Physics Laboratory Manual
4th Edition
ISBN: 9781133950639
Author: David Loyd
Publisher: Cengage Learning
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Textbook Question
Chapter 41, Problem 9PLA
Two lenses are in contact. One of the lenses has a focal length of +l0.0 cm when used alone. When the two are in combination, an object 20.0 cm away from the lenses forms a real image 40.0 cm away from the lenses. What is the focal length of the second lens? Show your work.
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The diagram shows a lens with a positive focal length 11 cm. (a) If we place an object at a distance of 25 cm from the lens, where will the resulting image position on the other side of the lens be found? Include units in answer, (b) With the object at 25 cm from the lens, what will the magnification be for the image at this position? (c) If we place an object at a distance of 4 cm from the lens, where will the resulting image position be found? (d) With the object at 4 cm from the lens, what will the magnification be for the image at this position?
Help on three part question on convex images please and thank you.
What would be the magnification on an object if the height of the image is 10 cm and the height of the object is 50 cm? Describe the condition of the image, i.e. upright or inverted, enlarged or diminished. Show all work for full credit.
Chapter 41 Solutions
Physics Laboratory Manual
Ch. 41 - Prob. 1PLACh. 41 - A double convex lens is made from glass with an...Ch. 41 - Prob. 3PLACh. 41 - For a diverging lens, state what kinds of images...Ch. 41 - For a converging lens, state what kinds of images...Ch. 41 - A lens has a focal length of f = +10.0 cm. If an...Ch. 41 - An object is 16.0 cm from a lens. A real image is...Ch. 41 - One lens has a focal length of +15.0 cm. A second...Ch. 41 - Two lenses are in contact. One of the lenses has a...
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- Lens and mirror practice! Draw ray diagrams for each of the following scenarios, and check your results using the lens/mirror equation. (a) Concave mirror, object at 2f. (b) Convex mirror, object at 2f. (c) Converging lens, object at f/2. (d) Diverging lens, object at f/2. (e) Two closely spaced converging lenses with the same focal length f, object at 2f. (Hint: Draw two separate ray diagrams; treat the image of the first lens as the object of the second—but be careful if the object ends up being virtual!) (f) Briefly discuss: can a convex mirror or diverging lens ever produce a real image? If not, why not; if yes, how?arrow_forwardConsider the compound optical system shown in the diagram, where two thin lenses of focal lengths 7.5 cm (left lens) and 35 cm (right lens) are separated by a distance 25 cm. If a 2.9 cm tall object is placed as indicated in part (a), and the image formed is 0.74 cm tall, what is the magnification of the first lens? M1 = b. Using the information from part (a), calculate the image distance, in centimeters, from the first lens. di1 =arrow_forwardAn object is placed 10 m before a convex lens with focal length 5.2 m . Another concave lens is placed 15.6 m behind the first lens with a focal length −7.2 m (see the figure below). Note: Make a ray diagram sketch in order to check your numerical answer. At what distance is the first image from the first lens? Answer in units of m. What is the magnification of the first image? At what distance is the second image from the second lens? Answer in units of m. What is the magnification of the final image, when compared to the initial object?arrow_forward
- An image seen through a convex mirror cut from a sphere of radius 20cm is exactly half size of the object. Where must the object and image be located? Support your work with a ray diagram. Hint: Remember that virtual distances are negative when using the mirror equation. Follow grading rubric. Explain answer.arrow_forward1. Find the focal length of a biconcave lens (n = 1.65) if the magnitudes of the radii of curvature are 0.40 m and 0.60 m. In your solution, did it matter which was surface A and which was surface B? Briefly explain (or show your solution). 2. When a glass lens is submerged in water, is its focal length less than, equal to, or greater than when it is surrounded by air? Explain using Snell’s law. 3. A small insect viewed through a convex lens is 1.8 cm from the lens and appears 2.5 times larger than its actual size. What is the focal length of the lens?arrow_forwarda convex mirror has a focal length of 1.1 m and the 2.4 m object is 2.6 m away from the mirror. What is the distance, magnification, and height of the image? Show your work.arrow_forward
- Show your knowledge on image formation in lenses or mirrors. Use the following attributes. ● Ray diagram (with Size, Characteristic ng Image formed [Attitude], Location, and Type of Imageformed) that describes image formation in your chosen activityarrow_forwardPlease show work. An object is located a distance of d0 = 15 cm in front of a concave mirror whose focal length is f = 12.5 cm. Write an expression for the image distance, di. Numerically, what is this distance in cm?arrow_forwardA flower 10.4 cm high is placed in front of a diverging lens. An upright, virtual image that is 4.1 cm high is formed on the same side of the lens as the flower. What is the magnification of the lens? Show your work. (13.3, 13.4)arrow_forward
- Please find the image distance, image height and magnification. Provide units as well. Thank youarrow_forwardFor each case below draw a ray diagram. Draw the image as an arrow and give a description of the image: (real, virtual or no image formed), (upright or inverted) and (enlarged, reduced or same size). 2.) Diverging Lensarrow_forwardFor the mirror in the attached picture, locate the image by drawing a ray diagram (3 rays) and describe the image. Is it: a. Upright, virtual, reduced. b. Inverted, real, magnified. c. Inverted, virtual, magnified. d. Upright, real, reduced. Thank you.arrow_forward
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