introduction
Interpretation:
The standard enthalpy
Concept Introduction:
The standard enthalpy change for a reaction
For a given
Here, ?n = change in the number of moles
R = gas constant; T = temperature
Expert Solution & Answer
Want to see the full answer?
Check out a sample textbook solutionStudents have asked these similar questions
For the complete combustion of 1.000 mole of propane gas at 298 K and 1 atm pressure, ∆H° = -2220 kJ/mol. What will be the heat released when 4.13 g of propane is combusted under these conditions? The chemical formula for propane is C3H8.
Cl(g) ΔH°f, = +121.3 kJ mol–1
Cl–(aq) ΔH°f, = –167.2 kJ mol–1
HCl(g) ΔH°f, = –92.3 kJ mol–1
HCl(aq) ΔH°f, = –167.2 kJ mol–1
Cl2(g) ΔH°f, = 0 kJ mol–1
H2O(l) ΔH°f, = –286 kJ mol–1
ClO2(g) ΔH°f, = +102.5 kJ mol–1
Cl2O(g) ΔH°f, = +80.3 kJ mol–1
O(g) ΔH°f, =+249.0 kJ mol–1
H(g) ΔH°f, =+218.2 kJ mol–1
Which material is most 'stable' at 298 K?
Question 1 options:
Cl2(g)
Cl–(aq)
Cl(g)
Calculate ΔG° for the reaction of benzene with hydrogen gas to give cyclohexane using the following data: ?6?6 + 3H2 → ?6?12
ΔG∘f (benzene) = 124.5 kJ/mol ΔG∘f (cyclohexane) = 217.3 kJ/mol. Is the reaction spontaneous as written?
Chapter 4 Solutions
Thermodynamics, Statistical Thermodynamics, & Kinetics
Ch. 4 - In calculating HR at 285.15 K, only the Hf of the...Ch. 4 - What is the point of having an outer water bath in...Ch. 4 - Is the following statement correct? If not rewrite...Ch. 4 - Does the enthalpy of formation of H2Ol change if...Ch. 4 - Why are elements included in the sum in Equation...Ch. 4 - Why are heat capacities of reactants and products...Ch. 4 - Prob. 4.7CPCh. 4 - Prob. 4.8CPCh. 4 - Prob. 4.9CPCh. 4 - Prob. 4.10CP
Ch. 4 - Prob. 4.11CPCh. 4 - Prob. 4.12CPCh. 4 - You wish to measure the heat of solution of NaCl...Ch. 4 - Prob. 4.14CPCh. 4 - Prob. 4.15CPCh. 4 - Prob. 4.16CPCh. 4 - Prob. 4.17CPCh. 4 - Dogs cool off in hot weather by panting. Write a...Ch. 4 - Prob. 4.19CPCh. 4 - Prob. 4.20CPCh. 4 - Given the data in Table 4.1 (Appendix, Data...Ch. 4 - Prob. 4.2NPCh. 4 - A sample of K(s) of mass 2.740 g undergoes...Ch. 4 - Calculate Hf for NO(g) at 975 K, assuming that the...Ch. 4 - Prob. 4.5NPCh. 4 - Derive a formula for HRT for the reaction...Ch. 4 - Prob. 4.7NPCh. 4 - Prob. 4.8NPCh. 4 - Calculate the standard enthalpy of formation of...Ch. 4 - The following data are a DSC scan of a solution of...Ch. 4 - Prob. 4.11NPCh. 4 - Prob. 4.12NPCh. 4 - Prob. 4.13NPCh. 4 - Prob. 4.14NPCh. 4 - Prob. 4.15NPCh. 4 - The total surface area of Asia consisting of...Ch. 4 - Prob. 4.17NPCh. 4 - A sample of Na2SO4s is dissolved in 225 g of water...Ch. 4 - Nitrogen is a vital component of proteins and...Ch. 4 - Prob. 4.20NPCh. 4 - Prob. 4.21NPCh. 4 - A 0.1429 g sample of sucrose C12H22O11 is burned...Ch. 4 - Prob. 4.23NPCh. 4 - Prob. 4.24NPCh. 4 - Prob. 4.25NPCh. 4 - Given the following heat capacity data at 298 K,...Ch. 4 - Calculate H for the process in which Cl2g...Ch. 4 - From the following data at 298.15 K C, calculate...Ch. 4 - Prob. 4.29NPCh. 4 - Use the average bond energies in Table 4.3 I to...Ch. 4 - Prob. 4.31NPCh. 4 - Prob. 4.32NPCh. 4 - Prob. 4.33NPCh. 4 - Prob. 4.34NPCh. 4 - Prob. 4.35NP
Knowledge Booster
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, chemistry and related others by exploring similar questions and additional content below.Similar questions
