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If the vector components of the position of a particle moving in the xy plane as a function of time are
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Chapter 5 Solutions
Physics for Scientists and Engineers: Foundations and Connections
- For t 0, an object of mass m experiences no force and moves in the positive x direction with a constant speed vi. Beginning at t = 0, when the object passes position x = 0, it experiences a net resistive force proportional to the square of its speed: Fnet=mkv2i, where k is a constant. The speed of the object after t = 0 is given by v = vi/(1 + kvit). (a) Find the position x of the object as a function of time. (b) Find the objects velocity as a function of position.arrow_forwardIn the figure, a slab of mass m1 = 40 kg rests on a frictionless floor, and a block of mass m2 = 10 kg rests on top of the slab. Between block and slab, the coefficient of static friction is 0.60, and the coefficient of kinetic friction is 0.40. A horizontal force F→ of magnitude 104 N begins to pull directly on the block, as shown. In unit-vector notation, what are the resulting accelerations of (a) the block and (b) the slab?arrow_forwardA 3.5 kg particle moves along an x axis according to x(t) = −12 + 5t2 − 4t3, with xin meters and t in seconds. In unit-vector notation, what is the net force acting on theparticle at t = 6 s?arrow_forward
- A particle, which remains at rest, is acted on by three forces F, G and H. The force F has magnitude 16N and is directed to the right and down, making an angle of 50 degrees with the horizontal. The force G has magnitude 7N and is directed to the left and down, making an angle of 50 degrees with the horizontal. Find the magnitude of the vector H, and the acute angle it makes with the horizontal. Give the magnitude to one decimal place and the angle to the nearest degree. What is the magnitude of H and what is the acute angle H makes with the horizon?arrow_forwardDetermine the magnitude F and direction θ (measured clockwise from the positive y-axis which is downward in this case) that will cause the resultant R of the four applied forces to be directed to the right with a magnitude of 12.4 kN. 12.7 kN, 51.8o 17.2 kN, 15.8o 21.7 kN, 18.5o 72.1 kN, 81.5oarrow_forwardA drag force is represented by vector a of magnitude 5.72 N and direction 148.6 degrees (measured from the +x-axis, counter-clockwise). If the gravitational force of a projectile is represented by vector bof magnitude of 11.2 N. The x-component of the Sum vector, sx (N) is:arrow_forward
- a slab of mass m1 40 kg rests on a frictionless floor, and a block of mass m2 10 kg rests on top of the slab. Between block and slab, the coefficient of static friction is 0.60, and the coefficient of kinetic friction is 0.40.A horizontal force of magnitude 100 N begins to pull directly on the block, as shown. In unit-vector notation, what are the resulting accelerations of (a) the block and (b) the slab?arrow_forwardIn Fig, a slab of mass m1 =40 kg rests on a frictionless floor, and a block of mass m2 =10kg rests on top of the slab. Between block and slab, the coefficient of static friction is 0.60, and the coefficient of kinetic friction is 0.40. A horizontal force of magnitude 100 N begins to pull directly on the block, as shown. In unit-vector notation, what are the resulting accelerations of (a) the block and (b) the slab?arrow_forwardThree forces act on an object, considered to be a particle, which moves with constant velocity v =(3 m/s)î +(−2 m/s)ĵ Two of the forces are shown in the picture below., while the third force, F_3 is not given. 1.) What are the x, y, and z components of F_3?arrow_forward
- a 2 kg golf ball moves along an x axis according to x(t) = 10t^3 - 2.80t^2 + 7.4t +15 , with x in meters and t in seconds . in unit-vector notation , what is the net force acting on the particle at t= 5.20 s?arrow_forwardA 0.150 kg particle moves along an x axis according to x(t)=-13.00 + 2.00t - 4.00t2 -3.00t3, with x in meters and t in seconds. In unit-vector notation, what is the net force acting on the particle at t = 3.40 s?arrow_forwardThree forces act on an object, considered to be a particle, which moves with constant velocity v = (3i ^ − 2j ^ ) m/s. Two of the forces are F→1 = (3i ^ + 5j ^ − 6k ^ ) N and F→2 = (4i ^ − 7j ^ + 2k ^ ) N. Find the third force.arrow_forward
- Physics for Scientists and Engineers: Foundations...PhysicsISBN:9781133939146Author:Katz, Debora M.Publisher:Cengage LearningPhysics for Scientists and Engineers with Modern ...PhysicsISBN:9781337553292Author:Raymond A. Serway, John W. JewettPublisher:Cengage LearningPhysics for Scientists and EngineersPhysicsISBN:9781337553278Author:Raymond A. Serway, John W. JewettPublisher:Cengage Learning