Chapter 5, Problem 34SA

What is the result of the following code? int xNum T 0; int yNum = 0; do { xNum = xNum+yNum; yNum += 1; cout << "xNum: } while (xNum > 2); << xNum; O a.xNum: 2 is printed O b. no output, the loop is never executed O c. xNum: 0 is printed O d. endless loop

Loops, C++ Write a program whose input is two integers, and whose output is the first integer and subsequent increments of 5 as long as the value is less than or equal to the second integer. Ex: If the input is: -15 10 the output is: -15 -10 -5 0 5 10 Ex: If the second integer is less than the first as in: 20 5 the output is: Second integer can't be less than the first. For coding simplicity, output a space after every integer, including the last.

JAVA: Replace the for loop below with a code using the "While" loop: int s = 0; int c = 0; boolean valid = true; for(int i = 4; i <= 20 || valid; i = i+2) {      if(i%4 != 0) {           s = s + i;           c++;      }      if(i > 20) {           valid = false;      } } System.out.println(s / c);

What is the total number of iterations in the following loop ? for(int i=0; i<9; i+=2);   a   0 b   5 c   4 d   9

write this in pseudocode  #4 – In pseudocode, write a for-loop that decreases from 100 to 2 by 2s. Inside the loop, print the value of the loop variable unless the value is from 60 to 80 (inclusive). Use only 1 if-statement. Do NOT write Python code! Write your answer below:   #5 – Review the decision structure given below. If myAnswer > 20 Then    myAnswer = myAnswer - 25Else If myAnswer <= 5 Then    If myAnswer < 0 Then        myAnswer = 10    If myAnswer < 3 Then        myAnswer += 10    Else        myAnswer += 1Else    myAnswer = 9 If myAnswer < 10 ThenmyAnswer += 1 Display myAnswer What are the results displayed when the decision structure above executes for each given value below:If       myAnswer = 6        then myAnswer =         myAnswer = 15      then myAnswer =           myAnswer = 30      then myAnswer =              myAnswer = 2     then myAnswer =             myAnswer = -1    then myAnswer =     #6 – 2-dimensional arrays can be thought of as containing rows…

Harlan A. Brothers and John A. Knox discovered that as the value of x gets larger, the value of the expression gets closer and closer to e. Write a program that evaluates this expression for x = 1, 2, 3, and so on until the absolute difference between the expression’s value and the value of e calculated by the library function (exp) is less than 0.000001. Display the value of x that causes your loop to exit along with both the final approximation of e and the value of e calculated by the (exp) function. Show seven decimal places. IN C PROGRAMMING LANGUAGE PLEASE AND COMMENT EVERY STEP OF IT

Write a program that asks the user for a number of integer test scores. It then has the user enter that number of scores and computes the average. Ex: If the input is: 5 95 90 82 88 87 the output is: Your test average is: 88.4 You can assume that the first number is greater than 0. Hint: Use a loop to calculate the sum. When you are done with the loop, calculate the average. python

JAVA program   Write a while loop that prints all the even numbers from 1 to 100 (inclusive). and another while loop to print all the odd numbers from 1 to 100 (inclusive).

All the loops below are meant to do the same thing, except... Select one: a. int index = 0; do{    if(numbers[index]%2 == 1)          System.out.println(numbers[index]+" is an odd number.");   index++;}while(index < numbers.length); b. for(int a=0 ;a < numbers.length; a +=2){          System.out.println(numbers[a]+" is an odd number.") } c. for(int num:numbers){    if(num%2 == 1)          System.out.println(num+" is an odd number.") } d. int index = 0; while(index < numbers.length){    if(numbers[index]%2 == 1)          System.out.println(numbers[index]+" is an odd number.");    index++; } CLEAR MY CHOICE