PHYSICS F./SCI... W/MOD V.II W/KIT
4th Edition
ISBN: 9780134819884
Author: GIANCOLI
Publisher: PEARSON
expand_more
expand_more
format_list_bulleted
Concept explainers
Question
Chapter 43, Problem 9Q
To determine
The particle decay that occurs due to the
Expert Solution & Answer
Want to see the full answer?
Check out a sample textbook solution
Students have asked these similar questions
Determine which of the following decays is not allowed and explain why. (a) π+ → μ+ + n (b) μ- → e- + γ (c) Λ → p + π- (d) p → π+ + π0
Classify each of the following reactions or decays according to whether it is electromag-
netic, weak, strong, or none of these (doesn't take place).
2.
(d)
(е)
wo → T° + Y
2) Kaons are the lightest mesons that contain at least one strange or anti-strange valence
quark. The positive kaon (K+) has the valence quark content us and it can be
produced in the reaction T+ p → K+ +¯ + A, which proceeds through the strong
interaction.
(a) Draw a quark flow diagram for the reaction 1¯ +p→ K+ +¯ + A and deduce the
valence quark content of A.
b) A negative pion with energy E is incident on a stationary proton p. Show that
the minimum pion energy Emin required for the reaction T +p→ K+ + T+A to
occur is
(тк + т, + mл)? — т? — т?
Emin
2mp
where mr, mp, mK, and ma are the a, p, K+ and A masses, respectively.
Chapter 43 Solutions
PHYSICS F./SCI... W/MOD V.II W/KIT
Ch. 43.1 - Prob. 1AECh. 43.2 - Prob. 1CECh. 43.9 - Prob. 1DECh. 43.9 - Prob. 1EECh. 43 - Prob. 1QCh. 43 - If a proton is moving at very high speed, so that...Ch. 43 - Prob. 3QCh. 43 - Prob. 4QCh. 43 - Prob. 5QCh. 43 - Prob. 6Q
Ch. 43 - Prob. 7QCh. 43 - Prob. 8QCh. 43 - Prob. 9QCh. 43 - Prob. 10QCh. 43 - Prob. 11QCh. 43 - Prob. 12QCh. 43 - Prob. 13QCh. 43 - Prob. 14QCh. 43 - Prob. 15QCh. 43 - Prob. 16QCh. 43 - Prob. 17QCh. 43 - Prob. 18QCh. 43 - Prob. 19QCh. 43 - Prob. 20QCh. 43 - Prob. 1PCh. 43 - Prob. 2PCh. 43 - Prob. 3PCh. 43 - Prob. 4PCh. 43 - Prob. 5PCh. 43 - Prob. 6PCh. 43 - Prob. 7PCh. 43 - Prob. 8PCh. 43 - Prob. 9PCh. 43 - Prob. 10PCh. 43 - Prob. 11PCh. 43 - Prob. 12PCh. 43 - Prob. 13PCh. 43 - Prob. 14PCh. 43 - Prob. 15PCh. 43 - Prob. 16PCh. 43 - Prob. 17PCh. 43 - Prob. 18PCh. 43 - Prob. 19PCh. 43 - Prob. 20PCh. 43 - Prob. 21PCh. 43 - Prob. 22PCh. 43 - Prob. 23PCh. 43 - Prob. 24PCh. 43 - Prob. 25PCh. 43 - Prob. 26PCh. 43 - Prob. 27PCh. 43 - Prob. 28PCh. 43 - Prob. 29PCh. 43 - Prob. 30PCh. 43 - Prob. 31PCh. 43 - Prob. 32PCh. 43 - Prob. 33PCh. 43 - Prob. 34PCh. 43 - Prob. 35PCh. 43 - Prob. 36PCh. 43 - Prob. 37PCh. 43 - Prob. 38PCh. 43 - Prob. 39PCh. 43 - Prob. 40PCh. 43 - Prob. 41PCh. 43 - Prob. 42PCh. 43 - Prob. 43PCh. 43 - Prob. 44PCh. 43 - Prob. 45PCh. 43 - Prob. 46GPCh. 43 - Prob. 47GPCh. 43 - Prob. 48GPCh. 43 - Prob. 49GPCh. 43 - Prob. 50GPCh. 43 - Prob. 51GPCh. 43 - Prob. 52GPCh. 43 - Prob. 53GPCh. 43 - Prob. 54GPCh. 43 - Prob. 55GPCh. 43 - Prob. 56GPCh. 43 - Prob. 57GPCh. 43 - Prob. 58GPCh. 43 - Prob. 59GPCh. 43 - Prob. 60GPCh. 43 - Prob. 61GPCh. 43 - Prob. 62GPCh. 43 - Prob. 63GPCh. 43 - Prob. 64GPCh. 43 - What fraction of the speed of light c is the speed...Ch. 43 - Prob. 66GPCh. 43 - Prob. 67GP
Knowledge Booster
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, physics and related others by exploring similar questions and additional content below.Similar questions
