INTEGRAT PRINC OF ZOO (LL W/ CONNECT)
18th Edition
ISBN: 9781264177875
Author: HICKMAN
Publisher: MCG
expand_more
expand_more
format_list_bulleted
Concept explainers
Question
Chapter 5, Problem 13RQ
Summary Introduction
To determine: The probable genotypes of the individuals.
Introduction: Genotype is the genetic makeup of an organism. Offspring receive two sets of chromosomes in which each set belong to each parent. Color blindness is an X-linked recessive trait.
Expert Solution & Answer
Want to see the full answer?
Check out a sample textbook solutionStudents have asked these similar questions
Assume that color blindness is a recessive character on the X chromosome. A man and woman with normal vision have the following offspring: a daughter with normal vision who has one color-blind son and one normal son; a daughter with normal vision who has six normal sons; and a color-blind son who has a daughter with normal vision. What are the probable genotypes of all individuals?
Cystic fibrosis is a recessive human condition. A male with Cystic fibrosis and a woman with a dominant phenotype have sevral children, in which one displays Cystic fibrosis. What can you conclude about the genotype of the maternal parent and what is the probability that a child who does not display Cystic fibrosis is heterozygous?
In humans, the genes for colorblindness and hemophilia are both located on the X chromosome with no corresponding gene in the Y. These are both recessive alleles.
If a man and a woman, both with normal vision, marry and have a colorblind son, draw the Punnet square that illustrates this.
If the man dies and the woman remarries a colorblind man, draw a Punnet Square showing the type of children that could be expected from the second marriage. How many/what percentages of each could be expected.
Chapter 5 Solutions
INTEGRAT PRINC OF ZOO (LL W/ CONNECT)
Ch. 5 - What is the relationship between homologous...Ch. 5 - Describe or diagram the sequence of events in...Ch. 5 - What are the designations of the sex chromosomes...Ch. 5 - Prob. 4RQCh. 5 - Diagram by Punnett square a cross between...Ch. 5 - Prob. 6RQCh. 5 - Assuming brown eyes (B) are dominant over blue...Ch. 5 - Prob. 8RQCh. 5 - Prob. 9RQCh. 5 - Prob. 10RQ
Ch. 5 - Assume that right-handedness (R) is genetically...Ch. 5 - Prob. 12RQCh. 5 - Prob. 13RQCh. 5 - Distinguish the following: euploidy, aneuploidy,...Ch. 5 - Prob. 15RQCh. 5 - Prob. 16RQCh. 5 - Prob. 17RQCh. 5 - Prob. 18RQCh. 5 - Prob. 19RQCh. 5 - Prob. 20RQCh. 5 - Prob. 21RQCh. 5 - Why do many mutations have no detectable effects...Ch. 5 - Distinguish between proto-oncogene and oncogene....Ch. 5 - Prob. 24RQCh. 5 - Outline the essential steps in the polymerase...Ch. 5 - Prob. 26RQCh. 5 - Prob. 27RQCh. 5 - Prob. 1FFT
Knowledge Booster
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, biology and related others by exploring similar questions and additional content below.Similar questions
- The following pedigree shows the pattern of inheritance of red-green color blindness in a family. Females are shown as circles and males as squares; the squares or circles of individuals affected by the trait are filled in black. What is the chance that a son of the third-generation female indicated by the arrow will be color blind if the father is not color blind? If he is color blind?arrow_forwardA man who is an achondroplastic dwarf with normal vision marries a color- blind woman of normal height. The man's father was 6 feet tall, and both the woman's parents were of average height. Achondroplastic dwarfism is autosomal dominant, and red-green color blindness is X-linked recessive. They have a daughter who is a dwarf with normal vision. What is the probability that she is heterozygous for both genes? а. 0% b. 25% c. 50% d. 75% е. 100%arrow_forwardA gene that controls the ability to see red and green is located on the X chromosome but not on the Y chromosome. There is a recessive nonfunctional allele for this gene that can cause red-green color blindness if the person possessing it does not also have the dominant normal gene. Consider the case of a carrier mother who is heterozygous for the red-green vision gene and a father who has normal vision. Use XB = normal vision, Xb = color-blind vision. What is the chance the parents would have a color-blind boy? A color-blind girl? What about a girl or boy with normal vision? Redo the Punnett square for a carrier mother (XBXb) and a color-blind father (XbY). Do the chances of having color-blind children change? How?arrow_forward
