EBK BIOLOGY
11th Edition
ISBN: 8220102797352
Author: Raven
Publisher: YUZU
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Chapter 41, Problem 1A
Summary Introduction
Introduction:
The monoecious flowers prevent self
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Under which of the following conditions would pollen from an S2S5 plant successfully pollinate an S1S5 flower?
a. Using pollen from a carpelate flower to fertilize a staminate flower would be successful.
b. If the plants used gametophytic self-incompatibility, half of the pollen would be successful.
c. If the plants used sporophytic self-incompatibility, half of the pollen would be successful.
d. Pollen from an S2S5 plant can never pollinate an S1S5 flower.
The drooping, bell-like flower Aquilegia canadensis is adapted for cross-pollination. However, if the plant has not been pollinated previously, self-pollination can occur. However, if cross pollination occurs after self-pollination takes place, the pollen from cross pollination reaches the style before the pollen from self-pollination. Using course concepts and vocabulary 1) Provide a reasoning for this phenomenon. 2) Would this adaptation for reproduction be beneficial for the plant?
Choose the statement that is true.a. All flowers are pollinated by bees.b. Apple trees are propagated by grafting because they are triploid.c. Carpels function to attract pollinators.d. A coleoptile protects the plumule of eudicot seedlings.e. The arrival of pollen on a receptive seed is called pollination.f. In plants, sperm cells are male gametes.g. Nutrients in fruits nourish new seedlings.
Chapter 41 Solutions
EBK BIOLOGY
Ch. 41 - Morphogenesis is the development of a. growth...Ch. 41 - Vernalization induces flowering following exposure...Ch. 41 - Prob. 3UCh. 41 - Which of the following is NOT a component of a...Ch. 41 - Megasporcs are produced in a. anthers by mitosis....Ch. 41 - A stamen contains a a. style. b. stigma. c....Ch. 41 - Unlike bee-pollinated flowers, bird-pollinated...Ch. 41 - Prob. 8UCh. 41 - Endosperm is produced by the union of a. a central...Ch. 41 - During the globular stage of embryo development,...
Ch. 41 - Which of the following is NOT a primary meristem?...Ch. 41 - Prob. 12UCh. 41 - The shoot tip of an emerging maize seedling is...Ch. 41 - Asexual reproduction is likely to be most common...Ch. 41 - Prob. 15UCh. 41 - Prob. 16UCh. 41 - Prob. 17UCh. 41 - Prob. 1ACh. 41 - Your roommate is taking biology with you this...Ch. 41 - In Iowa, a company called Team Corn works to...Ch. 41 - Prob. 4ACh. 41 - One of the most notable differences between gamete...Ch. 41 - A plant lacking the WOODEN LEG gene will likely a....Ch. 41 - How would plant development change if the...Ch. 41 - Prob. 8ACh. 41 - Loss-of-function mutations in the suspensor gene...Ch. 41 - Prob. 1SCh. 41 - If you live in a north temperate region, explain...Ch. 41 - In wild columbine flower morphology encourages...Ch. 41 - In most part of the world, commercial potato crops...Ch. 41 - Design an experiment to determine whether light or...