- The K0 meson is an uncharged member of the particle “zoo” that decays into two charged pions according to K0 → π+ + π−. The pions have opposite charges, as indicated, and the same mass, mπ = 140 MeV/c2. Suppose that a K0 at rest decays into two pions in a bubble chamber in which a magnetic field of 2.0 T is present (see Fig. P2.22). If the radius of curvature of the pions is 34.4 cm, find (a) the momenta and speeds of the pions and (b) the mass of the K0 meson.arrow_forwardOne of the common decay modes of the is 0 is 0+p . Even though only hadrons are involved in this decay, it occurs through the weak nuclear force. How do we know that this decay does not occur through the strong nuclear force?arrow_forwardExplain how conservation of baryon number is responsible for conservation of total atomic mass (total number at nucleons) in nuclear decay and reactions.arrow_forward
- A proton and an antiproton collide headon, with each having a kinetic energy of 7.00 TeV (such as in the LHC at CERN). How much collision energy is available, taking into account the annihilation of the two masses? (Note that this is not significantly greater than the extremely relativistic kinetic energy.)arrow_forwardSuppose leptons are created in a reaction. Does this imply the weak force is acting? (for example, consider (decay.)arrow_forwardBased on quark composition of a proton, show that its charge is +1.arrow_forward
- Verify the quantum numbers given for the proton and neutron in Table 33.2 by adding the quantum numbers for their quark constituents as given in Table 33.4.arrow_forward2arrow_forwardCertain theories predict that the proton is unstable, with a half-life of about 1032 years.Assuming that this is true, calculate the number of proton decays you would expect to occur in one year in the water of an Olympic-sized swimming pool holding 4.32 * 105 L of water.arrow_forward
- Which of the following reactions obey the conservation of baryon number? (a) p + pS p + e+; (b) p + nS 2e+ + e-; (c) p S n bar + e- + ne; (d) p + p bar S 2g.arrow_forwardState which of the following decay modes is more likely. Justify the answer well. D+ → K + 2π+ or or D+ → π++πºarrow_forward5. When a muon decays, the angular distribution of the daughter electron is 1 P(cos 0) = (1 + a cos 0), where e is the angle measured relative to the muon spin, and a is a well-defined number. Imagine that you are writing a Monte Carlo model that includes such a decay. Find the quadratic equation that has to be solved to generate appropri- ate values for cos 0, in terms of computer-generated random numbers x that are uniform over the range 0arrow_forwardarrow_back_iosSEE MORE QUESTIONSarrow_forward_ios
Recommended textbooks for you
Modern PhysicsPhysicsISBN:9781111794378Author:Raymond A. Serway, Clement J. Moses, Curt A. MoyerPublisher:Cengage Learning
Principles of Physics: A Calculus-Based TextPhysicsISBN:9781133104261Author:Raymond A. Serway, John W. JewettPublisher:Cengage Learning
College PhysicsPhysicsISBN:9781938168000Author:Paul Peter Urone, Roger HinrichsPublisher:OpenStax College
College PhysicsPhysicsISBN:9781305952300Author:Raymond A. Serway, Chris VuillePublisher:Cengage Learning
College PhysicsPhysicsISBN:9781285737027Author:Raymond A. Serway, Chris VuillePublisher:Cengage Learning
Modern Physics
Physics
ISBN:9781111794378
Author:Raymond A. Serway, Clement J. Moses, Curt A. Moyer
Publisher:Cengage Learning
Principles of Physics: A Calculus-Based Text
Physics
ISBN:9781133104261
Author:Raymond A. Serway, John W. Jewett
Publisher:Cengage Learning
College Physics
Physics
ISBN:9781938168000
Author:Paul Peter Urone, Roger Hinrichs
Publisher:OpenStax College
College Physics
Physics
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Cengage Learning
College Physics
Physics
ISBN:9781285737027
Author:Raymond A. Serway, Chris Vuille
Publisher:Cengage Learning