- an unaffected woman who is heterozygous for the x linked allele causing duchenne muscular dystrophy has children with a normal man. What is the probability that their first child is an unaffected daughter and their second child is an affected son?arrow_forwardHemophilia is caused by an X-linked recessive mutation in humans. If a man whose paternal uncle (father's brother) was a hemophiliac marries a woman whose brother is also a hemophiliac, what is the probability that their first child will have hemophilia? (Assume that no other cases of hemophilia exist in the pedigree.) 1/3 0 1/8 0 1/4 1/2arrow_forwardA boy with Klinefelter syndrome (47,XXY) is born to a mother who is phenotypically normal and a father who has the X- linked skin condition called anhidrotic ectodermal dysplasia. The boy has patches of normal skin and patches of abnormal skin. Which of the following statemnets likely explains these observations? The father contributed the extra X chromosome in the son as a result of a non-disjunction in meiosis I during spermatogenesis. The mother contributed the extra X chromosome in the son as a result of a non-disjunction in meiosis II during oogenesis. The mother contributed the extra X chromosome in the son as a result of a non-disjunction in meiosis I during oogenesis. The father contributed the extra X chromosome in the son as a result of a non-disjunction in meiosis II during spermatogenesis. Either parent could have contributed to the extra X chromosome in the son as a results of disjunction in either meiosis I or meiosis II during…arrow_forward
- Red-green colorblindness in humans is caused by a sex-linked recessive allele. A color-blind man marries a woman with normal vision whose father was color-blind. Complete the Punnett square to answer the following questions: What is the probability that they will have a color-blind daughter? (X = wild type allele, Xc = color blind allele) Xc Y XcXc XY XCXY 1/2 3/4 None X Yc XcY XXc YYC 1/4 100% XC Y Probability of having a colorblind daughter? Aarrow_forwardA man who is an achondroplastic dwarf with normal vision marries a color-blind woman of normal height. The man's father was 6 feet tall, and both the woman's parents were of average height. Achondroplastic dwarfism is autosomal dominant, and red-green color blindness is X-linked recessive. a) How many of their daughters might be expected to be color-blind dwarfs? b)What proportion of their sons would be color-blind and of normal height? c)They have a daughter who is a dwarf with normal color vision. What is the probability that she is heterozygous for both genes?arrow_forwardRed-green color blindness is inherited as an X-linked recessive (Xc). If a color-blind man marries a woman who is heterozygous for normal vision, what would be the expected phenotypes of their children with reference to this character? In your answer, specify in your phenotype descriptions the gender of the children. (For example, don’t just say 75% of the children would be colorblind – you would instead say 100 % of the daughters would be colorblind and 50% of the sons would be colorblind. Note that this is not a correct answer; it is just to give you an idea of how to explain the correct phenotypes of the cross.)___arrow_forward
- Duchenne muscular dystrophy (DMD), marked by muscular degeneration, results from an X- linked recessive gene. Thus, a female who is heterozygous for this gene and does not have the disease can be a carrier. What kind of offspring can you expect from a DMD-affected male and a carrier female? Can there be a carrier male?arrow_forwardBoth red/green color blindness (R=normal, r=colorblind) and Duchenne-type muscular dystrophy (D=normal, d=muscular dystrophy) are X-linked recessive traits that map close to each other. A woman has a father who is red/green color blind. Her mother's family has a history of Duchenne's muscular dystrophy. This woman is apparently healthy with neither color blindness nor muscular dystrophy. She marries a healthy man and they have four sons and two daughters. Half the sons are healthy but color blind, the other half have normal color vision, but have Duchenne's muscular dystrophy. The daughters are both normal. What is the genotype of the woman? ** The notation is written as X/X (so the / separates the two X chromosomes in a female) Group of answer choices RD/rd rd/rd Rd/rD RD/RDarrow_forwardIn Drosophila, the white gene located on the X chromosome affects eye color; an autosomal gene, wingless, is on an autosomal chromosome. Use the following allele symbols: Xw+ _ , Xw+Y = wild type red eyes; X-linked dominant allele Xw Xw , XwY = white eyes; X-linked recessive allele Y = Y sex chromosome vg+ = wild type wings; autosomal dominant vg = wingless; autosomal recessive Predict ratios/proportions of genotypes and phenotypes of offspring from the following cross, of a white-eyed male with wild type wings and a wild type red eyed female with wild type wings: indicate sex of offspring along with phenotypes. XwY vg+ vg x Xw+Xw vg+vgarrow_forward
arrow_back_ios
SEE MORE QUESTIONS
arrow_forward_ios
Recommended textbooks for you
- Human Biology (MindTap Course List)BiologyISBN:9781305112100Author:Cecie Starr, Beverly McMillanPublisher:Cengage Learning
Human Biology (MindTap Course List)
Biology
ISBN:9781305112100
Author:Cecie Starr, Beverly McMillan
Publisher:Cengage Learning
Mitochondrial mutations; Author: Useful Genetics;https://www.youtube.com/watch?v=GvgXe-3RJeU;License: CC-BY