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- Monoecious plants such as corn have either staminate or carpelate flowers. Knowing what you do about the molecular mechanisms of floral development, which of the following might explain the development of single-sex flowers? a. Expression of B-type genes in the presumptive carpel whorl will generate staminate flowers. b. Loss of A-type genes in the presumptive petal whorl will allow C-type and B-type genes to produce stamens instead of petals in that whorl. c. Restricting B-type gene expression to the presumptive petal whorl will generate carpelate flowers. d. All of the choices are correct.arrow_forwardCan you answer all the parts to this question please (a) What are the advantages of the self-incompatibility (SI) system in plants? Give at least three advantages. (b) What are the differences between gametophytic SI and sporophytic SI?arrow_forwardOne similarity about the chlorophyll content between the low and moderate light seedlings is: A. Both seedling groups have about the same amount of chlorophyll content for the first 12 hours of growth. B. Both seedling groups have the exact same amount of chlorophyll content for the first 8 hours of growth. C. Both seedling groups have the exact same amount of chlorophyll content for the first 3 to 5 hours of growth. D. Both seedling groups have the exact same amount of chlorophyll content for the last 24 hours of growth.arrow_forward
- Green fluorescent protein (GFP) can attach and mark other proteins with fluorescence, enabling scientists to see the presence of a particular protein. In an experiment to understand the molecular physiology behind the GA-induced seed germination, a GFP-tagged protein was observed to be moving from the cytoplasm into the nucleus of aleurone layer cells before the detection of alpha-amylase in the endosperm. Based on your knowledge, identify the possible protein(s) with which the GFP is attached in the given situation. Justify your answer.arrow_forwardWhat is the most likely consequence of a mutation that would cause sporopollenin to degrade quickly right after it is synthesized? -A reduction in the ability of pollen and spores to survive intact and disperse to new areas. -A reduction in the ability of pollinators to detect and transfer pollen grains to a stigma. -A decrease in the number of sperm that can be produced. -A decrease in the ability of the pollen grain or spore to open when a suitable location is found. -A reduction in the ability of the integument of an ovule to develop into a seed coat.arrow_forwardWhich of the following is True?a. Ethylene stimulates abscission layers to form.b. Abscisic acid causes abscission layers to form.c. Ethylene is sometimes sprayed on flowers to keep them fresh.d. Abscisic acid stimulates seed germination.arrow_forward
- What will be the flower structure of a plant in which expression of the following genes is inhibited in the specified whorls? a. Expression of class B genes is inhibited in the second whorl, but not in the third whorl. b. Expression of class C genes is inhibited in the third whorl, but not in the fourth whorl. c. Expression of class A genes is inhibited in the first whorl, but not in the second whorl. d. Expression of class A genes is inhibited in the second whorl, but not in the first whorl.arrow_forwardThe data that is attached below was collected during a lettuce seed ecotoxicity assay. Lettuce seed assays are used to compare the ecotoxicity of methanol, ethanol, and isopropanol by these alcohols' effects on germination rate and root elongination. Using the attached data, help answer which alcohol seems to be the most toxic to lettuce seeds. Why or why not would your results be expected? What does this information tell you about using ecotoxicity data to estimate human toxicity?arrow_forwardSuppose that 100 pollen grains land on a stigma, and 50 mature seeds are formed in the fruit. What does this indicate about the pollination process and success? A) 100% success: 100 pollen grains grew to 50 ovules, two to each, and double fertilization occurred. B) 100% success: Only 50% of the pollen grains germinated, but each produced 2 sperms to complete double fertilization in 50 seeds. C) 50% success: 50 sperm fertilized 50 eggs, and 50 sperm fused with 50 polar nuclei. D) 50% success: 50 sperm fertilized 50 eggs, and 50 sperm fused with 100 polar nuclei. correct answer and explanation why please.arrow_forward
- In the Philippines, owners and managers of plant nurseries have to plan lighting schedules for a long-day plant (LDP) with a critical night length of 10 hours that will flower in December. What lighting periods and color of light enrichment will be most effective for flowering of the said LDP? A. Light periods of 15 hours with light enriched in the red range of the spectrum B. Dark periods of 11 hours with light enriched in the red range of the spectrum C. Light periods of 14 hours with light enriched in the far-red range of the spectrum D. Dark periods of 9 hours with light enriched in the far-red range of the spectrum E. Light periods of 13 hours with light enriched in the red range of the spectrum F. Dark periods of 10 hours with light enriched in the far-red range of the spectrumarrow_forwardRefer to the figure. a. What gene mutation(s) will result in the loss of production of the sepals? b. What gene mutation(s) will result in the loss of production of the petals? c. What gene mutation(s) will result in the loss of production of the stamens? d. What gene mutation(s) will result in the loss of production of the carpels?arrow_forwardThe shoot morphologies of the Arabidopsis plants below reflect their genotypes. Upper case gene symbols indicate wild type alleles, lower case symbols indicate mutant alleles. Arrowheads indicate a vegetative shoot. What is the genotype of plant 2? A. LFY AP1 TFL1 B. lfy ap1 TFL1 C. lfy AP1 TFL1 D. LFY ap1 TFL1 E. LFY AP1 tfl1arrow_forward
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