Chapter 4, Problem 4.75E

Interpretation Introduction

(a)

Interpretation:

The formula for the compound by using M containing appropriate charges, which represents the metal ion, is to be stated.

Concept introduction:

The smallest particle which represents an ionic compound is known as formula unit. While writing the chemical formula of a compound, the net charge present over the formula unit should be zero. The zero net charge is obtained by equalizing the total positive charge on cations with the total negative charge on the anions.

Answer to Problem 4.75E

The formula for the compound by using M containing appropriate charges, which represents the metal ion, is ${\text{M}}_{\text{3}}{\left({\text{PO}}_4\right)}_2$.

Explanation of Solution

While writing the formula of the covalent molecule, the name of the atom having less electronegativity is given first. Then, the most electronegative atom is added with a suffix –ide.

It is given that metal, M, is taken from the group IIA(2) and combined this metal with ${\text{PO}}_4^{3-}$. The metal that belongs to the group IIA(2) must have $+2$ charge over it. So, the charge on M is ${\text{M}}^{+}$. The given charge on phosphate ion is $-3$. To balance the charges, this formula of the compound contains three M ions as cation each with $+2$ charge and two phosphate ions as anion each with $-3$ charge.

Therefore, the formula that can be given to the compound is ${\text{M}}_{\text{3}}{\left({\text{PO}}_4\right)}_2$.

Conclusion

The formula for the compound is ${\text{M}}_{\text{3}}{\left({\text{PO}}_4\right)}_2$.

Interpretation Introduction

(b)

Interpretation:

The formula for the compound by using M containing appropriate charges, which represents the metal ion, is to be stated.

Concept introduction:

The smallest particle which represents an ionic compound is known as formula unit. While writing the chemical formula of a compound, the net charge present over the formula unit should be zero. The zero net charge is obtained by equalizing the total positive charge on cations with the total negative charge on the anions.

Answer to Problem 4.75E

The formula for the compound by using M containing appropriate charges, which represents the metal ion, is $\text{M}{\left({\text{NO}}_3\right)}_2$.

Explanation of Solution

While writing the formula of the covalent molecule, the name of the atom having less electronegativity is given first. Then, the most electronegative atom is added with a suffix –ide.

It is given that metal, M, is taken from the group IIA(2) and combined this metal with ${\text{NO}}_3^{-}$. The metal that belongs to the group IIA(2) must have $+2$ charge over it. So, the charge on M is ${\text{M}}^{+}$. The given charge on nitrite ion is $-1$. To balance the charges, this formula of the compound contains one M ions as cation with $+2$ charge and two nitrite ions as anion each with $-1$ charge.

Therefore, the formula that can be given to the compound is $\text{M}{\left({\text{NO}}_3\right)}_2$.

Conclusion

The formula for the compound is $\text{M}{\left({\text{NO}}_3\right)}_2$.

Interpretation Introduction

(c)

Interpretation:

The formula for the compound by using M containing appropriate charges, which represents the metal ion, is to be stated.

Concept introduction:

The smallest particle which represents an ionic compound is known as formula unit. While writing the chemical formula of a compound, the net charge present over the formula unit should be zero. The zero net charge is obtained by equalizing the total positive charge on cations with the total negative charge on the anions.

Answer to Problem 4.75E

The formula for the compound by using M containing appropriate charges, which represents the metal ion, is ${\text{M}}_{\text{2}}{\text{SO}}_{\text{4}}$.

Explanation of Solution

While writing the formula of the covalent molecule, the name of the atom having less electronegativity is given first. Then, the most electronegative atom is added with a suffix –ide.

It is given that any metal forms ${\text{M}}^{+}$ and combined this metal ion with ${\text{SO}}_4^{2-}$. So, the charge on M is ${\text{M}}^{+1}$. The given charge on sulfate ion is $-2$. To balance the charges, this formula of the compound contains two M ions as cation each with $+1$ charge and one sulfate ion as anion with $-2$ charge.

Therefore, the formula that can be given to the compound is ${\text{M}}_{\text{2}}{\text{SO}}_{\text{4}}$.

Conclusion

The formula for the compound is ${\text{M}}_{\text{2}}{\text{SO}}_{\text{4}}$.

Interpretation Introduction

(d)

Interpretation:

The formula for the compound by using M containing appropriate charges, which represents the metal ion, is to be stated.

Concept introduction:

The smallest particle which represents an ionic compound is known as formula unit. While writing the chemical formula of a compound, the net charge present over the formula unit should be zero. The zero net charge is obtained by equalizing the total positive charge on cations with the total negative charge on the anions.

Answer to Problem 4.75E

The formula for the compound by using M containing appropriate charges, which represents the metal ion, is $\text{M}{\left(\text{OH}\right)}_{\text{3}}$.

Explanation of Solution

While writing the formula of the covalent molecule, the name of the atom having less electronegativity is given first. Then, the most electronegative atom is added with a suffix –ide.

It is given that any metal forms ${\text{M}}^{3+}$ and combined this metal ion with ${\text{OH}}^{-}$. So, the charge on M is ${\text{M}}^{3+}$. The given charge on hydroxyl ion is $-1$. To balance the charges, this formula of the compound contains one M ion as cation with $+3$ charge and three hydroxyl ions as anion each with $-1$ charge.

Therefore, the formula that can be given to the compound is $\text{M}{\left(\text{OH}\right)}_{\text{3}}$.

Conclusion

The formula for the compound is $\text{M}{\left(\text{OH}\right)}_{\text{3}}$.

Interpretation Introduction

(e)

Interpretation:

The formula for the compound by using M containing appropriate charges, which represents the metal ion, is to be stated.

Concept introduction:

The smallest particle which represents an ionic compound is known as formula unit. While writing the chemical formula of a compound, the net charge present over the formula unit should be zero. The zero net charge is obtained by equalizing the total positive charge on cations with the total negative charge on the anions.

Answer to Problem 4.75E

The formula for the compound by using M containing appropriate charges, which represents the metal ion, is $\text{M}\left({\text{HPO}}_4\right)$.

Explanation of Solution

While writing the formula of the covalent molecule, the name of the atom having less electronegativity is given first. Then, the most electronegative atom is added with a suffix –ide.

It is given that any metal forms ${\text{M}}^{2+}$ and combined this metal ion with ${\text{HPO}}_4^{2-}$. So, the charge on M is ${\text{M}}^{2+}$. The given charge on anion is $-2$. To balance the charges, this formula of the compound contains one M ion as cation with $+2$ charge and one ${\text{HPO}}_4^{2-}$ ion as anion with $-2$ charge.

Therefore, the formula that can be given to the compound is $\text{M}\left({\text{HPO}}_4\right)$.

Conclusion

The formula for the compound is $\text{M}\left({\text{HPO}}_4\right)$.