Chapter 5, Problem 26SA

Q9/Write a program in c++ that inputs a three-digit integer, separates the integer into its individual digits and prints the digits separated from one another by three spaces each by using functions.  For example, if the user types in 429, the program should print: 4 2 9

R7.30Assuming the following declarations, find the mistakes in the statements below. struct A { int m1[2]; int m2; } struct B { A a1; A* a2; int m3; } A a; B b[2]; a.b[0].a2 = a; b.b[1].m2 = 42; c.b[2].a2 = new A; d.b[0].a1.m1 = 42; e.b[1].a2->m2 = 42;

Question 1 is already done need help with the others though    This is the C code I have so far  #include <stdio.h>   #include <stdlib.h>   struct employees   {   char name[20];   int ssn[9];   int yearBorn, salary;   };   struct employees **emps = new employees()[10]; //Added new statement ---- bartleby     // function to read the employee data from the user   void readEmployee(struct employees *emp)   {   printf("Enter name: ");   gets(emp->name);   printf("Enter ssn: ");   for(int i =0; i <9; i++)   scanf("%d", &emp->ssn[i]);   printf("Enter birth year: ");   scanf("%d", &emp->yearBorn);   printf("Enter salary: ");   scanf("%d", &emp->salary);   }       // function to create a pointer of employee type   struct employees *createEmployee()   {   // creating the pointer   struct employees *emp = malloc(sizeof(struct employees));   // function to read the data   readEmployee(emp);   // returning the data   return emp;   }       // function to…

18. What is the return type of function id ? a. int b. float c. bool d. dict

Please use the below code to write code for median and standard deviation. I have already written for Average, Min, and Max value. Thanks!     #include <stdlib.h> #include <stdio.h> #include <pthread.h>   int nums; int* vals;   double avg; int min, max;   void* myAvg(void* param) {     avg = 0.0;     for(inti = 0; i < nums; ++i) {      avg += vals[i]; }   avg /= nums;   pthread_exit(0); }   void* myMin(void* param) {     min = vals[0];     for(inti = 1; i < nums; ++i) {            if(min > vals[i])                 min = vals[i]; }     pthread_exit(0); }   void* myMax(void* param) {       max = vals[0];       for(inti = 1; i < nums; ++i) {              if(max < vals[i])                   max = vals[i];       }      pthread_exit(0); } int main(int argc, char** argv) {      int i;      nums = (argc - 1);         if(nums <= 0) {             printf("you have to give atleat one value!\n");             return1;       }          vals =…

What is the output of the following code? for (int k = 2; k <= 10000; k = k * k)cout << k << " ";cout << endl;

Write minimum test cases for statement coverage.

What is the output of the code below?  def mystery_func(input, num, t = 0, x = 10, y = 10)[this function multiples all arguments together (except t) and raises the result to the power of t and returns this]print(mystery_func(2, 3))

What does it mean by line1 of the following C++ statements.   void y (int k) //line1 {   if ((k%2)==0)      cout<< k << " is an even number";   else      cout<< k << " is an odd number"; } A.Function name y receives an int-type parameter. The function y does not return anything to the caller. B.Function name y receives an int-type parameter. The function y does return an int-type value to the caller.