   Chapter 4.1, Problem 28E

Chapter
Section
Textbook Problem

Finding an Indefinite Integral In Exercises 15-36, find the indefinite integral and check the result by differentiation. ∫ ( sec y ) ( tan y − sec y ) d y

To determine

To calculate: The expression of the indefinite integral, (4t2+3)2dt.

Explanation

Given:

The integral, (4t2+3)2dt.

Formula used:

The integration formula of a function, xn is,

xndx=xn+1n+1+C

The derivative of a function, xn is,

ddx(xn)=nxn1

And, the derivative of a constant is,

ddx(Constant)=0

Calculation:

Consider the integral given as,

(4t2+3)2dt

Integrate it as,

(4t2+3)2dt=(16t4+9+24t2)dt=16t4dt+24t2dt+9dt=16t4+14+1+24t2+12<

Still sussing out bartleby?

Check out a sample textbook solution.

See a sample solution

The Solution to Your Study Problems

Bartleby provides explanations to thousands of textbook problems written by our experts, many with advanced degrees!

Get Started

In Exercises 13 and 14, find the inverse function of f. f(x)=4x+6

Calculus: An Applied Approach (MindTap Course List)

Domain Find the domain of the expression. 13. x2+1x2x2

Precalculus: Mathematics for Calculus (Standalone Book)

Convert the expressions in Exercises 6584 to power form. 8

Finite Mathematics and Applied Calculus (MindTap Course List)

In Exercises 1-6, show the interval on a number line. 5. (0, )

Applied Calculus for the Managerial, Life, and Social Sciences: A Brief Approach 