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- Using the inverses of the previous problem, find the solution of Ax = b and Bx = c for the vectors b = (3, 2, 1, 1, 4)^T and c = (1, 2, 1)^T , respectively.arrow_forwardSuppose A is equal to the following: A= 1 3 2 -1 2 -6 2 2 a) Determine N(A), the nullspace of A.b) Show that the vectors in your answer in part (a) span N(A) and are linearly independent.c) Do the vectors in your answer to part (a) span R4?arrow_forwardi) Solve the following system of equations using Gauss (or Gauss-Jordan) elimination: 3x+y =-2 4x +3y=-1 -2x+y =3 ii) Based ONLY on your answer in part (i) and without doing any extra work, answer True or False to the following statements and briefly explain why they are True or False (no explanation: no marks). 1) Vector w = (-2, -1, 3) belongs to the spanning set of vectors u = (3, 4, -2) and v = (1, 3, 1). 2) The set S = {(-2, -1, 3), (3, 4, -2), (1, 3, 1)} is a basis for its spanning set. 3) The following system of equations has a unique solution: 3x +y -2z=-1 4x +3y-z =0 -2x+y +3z=4arrow_forward
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