Chapter 4.4, Problem 24PPS

To determine

To prove: $\Delta YXZ\cong \Delta WZX$

Explanation of Solution

Given information: $\overline{YX}\cong \overline{WZ}\&\overline{YX}\left|\right|\overline{ZW}$

  

Proof: Since $\overline{YX}\cong \overline{WZ}\&\overline{YX}\left|\right|\overline{ZW}$

By reflexive property of congruence, $\overline{YZ}\cong \overline{YZ}$

As alternate interior angles of two parallel lines are congruent,

  $\angle WZX\cong \angle YXZ$

By properties of Side Angle Side congruence postulate,

Therefore, $\Delta YXZ\cong \Delta WZX$