Electrical Engineering: Principles & Applications, 7th Edition
7th Edition
ISBN: 9780134485201
Author: Allan R. Hambley
Publisher: PEARSON
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Textbook Question
Chapter 5, Problem 5.4P
Repeat Problem P5.3 for v(t) = 50 sin
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An electrical circuit with a sinusoidal voltage source, a resistor, and a capacitor all connected in series. The voltage across the capacitor:
Select one:
a.
Leads the current in the capacitor by exactly 90o
b.
Is in phase with the sinusoidal voltage source
c.
Is in phase with the voltage across the resistor
d.
Leads the current in the circuit by 90o
e.
Lags the current in the circuit by 90o
Please solve and show your detailed solution
Number 37
Shown in the figure below is an "RLC" circuit driven by an AC power source. The AC power source has an RMS voltage of Vps(RMS) = 11.80 Volts and is running at a frequency of f = 147000 Hz. The resistor has a resistance of R = 3910 Ω, the capacitor has a capacitance of C = 4.01e-10 Farads, and the inductor has an inductance of L = 5.97e-03 Henries.Write the FORMULA for the total impedance of the circuit Ztot =
Write the FORMULA for the phase of the total impedance of the circuit ?Ztot =
Determine the numerical value of Ztot = ΩDetermine the numerical value of ?Ztot = degreesDetermine the current through the circuit:
I(PEAK) = Amps
I(RMS) = Amps
Determine the voltage across the inductor:
VL(PEAK) = Volts
VL(RMS) = Volts
Determine the voltage across the capacitor:
VC(PEAK) = Volts
VC(RMS) = Volts
If a second circuit were connected in parallel with the resistor, this circuit would be considered as:
a high-pass filtera flux capacitor a radio tunera phase…
Chapter 5 Solutions
Electrical Engineering: Principles & Applications, 7th Edition
Ch. 5 - Consider the plot of the sinusoidal voltage...Ch. 5 - Repeat Problem P5.3 for v(t) = 50 sin (500t+120) .Ch. 5 - A sinusoidal voltage v(t) has an rms value of 20...Ch. 5 - A current i(t)=10cos(2000t) flows through a 100...Ch. 5 - We have a voltage v(t)=1000sin(500t) across a 500...Ch. 5 - Calculate the rms value of the half-wave rectified...Ch. 5 - We have v1(t)=10cos(t+30) . The current i1(t)has...Ch. 5 - Solve for the mesh currents shown in Figure P5.55.Ch. 5 - Two loads. A and B, are connected in parallel...
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- Shown in the figure below is an "RLC" circuit driven by an AC power source. The AC power source has an RMS voltage of Vps(RMS) = 9.35 Volts and is running at a frequency of f = 113000 Hz. The resistor has a resistance of R = 1980 , the capacitor has a capacitance of C = 1.08e-09 Farads, and the inductor has an inductance of L = 3.71e-03 Henries. mm Vps Write the FORMULA for the total impedance of the circuit Ztot = Write the FORMULA for the phase of the total impedance of the circuit øztot Determine the numerical value of Ztot = 2384 Determine the numerical value of @Z tot Determine the current through the circuit: ● R www I(PEAK) = I(RMS) = ● ● Determine the voltage across the inductor: • VL(PEAK) = Volts Volts VL(RMS) = Amps Amps Determine the voltage across the capacitor: Vc(PEAK) = Volts Volts Vc(RMS) = = 33.85 a capacitive switcher Ω degrees C If a second circuit were connected in parallel with the resistor, this circuit would be considered as: O a high-pass filter a radio tuner O…arrow_forwardCan I have help with problem 5.49?arrow_forwardFor a given series RC circuit with resistance R= 50 ohm and capacitance C= 1.5uF connected to an ac voltage source of 60 V, 2500 Hz, then the magnitude of current through the circuit is Select one: a. 5.45A b. 3.45A c. 0.915A d. None of thesearrow_forward
- Pls. write solution neatlyarrow_forwardQUESTION 3 An inductor, a capacitor, and a resistor are connected in series with a function generator. The inductor drops 5V RMS, the capacitor drops 20V RMS, and the resistor drops 2V RMS. Find the magnitude of the total voltage. O 27V RMS O 15V RMS O 38V RMS O 9V RMSarrow_forwardFor a series RLC circuit with a sinusoidal input voltage, the amplitude of the current passing through the circuit (I, in mA) is plotted as a function of frequency for two cases: Curve 1 with R1, L1. and Curve 2 with R2. L2 as shown in the next figure. The value of the capacitor used in the circuits is C=0.01 micro Farads. If the value of R2 =1600 Ohm then the input voltage (in volts) is: 7.5 25 110 Frequency H2 O a. 4 O b. 16 sin(9888 t) O c. 8 O d. 8 cos(6.28 f t) O e. 8 sin (6.28 R t)arrow_forward
- Please show workarrow_forwardThe following circuit corresponds to: Time left 0:51:55 Ic(s)→ of 2/s Vc( ) + 2/s O a. a 2F capacitor with an initial voltae v. (0)= 2V a 2F capacitor with an initial voltae v. (0)= 0.5V c a 0.5F capacitor with an initial voltae v. (0 ) = 2V a0.5F capacitor with an initial voltae v. (0 )= 0.5V d. e None of the other answers O Type here to searcharrow_forwardC1 L1 R1 V1 Vout V1 contains the fundamental and its harmonics (fo, 2fo, 3fo, ...). The amplitude of the harmonics is inversely proportional to the harmonic number. V(fo) = 10 mV V(2fo) = 10mv/2 = 5 mV V(3fo) = 10mv/3 = 3.33 mV V(4fo) = 10mv/4 = 2.55 mV a) What is the minimum value of Q for the circuit that will attenuate the third harmonic (3fo) in Vout to be less than 1% of the fundamental? b) What is the amplitude of the fifth harmonic (5fo) as a percentage of the fundamental?arrow_forward
- The current through a 50 mH inductor is given below. Use Ohm’s Law to find the voltage. Convert to polar form, find the impedance and complete the math, then convert back to the waveform at i1 = 7.5sin(2500t – 20°) mA and i2 = 5.9sin(200t + 40°) mAarrow_forwardasnwers with steps pleasearrow_forwardCan I have help with problem 5.33?arrow_forward
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