Concept explainers
(III) The position of a particle moving in the xy plane is given by
Want to see the full answer?
Check out a sample textbook solutionChapter 5 Solutions
PHYSICS F/SCI.+ENGR.,V.1 (CHAP.1-20)
Additional Science Textbook Solutions
Physics: Principles with Applications
Physics for Scientists and Engineers: A Strategic Approach, Vol. 1 (Chs 1-21) (4th Edition)
The Cosmic Perspective (8th Edition)
College Physics
University Physics (14th Edition)
Applied Physics (11th Edition)
- 0, y 0) 44. A projectile is launched from the point (x QC with velocity (12.0î + 49.0 j) m/s, at t = 0. (a) Make a table listing the projectile's distance |r| from the ori- gin at the end of each second thereafter, for 0 s I S 10 s. Tabulating the x and y coordinates and the compo- nents of velocity v and v will also be useful. (b) Notice that the projectile's distance from its starting point increases with time, goes through a maximum, and starts to decrease. Prove that the distance is a maximum when the position vector is perpendicular to the veloc- ity. Suggestion: Argue that if v is not perpendicular to f, then r|must be increasing or decreasing. (c) Determine the magnitude of the maximum displacement. (d) Explainarrow_forwardThe position of a particle moving in the xy plane varies with time, and its coordinates are given by the following expressions: x(t) = 4.00 m +r cos[(4.00/s)t] and y(t) = r sin[(4.00/s)t], where r = 2.00 m, and x and y will be in meters when t is in seconds. Determine the following for this particle. (a) speed of the particle at any time m/s (b) magnitude of the acceleration of the particle at any time m/s?arrow_forwardshow complete solutionarrow_forward
- (b) A particle moves with position y = 2x , where x and y are in meters. The velocity in x direction is v, = 31² . Determine the velocity at time t = 5 s and write in unit vectors.arrow_forward22)))At t = 0, a particle moving with constant acceleration in the xy plane has a velocity v = (3.00i-2.00j) m / s at its origin. At t = 3.00 s, the velocity of the particle is v = (9.00i + 7.00j) m / s. Find the acceleration of the particle?arrow_forwardInitially, a bicycle is at the position 7 = (130 m)i + (210 m)j. After 120 s, the position of the particle is 7 = (110 m)i + (240 m)j . What is the average velocity vector of the bicycle in that time || tinterval? O Tav = (0.17 m/s)i + (-0.25 m/s)j O Jay = (0.25 m/s)i + (-0.17 m/s) O Tay = (-0.25 m/s)î + (0.17 m/s) O Jay = (-0.17 m/s)i + (0.25 m/s)jarrow_forward
- Multiple-choice question: A particle moves in a circular motion at a uniform rate with a radius R, and makes one revolution every T seconds. Its average velocity and average velocity in a 2T time intervalarrow_forwardThe position of a particle is given by r(t) = A (cos wt i + sin wt j ). where w is a constant. (a) Show that the particle moves in a circle of radius A.arrow_forwardThe position F of a particle moving in an xy plane is given by: F =(2.00"–5.00t)i +(6.00–7.00€*)} with ř in meters and t in seconds. (Note that this is an example where the units for the coefficients are ignored – don't let this distract you!) In unit vector notation, calculate: а). г b). V с). а for time t = 2.00 s. d). What is the angle between the positive direction of the x axis and a line tangent to the particle's path at t= 2.00 s?arrow_forward
- A robotic vehicle, or rover, is exploring the surface of Mars. The stationary Mars lander is the origin of coordinates, and the sur-rounding Martian surface lies in the xy-plane. The rover, which we x = 2.0 m - 10.25 m > s22t2represent as a point, has x- and y-coordinates that vary with time:y = 11.0 m > s2t + 10.025 m > s32t3(a) Find the rover’s coordinates and distance from the lander at t = 2.0 s. (b) Find the rover’s displacement and average velocity vectors for the interval t = 0.0 s to t = 2.0 s. (c) Find a general S. Express expression for the rover’s instantaneous velocity vector vS at t = 2.0 s in component form and in terms of magnitude and vdirection. d) Find the instantaneous acceleration at t = 2.0 s. e) a1 , t=1sec a0 , t=0secarrow_forward(e) Calculate for a 14 m/s turn of radius 28 m. Assume all quantities are correct to 3 significant figures. Enter to 3 significant figures 0= ✔degreesarrow_forwardA particle travels around a circular path having a radius of 50 m. If it is initiallytraveling with a speed of 10 m/s and its speed then increases at a rate of a (v) = (0.05v) m/s 2 , thendetermine the magnitude of the particle’s acceleration four seconds later.arrow_forward
- Principles of Physics: A Calculus-Based TextPhysicsISBN:9781133104261Author:Raymond A. Serway, John W. JewettPublisher:Cengage LearningGlencoe Physics: Principles and Problems, Student...PhysicsISBN:9780078807213Author:Paul W. ZitzewitzPublisher:Glencoe/McGraw-Hill