Concept explainers
Balance each of the following chemical equations.
a. KO2(s) + H2O(l) ⟶ KOH(aq) + O2(g) + H2O2(aq)
b. Fe2O3(s) + HNO3(aq) ⟶ Fe(NO3)(aq) + H2O(l)
c. NH3(g) + O2(g) ⟶ NO(g) + H2O (g)
d. PCl5(l) + H2O(l) ⟶ H3PO4(aq) + HCl(g)
e. CaO(s) + C(s) ⟶ CaC2(s) + CO2 (g)
f. MoS2(s) + O2(g) ⟶ MoO3(s) + SO2 (g)
g. FeCO3(s) + H2CO3(aq) ⟶ Fe(HCO3)2(aq)
(a)
Interpretation: A balanced form of the given chemical equations is to be stated.
Concept introduction: According to the law of conservation of mass, mass can neither be created nor destroyed. The mass of reactants is equal to the mass of products formed during a chemical process.
To determine: A balanced form of the given chemical equation.
Explanation of Solution
According to the law of conservation of mass, mass can neither be created nor destroyed. The mass of reactants is equal to the mass of products formed. Therefore a chemical equation, having lesser number of moles of an element on either side of a reaction, is balanced using appropriate numerical coefficients to satisfy the law of conservation of mass.
The given reaction is,
Adding the coefficient
Adding the coefficient
The balanced chemical equation is,
(b)
Interpretation: A balanced form of the given chemical equations is to be stated.
Concept introduction: According to the law of conservation of mass, mass can neither be created nor destroyed. The mass of reactants is equal to the mass of products formed during a chemical process.
To determine: A balanced form of the given chemical equation.
Explanation of Solution
According to the law of conservation of mass, mass can neither be created nor destroyed. The mass of reactants is equal to the mass of products formed. Therefore a chemical equation, having lesser number of moles of an element on either side of a reaction, is balanced using appropriate numerical coefficients to satisfy the law of conservation of mass.
The given reaction is,
Adding the coefficient
Adding the coefficient
The balanced chemical equation is,
(c)
Interpretation: A balanced form of the given chemical equations is to be stated.
Concept introduction: According to the law of conservation of mass, mass can neither be created nor destroyed. The mass of reactants is equal to the mass of products formed during a chemical process.
To determine: A balanced form of the given chemical equation.
Explanation of Solution
According to the law of conservation of mass, mass can neither be created nor destroyed. The mass of reactants is equal to the mass of products formed. Therefore a chemical equation, having lesser number of moles of an element on either side of a reaction, is balanced using appropriate numerical coefficients to satisfy the law of conservation of mass.
The given reaction is,
Adding the coefficient
Adding the coefficient
The balanced chemical equation is
(d)
Interpretation: A balanced form of the given chemical equations is to be stated.
Concept introduction: According to the law of conservation of mass, mass can neither be created nor destroyed. The mass of reactants is equal to the mass of products formed during a chemical process.
To determine: A balanced form of the given chemical equation.
Explanation of Solution
According to the law of conservation of mass, mass can neither be created nor destroyed. The mass of reactants is equal to the mass of products formed. Therefore a chemical equation, having lesser number of moles of an element on either side of a reaction, is balanced using appropriate numerical coefficients to satisfy the law of conservation of mass.
The given reaction is,
Adding the coefficient
Adding the coefficient
The balanced chemical equation is
(e)
Interpretation: A balanced form of the given chemical equations is to be stated.
Concept introduction: According to the law of conservation of mass, mass can neither be created nor destroyed. The mass of reactants is equal to the mass of products formed during a chemical process.
To determine: A balanced form of the given chemical equation.
Explanation of Solution
According to the law of conservation of mass, mass can neither be created nor destroyed. The mass of reactants is equal to the mass of products formed. Therefore a chemical equation, having lesser number of moles of an element on either side of a reaction, is balanced using appropriate numerical coefficients to satisfy the law of conservation of mass.
The given reaction is,
Adding the coefficient
Adding the coefficient
The balanced chemical equation is
(f)
Interpretation: A balanced form of the given chemical equations is to be stated.
Concept introduction: According to the law of conservation of mass, mass can neither be created nor destroyed. The mass of reactants is equal to the mass of products formed during a chemical process.
To determine: A balanced form of the given chemical equation.
Explanation of Solution
According to the law of conservation of mass, mass can neither be created nor destroyed. The mass of reactants is equal to the mass of products formed. Therefore a chemical equation, having lesser number of moles of an element on either side of a reaction, is balanced using appropriate numerical coefficients to satisfy the law of conservation of mass.
The given reaction is,
Adding the coefficient
Adding the coefficient
The balanced chemical equation is
(g)
Interpretation: A balanced form of the given chemical equations is to be stated.
Concept introduction: According to the law of conservation of mass, mass can neither be created nor destroyed. The mass of reactants is equal to the mass of products formed during a chemical process.
To determine: A balanced form of the given chemical equation.
Explanation of Solution
According to the law of conservation of mass, mass can neither be created nor destroyed. The mass of reactants is equal to the mass of products formed. Therefore a chemical equation, having lesser number of moles of an element on either side of a reaction, is balanced using appropriate numerical coefficients to satisfy the law of conservation of mass.
The given reaction is,
The given reaction is already present in its balanced form.
The balanced chemical equation is
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Chapter 5 Solutions
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