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A truck loaded with cannonball watermelons stops suddenly to avoid running over the edge of a washed-out bridge (Fig. P4.76). The quick stop causes a number of melons to fly off the truck. One melon leaves the hood of the truck with an initial speed υi, = 10.0 m/s in the horizontal direction. A cross section of the bank has the shape of the bottom half of a parabola, with its vertex at the initial location of the projected watermelon and with the equation y2= 16x, where x and y are mea-
sured in meters What are the x and y coordinates of the melon when it splatters on the bank?
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Bundle: Physics for Scientists and Engineers, Technology Update, 9th Loose-leaf Version + WebAssign Printed Access Card, Multi-Term
- A motorcycle daredevil plans to ride up a 2.85 m high 29.0° ramp, sail across a 10-m-wide pool filled with hungry crocodiles, and land at ground level on the other side. He has done this stunt many times and approaches it with confidence. Unfortunately, the motorcycle engine dies just as starts up the ramp. He is going 18.2 m/s at that instant, and the rolling friction of his rubber tires is not negligible. Assuming that the local acceleration due to gravity is -9.80 m/s², calculate the landing point (in m) relative to the 10.0 m edge of the pool. (-1.0 m means he was 1.0 m short and in the pool, +1.0 m means he landed 1.0 m past the edge). The coefficient of rolling friction for rubber on ramp is 0.02. Submit Answer Tries 0/10arrow_forwardA truck carrying watermelons stops suddenly at the edge of a washed-out bridge (see figure below). The sudden stop causes several watermelons to fly off the truck. One watermelon rolls over the cab of the truck and is moving with an initial speed v₁ = 16.0 m/s in the horizontal direction at the instant shown. The river bank's cross section has the shape of the bottom half of a parabola, with its vertex at the initial location of the projected watermelon and with the equation y2 = 8x, where x and y are measured in meters. (The origin of the coordinate system is the initial position of the watermelon.) What are the x- and y-coordinates (in m) of the melon when it splatters on the bank? X = y = 3 3 Need Help? Read It Viarrow_forwardHere is my problem: From the top of a cliff overlooking a lake, a person throws two stones, as shown in the drawing. The cliff is 15.4 m high. The two stones described have identical initial speeds of v0 = 18.0 m/s and are thrown at an angle θ = 26.7 °, one below the horizontal and one above the horizontal. What is the distance between the points where the stones strike the water? Neglect air resistance. I think I have the correct steps.. but can't seem to get the right answer. I would like someone to walk me through how to solve this.arrow_forward
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- A model of a helicopter rotor has four blades, each 3.40 m long from the central shaft to the blade tip. The model is rotated in a wind tunnel at 550 rev/min. (a) What is the linear speed of the blade tip, in m/s? (b) What is the radial acceleration of the blade tip expressed as a multiple of g?arrow_forward32. Figure P4.32 represents the total acceleration of a particle mov- ing clockwise in a circle of radius 2.50 m at a certain instant of 15.0 m/s? a = 2.50 m time. For that instant, find (a) the radial acceleration of the particle, (b) the speed of the particle, and (c) its tangential acceleration. 30.0°arrow_forwardFigure P4.31 represents the total acceleration of a particle moving clockwise in a circle of radius 2.50 m at a certain instant of time. At this instant, find (a) the radial acceleration, (b) the speed of particle, and (c) its tangential accelerationarrow_forward
- A projectile is shot at a hill, the base of which is 300 m away. The projectile is shot at 60° above the horizontal with an initial speed of 75 m/s. The hill can be approximated by a plane sloped at 20° to the horizontal. Relative to the coordinate system shown in the figure, the equation of this straight y = (tan 20°) x - 109. Where on the hill does the projectile land? 75 m/s 60⁰ y = (tan 20°)x - 109 -300 m- 20⁰arrow_forwardHole number 7 at Pebble Beach golf course is one of the shortest championship holes in the world. The hole is only 100m away from the tee, and it is also 12m lower. Champion golfer Shooter McGavin hits a 9-iron at an angle of 50◦ with respect to the horizontal, and lands the ball right in the hole. Assume there is no wind or air resistance, and g = 9.8 m/s^2. (sin 50◦ = 0.766, cos 50◦ = 0.643, tan 50◦ = 1.19, sin 45◦ = 0.707, cos 45◦ = 0.707, tan 45◦ = 1.00). What is the initial velocity of the ball? How long was the ball in the air? What was the maximum height? If Shooter had misjudged the hole, and hit the ball with the same velocity but at an angle of 45◦ instead, by how much would he have overshot the hole?arrow_forwardThe aorta is a major artery, rising upward from the left ventricle of the heart and curving down to carry blood to the abdomen and lower half of the body. The curved artery can be approximated as a semicircular arch whose diameter is 4.3 cm. If blood flows through the aortic arch at a speed of 0.37 m/s, what is the magnitude (in m/s²) of the blood's centripetal acceleration?arrow_forward
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