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An aging coyote cannot run fast enough to catch a road-runner. He purchases on eBay a set of jet-powered roller skates, which provide a constant horizontal acceleration of 15.0 m/s2 (Fig. P1.78). The coyote starts at rest 70.0 in from the edge of a cliff at the instant the roadrunner zips past in the direction of the cliff, (a) Determine the minimum constant speed the roadrunner must have to reach the cliff before the coyote. At the edge of the cliff', the roadrunner escapes by making a sudden turn, while the coyote continues straight ahead. The coyote’s skates remain horizontal and continue to operate while he is in flight, so his acceleration while in the air ss (15.0 - 9.80
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Chapter 4 Solutions
EBK PHYSICS FOR SCIENTISTS AND ENGINEER
- Myla participated in a running competition. She ran around a circular track with a radius of 1.0 x 102 m. Myla completed the track after 2 minutes. If she had a constant speed, what was Myla’s average speed in the entire run? answer in "m·s", please.arrow_forwardYou attach a meter stick to an oak tree, such that the top of the meter stick is 2.672.67 meters above the ground. Later, an acorn falls from somewhere higher up in the tree. If the acorn takes 0.1860.186 seconds to pass the length of the meter stick, how high ℎ0h0 above the ground was the acorn before it fell, assuming that the acorn did not run into any branches or leaves on the way down?arrow_forwardA helicopter is ascending vertically with a speed of 5.30 m/s. At a height of 107 m above the Earth, a package is dropped from the helicopter. How much time does it take for the package to reach the ground? [Hint: What is v0 for the package?] Express your answer to three significant figures and include the appropriate units. My Answer is that t= 4.163 but what unit is it? I tried s, m/s, min but none of them were correct. PLEASE HELP CONFIRM MY ANSWER and THE UNIT along with 4.163arrow_forward
- A thief is trying to escape from a parking garage after completing a robbery, and the thief’s car is speeding (v = 11 m/s) toward the door of the parking garage (Fig. P2.60). When the thief is L = 14 m from the door a police officer flips a switch to close the garage door. The door starts at a height of 7 m and moves downward at 0.3 m/s. If the thief’s car is 1.4 m tall, will the thief escape? (Find the height of the door above the ground).arrow_forwardA rocket starts from rest and moves upward from the surface of the earth. For the first 10.0 s of its motion, the vertical acceleration of the rocket is given by ay = (2.80 ?/?^3)t, where the +y direction is upward. a) What is the height of the rocket above the surface of the earth at t = 10.0?? b) What is the speed of the rocket when it is 325 m above the surface of the earth?arrow_forwardA thief is trying to escape from a parking garage after completing a robbery, and the thief’s car is speeding (v = 12 m/s) toward the door of the parking garage (Fig. P2.60). When the thief is L = 30 m from the door, a police officer flips a switch to close the garage door. The door starts at a height of 2.0 m and moves downward at 0.20 m/s. If the thief’s car is 1.4 m tall, will the thief escape?arrow_forward
- A thief is trying to escape from a parking garage after completing a robbery, and the thief's car is speeding (v = 12 m/s) toward the door of the parking garage (Fig. P2.60). When the thief is L= 30 m from the door, a police officer flips a switch to close the garage door. The door starts at a height of 2.0 m and moves downward at 0.20 m/s. If the thief's car is 1.4 m tall, will the thief escape? Garage door L Figure P2.60arrow_forwardthe rocket starts from rest at t=0 and travel straight up. it's height above the ground as a function of time can be approximated by s=bt^2+ct^3, where b and c are constants. at t=10s, the rocket's velocity and acceleration are v= 229m/s and a=28.2 m/s^2 A.) determine the time in seconds at which the rocket reaches supersonic speed (325 m/s) B.) determine the value of constant B C.) determine the value of constant Carrow_forwardA toy car starts at rest and accelerate up a 40" ramp with acceleration a=√(t^3). It then flies into the air, and lands back on the ground. If the height of the ramp is h=6 m, what is the horizontal distance ?arrow_forward
- A car drives around a circular track of diameter 161 m at a constant speed of 47.4 m/s. During the time it takes the car to travel 256 degrees around, what is the magnitude of the car s average acceleration? Hint: Do not calculate instantenous accelleration. Instead calculte the average acceleration over the fraction of a complete lap. Average acceleration equals change in velocity divided by change in time, and that this is a two-dimensional situation so you'll have to calculate the x and y components of the average acceleration first and then figure out the magnitude. Remember also that ax = Δvx/Δt and ay = Δvy/Δt. 0 m/s^2 27.91 m/s^2 13.96 m/s^2 9.84 m/s^2arrow_forwardA student holds a ball 1.55 meters above the ground and drops it. Her friend uses a stopwatch and measures a time of 0.57 seconds for the ball to hit the ground. The ball accelerates due to gravity. Using the equation y = 1/2??2 where y is the height, to compute g , calculate the acceleration of the ball.arrow_forwardAn insect takes 8.03 minutes to walk 19.9 m toward the south along a deserted highway. A driver stops and picks up the insect. The driver takes the insect to a town 1.62 km to the north with an average speed of 15.6 m/s. What is the magnitude of the average velocity of the insect for its entire journey? Express your answer to 3 significant figures in meters/second.arrow_forward
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