Explanation Given information: Water is flowing at a constant rate (i.e., constant volume per unit time) into a cylindrical container standing vertically. Formula used: Volume of the cylinder = π r 2 h Calculation: Let r be the radius of the cylinder. Let α be the constant rate of water flows into the Then the depth h for any time t, Volume of the cylinder = (constant rate)×(time ⇒ π r 2 h = α t ⇒ h = ( α π r 2 ) t ⇒ h = k t � To determine (b) To graph: The depth of the water against time.

Applied Calculus, 6e WileyPLUS + Loose-leaf

6th Edition

ISBN: 9781119408901

Author: Deborah Hughes-Hallett, Andrew M. Gleason, Patti Frazer Lock, Daniel E. Flath

Publisher: Wiley (WileyPLUS Products)

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Chapter 4.2, Problem 36P

To determine

(a)

To graph:

The depth of the water against time.

To determine

(b)

To graph:

The depth of the water against time.

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Chapter 4.2, Problem 35P

Chapter 4.2, Problem 37P

Chapter 4 Solutions

Applied Calculus, 6e WileyPLUS + Loose-leaf

Ch. 4.1 - Prob. 1P Ch. 4.1 - Prob. 2P Ch. 4.1 - Prob. 3P Ch. 4.1 - Prob. 4P Ch. 4.1 - Prob. 5P Ch. 4.1 - Prob. 6P Ch. 4.1 - Prob. 7P Ch. 4.1 - Prob. 8P Ch. 4.1 - Prob. 9P Ch. 4.1 - Prob. 10P

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(a) To graph: The depth of the water against time.

Solution Summary: The author explains how the graph of the depth function with respect to time is given.