Electric machinery fundamentals
5th Edition
ISBN: 9780073529547
Author: Chapman, Stephen J.
Publisher: MCGRAW-HILL HIGHER EDUCATION
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Chapter 4, Problem 4.7Q
Would you expect a 400-Hz generator to be larger or smaller than a 60-Hz generator of the same power and voltage rating? Why?
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why does a series connected DC generator output voltage increase with an increase of the load current?
A 10-kW, 250-V compound (long-shunt) generator has a no-load voltage of 230 V. The shunt field has 800 turns per pole and the series field 8.5 turns per pole. The shunt- and the series-field resistances are 80 ohms and 0.07 ohm, respectively. In order to make the generator flat-compound, so that it will have a no-load voltage of 230 V and a full-load voltage of 230 V, the series must produce 225 amp-turns. Calculate: (a) the resistance of the diverter to accomplish this change; (b) the total number of ampere-turns produced by each pole at no-load and at full-load.
Differentiate the types of commulative compound dc generator.
Explain how the DC Generator building out voltages.
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- . A 20 kW compound generator works on full load with terminal voltage of 250 V. The armature, series, and shunt windings have resistances of 0.05-ohm, 0.025 ohm, and 100 ohms, respectively. If the machine is connected short shunt, the emf generated is nearest to. (Our subject is Electrical Machines 1 ) (I need a clear answer and solution. Thank you so much)arrow_forwardA 250-V, 50-kW shunt generator has 1000 turns on each pole of its field winding. On no load a current of 3:5 A in the field winding produces a terminal voltage of 250 V, but on full load the shunt current has to be increased to 5 A for the same terminal voltage at the same speed. Calculate the number of series field turns per pole required for level compounding.arrow_forwardQ2)A. Explain compound DC generator, also describe its types and terminal characteristics of compound DC generator. proper explanation and diagramarrow_forward
- D2. When a generator's full-load output voltage is the same as its no-load output voltage it is said to be a) under-compounded b) flat-compounded c) over-compounded d) none of the above D3. The output of an overcompounded DC generator can be lowered by use of a a) rheostat connected in series with the series field b) rheostat connected in parallel with the series field c) rheostat connected in parallel with the shunt field d) none of the above D4. When might it be desirable to use an overcompounded generator? a) never b) always c) to compensate for line loss d) when you need a higher no-load voltage than your full-load voltagearrow_forwardA long shunt compound generator has shunt field resistance with 1200 turns/pole and a series field with 4.5 turns/pole. If the shunt field and series field ampere turns are, respectively, 1200 and 196, calculate the power delivered to a load when the terminal voltage is 230 volts.arrow_forwardThe armature reaction occurs when a separately excited generator supplies rated load: Is always present Is always absent May be sometimes present None of the abovearrow_forward
- Why does an alternator's voltage rise when it is loaded down with a leading load?arrow_forwardDEGREE: ELECTRICAL ENGINEERING SUBJECT/COURSE: AC MACHINES Answer the following questions (A, B and C) depending on the topic. 1. ALTERNATORS A. Why is it necessary to maintain the speed of an alternator at all times and how do they control the speed of an alternator when in operation? B. Distinguish between half-coiled and full-coiled armature windings in alternators. C. Why are fractional pitch windings generally used in alternators?arrow_forwardQ2: A three phase alternator is rated at 120 mva,13.2 kv,0.8 pf lagging, and 60 Hz. its direct axis reactance is 0.62 N and its quadrature axis reactance is 0.4 N.all rotational losses may be neglected . 1-What is the voltage of this generator at the rated condition? 2- what is the voltage regulation of this generator at the rated conditions?arrow_forward
- A short shunt compound generator delivers 150A at a terminal voltage is 230V. The shunt field current is 2.5A. The resistances of the armature, series field and diverter are 0.032-ohm, 0.015 ohm and 0.03 ohm, respectively. Calculate the electrical efficiency of the generator at this load.arrow_forwardThe series field winding of a 170 kW, 250 V, 1450 rpm compound generator has a resistance of 0.00306 ohm. What will be the required resistance (in Ohm) of a noninductive diverter that will bypass 27 percent of the total armature current? "arrow_forwardA short-shunt compound wound generator has a shunt field resistance of 77 ohms, a series field resistance of 0.008 ohms, a commutating pole winding resistance of 0.005 ohms, and an armature resistance including brushes of 0.02 ohms. When the armature current is 128 amperes, the generated emf is 234.5 volts. Calculate the power delivered to the load. note: A commutating pole winding is connected in series with the armature winding.arrow_forward
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Working Principle of DC Motor (animation of elementary model); Author: chrvoje engineering;https://www.youtube.com/watch?v=j_F4limaHYI;License: Standard Youtube License