EBK THERMODYNAMICS, STATISTICAL THERMOD
EBK THERMODYNAMICS, STATISTICAL THERMOD
3rd Edition
ISBN: 9780100799431
Author: Reid
Publisher: YUZU
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Chapter 4, Problem 4.1CP

In calculating Δ H R ° at 285.15 K, only the Δ H f ° of the compounds that take part in the reactions listed in Tables 4.1 and 4.2 (Appendix A, Data Tables) are needed. Is this statement also true if you want to calculate Δ H R ° at 500. K?

Expert Solution & Answer
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Interpretation Introduction

Interpretation: Whether the given statement is true for the calculation of standard enthalpy change of the reaction at 500 K or not needs to be determined.

Concept Introduction:

Enthalpy change of a reaction is the amount of heat absorbed or evolved during the reaction which takes place at constant pressure conditions The standard enthalpy change for a reaction ΔHR0 is given in terms of the difference in the standard enthalpy of formation of the products and that of reactants.

i.e. ΔHR0 = npΔHf0(products) - nrΔHf0(reactants)  ------(1)

Here,np and nr are the number of moles of the products and reactants

Answer to Problem 4.1CP

The given statement is not true, since heat capacities of the substances involved in the reaction needs to be included at T = 500K

Explanation of Solution

Based on Kirchhoff's law the change in enthalpy (ΔH) of a reaction is directly proportional to the change in temperature (ΔT) i.e.

  ΔH α ΔTΔH = CpΔT

Where Cp is the heat capacity at constant pressure.

Equation (1) holds true only if the reaction takes place at 298K. At any other temperature, the heat capacities of the products and reactants need to be included. As a result, the net equation becomes:

  ΔHf0(500 K) = ΔHf0(298 K) + 298500ΔCpdT ------(2)

  ΔCp=Cp(products)Cp(reactants) 

Where ΔCp is the difference in the heat capacities of the products and reactants

Conclusion

In order to calculate the enthalpy change of the reaction at 500 K (or any temperature other than 298 K), heat capacities of the substances involved in the reaction needs to be included.

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Chapter 4 Solutions

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