Lisa in her Lamborghini accelerates at ( 3.00 i ^ − 2.00 j ^ ) m / s 2 , while Jill in her Jaguar accelerates at ( 1.00 i ^ − 3.00 j ^ ) m / s 2 . They both start from rest at the origin. After 5.00 s, (a) what is Lisa’s speed with respect to Jill. (b) how far apart are they, and (c) what is Lisa’s acceleration relative to Jill?
Lisa in her Lamborghini accelerates at ( 3.00 i ^ − 2.00 j ^ ) m / s 2 , while Jill in her Jaguar accelerates at ( 1.00 i ^ − 3.00 j ^ ) m / s 2 . They both start from rest at the origin. After 5.00 s, (a) what is Lisa’s speed with respect to Jill. (b) how far apart are they, and (c) what is Lisa’s acceleration relative to Jill?
Solution Summary: The author explains Lisa's speed with respect to Jill after 5.00mathrmsec and the final velocity of her Lamborghini.
Lisa in her Lamborghini accelerates at
(
3.00
i
^
−
2.00
j
^
)
m
/
s
2
, while Jill in her Jaguar accelerates at
(
1.00
i
^
−
3.00
j
^
)
m
/
s
2
. They both start from rest at the origin. After 5.00 s, (a) what is Lisa’s speed with respect to Jill. (b) how far apart are they, and (c) what is Lisa’s acceleration relative to Jill?
Lisa in her Lamborghini accelerates at the rate of (3.401 - 4.20ĵ) m/s², while Jill in her Jaguar accelerates at (2.201 + 2.60ĵ) m/s². They both start from rest at the origin of an xy coordinate system. After 5.00 s, find the following.
(a) What is Lisa's speed with respect to Jill?
m/s
(b) How far apart are they?
m
(c) What is Lisa's acceleration relative to Jill?
a =
m/s²
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Lisa in her Lamborghini accelerates at the rate of (2.20î - 2.20ĵ) m/s², while Jill in her Jaguar accelerates at
(3.00 +2.00ĵ) m/s². They both start from rest at the origin of an xy coordinate system. After 5.00 s, find the following.
(a) What is Lisa's speed with respect to Jill?
m/s
(b) How far apart are they?
m
(c) What is Lisa's acceleration relative to Jill?
a =
m/s²
I just wanted to make sure I did this right
a) What is the car’s average speed, in km/h, from Hither to Yon for the first part of the trip?
G: △d=450Km △T=4.50hr
U: v
E v=△d△t
S v=450km4.50hr
S the average speed from Hither to Yon is 100km/h
b)How long, in hours, did it take for the car to return to Hither from Yon?
G: △d=90.0km/h V=100km/h
U: △t
E △t=△dV
S △t=90.0km100km/h
S It took 9.0hr to get back to Hither from Yon
c) What is the average velocity of the car for the entire (whole) journey, from Hither to Yon, and back to Hither?
G △d =450km + 450km = 900km △T=4.50hr+4.50hr=9.0hr
U: V
E v=△d△t
S v=900km9.0hr
S the average velocity for the entire journey is 100km/hr
Chapter 4 Solutions
Bundle: Physics for Scientists and Engineers with Modern Physics, Loose-leaf Version, 9th + WebAssign Printed Access Card, Multi-Term
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