Algebra and Trigonometry: Structure and Method, Book 2

2000th Edition

ISBN: 9780395977255

Author: MCDOUGAL LITTEL

Publisher: McDougal Littell

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Question

Chapter 4.8, Problem 28P

To determine

To find the dimensions of the rug be ?

Expert Solution & Answer

Answer to Problem 28P

The dimensions of rug is 6m by 9m.

Explanation of Solution

Given information: Room size 9m by 12m.Rug is to cover half the floor space.

Calculation: The required solution is obtained as,

Area of room = 9×12=108

The area of the rug is half the area of the room.

Let D be the length of the strip of flooring around the rug.

The width and length of the rug is 9−2D and 12−2D .

Area of the rug is 54

(9−2D)(12−2D)=54108−24D−18D+4D2=54108−42D+4D2=544D2−42D+54=02D2−21D+27=0(2D−3)(D−9)=0D=3/2,9

D=9 gives the negative size of the rug. So, Ignore this value

D=3/2=1.5

Width of the rug is 9−2D=9−2×1.5=6

Length of the rug is 12−2D=12−2×1.5=9

Hence, the dimensions of rug is 6m by 9m.

Chapter 4.8, Problem 27P

Chapter 4.8, Problem 29P

Chapter 4 Solutions

Algebra and Trigonometry: Structure and Method, Book 2

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Polynomials with Trigonometric Solutions (2 of 3: Substitute & solve); Author: Eddie Woo;https://www.youtube.com/watch?v=EnfhYp4o20w;License: Standard YouTube License, CC-BY

Quick Revision of Polynomials | Tricks to Solve Polynomials in Algebra | Maths Tricks | Letstute; Author: Let'stute;https://www.youtube.com/watch?v=YmDnGcol-gs;License: Standard YouTube License, CC-BY

Introduction to Polynomials; Author: Professor Dave Explains;https://www.youtube.com/watch?v=nPPNgin7W7Y;License: Standard Youtube License