- Given the heat of formation of the following compounds: CO2(g) ΔfH° = -393.5 kJ/mol H2O(l) ΔfH° = -285.9 kJ/mol CH3OH(l) ΔfH° = -238.6 kJ/mol What is the value of ΔrH° for the reaction: CH3OH(l) + 3/2 O2(g) → CO2(g) + 2 H2O(l)arrow_forwardYou are given the following data: H2 (g) → 2H (g) ΔH° = 436.4 kJ/molBr2 (g) → 2Br (g) ΔH° = 192.5 kJ/molH2 (g) + Br2 (g) → 2HBr (g) ΔH° = -72.4 kJ/mol Calculate the ΔH° for the reaction: H (g) + Br (g) → HBr (g)arrow_forwardexplain the combustion of methane gasCOMBUSTION OF METHANE GAS:CH4 + 2O2 → CO2 + 2H2O + Energyarrow_forward
- Given the following data: Br2(l) + 5F2(g) → 2BrF5(l) ΔH°=-918.0 kJ BrF3(l) + Br2(l) → 3BrF(g) ΔH°=125.2 kJ 2NaBr(s) + F2(g) → 2NaF(s) + Br2(l) ΔH°=-316.0 kJ NaBr(s) + F2(g) → NaF(s) + BrF(g) ΔH°=-216.6 kJ calculate ΔH° for the reaction:BrF3(l) + F2(g) → BrF5(l)arrow_forward9C (s) + 12H2 (g) + 3/2 O2 (g) → 3C3H7 OH (1) The enthalpy change is -954 kJ and entropy increases. Using Le Chatelier's Principle, check all of the following disturbances that would allow you to obtain more propanol. increase temperature decrease temperature increase pressure decrease pressure increase hydrogen concentration remove product add carbon increase oxygen concentrationarrow_forwardExplain the differences between the energy content of one gram of fat, one gram of carbohydrate as well as one gram of protein obtained by complete combustion in calorimeter and by completely broken down in human body.arrow_forward
- In the system: C(s) + O2(g) + 2HCI(g) – COCI2(g) + H20(g) + heat how is it possible to increase the amount of heat evolved? add some carbon add a catalyst remove some of the HCI add COCI2 Add some O2arrow_forwardAcetylene burns in air according to the following equation:C₂H₂(g)+5/2O₂(g)→2CO₂(g)+H₂O(g) ΔH°ᵣₓₙ =-125.8kJ Given ΔH°f of CO₂(g) 393.5 kJ/mol and ΔH°f of H₂O(g) =241.8 kJ/mol, find ΔH°f of C₂H₂(g)arrow_forwardGiven the following data: 2 C6H6(l) + 15 O2(g) → 12 CO2(g) + 6 H2O(l) ΔG0= -6399 kJ C(s) + O2(g) → CO2(g) ΔG0= -394 kJ H2(g) + ½O2(g) → H2O(l) ΔG0= -237 kJ Calculate the ΔG0rxn for the reaction 6 C(s) + 3 H2(g) → C6H6(l)arrow_forward
- You are given the following data: H2(g) → 2H(g) AH° = 436.4 kJ/mol Br2(g) > 2Br(g) AH° = 192.5 kJ/mol H2(g) + Br2(g)→ 2HB1(g) AH°: =-72.4 kJ/mol Calculate AH for the reaction H(g) + Br(g) → HBr(g) kJ/molarrow_forwardA reaction occurs where ethane, C2H6 is prepared by the reaction of C with H2. Given the following data: C (gr) + 02 (g) → CO2 (g) AH° = -393.5 kJ Please note that C (gr) means carbon in the form of graphite. H2 (g) + 1/2 02 (g) → H20 (1) AH° = -285.8 kJ 2 C2H6 (g) + 7 O2 (g) → 4 CO2 (g) + 6 H2O (1) AH° = -3119.6 kJ Determine AH for the reaction: 2 C (s) + 3 H2 (g) → C2H6 (g) 308.9 kJ -478.1 kJ 1475.2 kJ -84.6 kJ 201.2 kJarrow_forwardConsider the following generic reaction: A+2B→C+3D, with ΔHΔH = 178 kJ . Determine the value of ΔH for each of the following related reactions. 3A+6B→3C+9D C+3D→A+2B 1/2C+3/2D→1/2A+Barrow_forward
arrow_back_ios
SEE MORE QUESTIONS
arrow_forward_ios
Recommended textbooks for you
- Chemistry & Chemical ReactivityChemistryISBN:9781337399074Author:John C. Kotz, Paul M. Treichel, John Townsend, David TreichelPublisher:Cengage LearningChemistry for Engineering StudentsChemistryISBN:9781337398909Author:Lawrence S. Brown, Tom HolmePublisher:Cengage Learning
Chemistry & Chemical Reactivity
Chemistry
ISBN:9781337399074
Author:John C. Kotz, Paul M. Treichel, John Townsend, David Treichel
Publisher:Cengage Learning
Chemistry for Engineering Students
Chemistry
ISBN:9781337398909
Author:Lawrence S. Brown, Tom Holme
Publisher:Cengage Learning
The Laws of Thermodynamics, Entropy, and Gibbs Free Energy; Author: Professor Dave Explains;https://www.youtube.com/watch?v=8N1BxHgsoOw;License: Standard YouTube License, CC-BY