Concept explainers
(a)
Interpretation:
The volume of
Concept Introduction:
Titration: It is a quantitative analysis method used to express the concentration of acid or base present in the solution.
For an
That is,
Here, V is volume and N is normality.
Normality: It generally expresses the concentration of acid or base as equivalents of acid or base present in one liter of the solution.
Molarity: The concentration for solutions is expressed in terms of molarity as follows,
Here, n is number of solute moles and V is volume of solution in liters.
The normality for any acid or base equals the molarity times of the number of
Equivalent of Acid: Generally, 1 equivalent of ion is the number of ions which has charge of one mole.
(a)
Answer to Problem 4.91QE
The volume of
Explanation of Solution
Given:
First, the concentration of
The equation for given reaction is
The mole of
(b)
Interpretation:
The volume of
Concept Introduction:
Refer part (a).
(b)
Answer to Problem 4.91QE
The volume of
Explanation of Solution
Given:
First, the concentration of
The equation for given reaction is
The mole of
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Chapter 4 Solutions
Chemistry: Principles and Practice
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- A soluble iodide was dissolved in water. Then an excess of silver nitrate, AgNO3, was added to precipitate all of the iodide ion as silver iodide, AgI. If 1.545 g of the soluble iodide gave 2.185 g of silver iodide, how many grams of iodine are in the sample of soluble iodide? What is the mass percentage of iodine, I, in the compound?arrow_forwardGlycerol (C3H8O3) is commonly used as an additive to moisturizers. The amount of glycerol added can be determined by titration with permanganate in basic solution. 14MnO4(aq)+C3H8O3(aq)+20OH(aq)14MnO42(aq)+3CO32(aq)+14H2O How many milliliters of 6.15 M KMnO4 are required to completely react with 7.25 mL of an aqueous solution of glycerol (d=1.144g/mL) that is 51.6% by mass?arrow_forwardA 10.0-mL sample of potassium iodide solution was analyzed by adding an excess of silver nitrate solution to produce silver iodide crystals, which were filtered from the solution. KI(aq)+AgNO3(aq)KNO3(aq)+AgI(s) If 2.183 g of silver iodide was obtained, what was the molarity of the original KI solution?arrow_forward
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