BUSINESS DATA COMMUNICATIONS AND NETWORK
13th Edition
ISBN: 9781119441113
Author: FITZGERALD
Publisher: amazon.com
expand_more
expand_more
format_list_bulleted
Expert Solution & Answer
Chapter 5, Problem 6HA5
Explanation of Solution
Subnet Number Subnet Address Range of Host Address Direct Broadcast Address 0 192.168.111.0 192.168.111.1- 192.168.111.14 192.168.111.15 1 192.168.111.16 192.168.111.17 - 192.168.111.30 192.168.111.31 2 192.168.111.32 192.168.111.33 - 192.168.111.46 192.168.111.47 3 192.168.111.48 192.168.111.49 - 192.168.111.62 192.168.111.63 4 192.168.111.64 192.168.111.65 - 192.168.111.78 192.168.111.79 5 192.168.111.80 192.168.111.81 - 192.168.111.94 192.168.111.95 6 192.168.111.96 192.168.111.97 - 192.168.111.110 192.168.111.111 7 192.168.111.112 192.168.111.113 - 192.168.111.126 192.168.111.127 8 192.168.111.128 192.168.111.129 - 192.168.111.142 192.168.111.143 9 192.168.111.144 192.168.111.145 - 192.168.111.158 192.168.111.159 10 192.168.111.160 192.168.111.161 - 192.168.111.174 192.168.111.175 11 192.168.111.176 192.168.111.177 - 192.168.111.190 192.168.111.191 12 192.168.111.192 192.168.111.193 - 192.168.111.206 192.168.111.207 13 192.168.111.208 192.168.111.209 - 192.168.111.222 192.168.111.223 14 192.168.111.224 192.168.111.225 - 192.168.111.238 192.168.111.239 15 192.168.111.240 192.168.111.241 - 192.168.111.254 192.168.111.255
Subnet Number | Subnet Address | Range of Host Address | Direct Broadcast Address |
0 | 192.168.111.0 | 192.168.111.1- 192.168.111.14 | 192.168.111.15 |
1 | 192.168.111.16 | 192.168.111.17 - 192.168.111.30 | 192.168.111.31 |
2 | 192.168.111.32 | 192.168.111.33 - 192.168.111.46 | 192.168.111.47 |
3 | 192.168.111.48 | 192.168.111.49 - 192.168.111.62 | 192.168.111.63 |
4 | 192.168.111.64 | 192.168.111.65 - 192.168.111.78 | 192.168.111.79 |
5 | 192.168.111.80 | 192.168.111.81 - 192.168.111.94 | 192.168.111.95 |
6 | 192.168.111.96 | 192.168.111.97 - 192.168.111.110 | 192.168.111.111 |
7 | 192.168.111.112 | 192.168.111.113 - 192.168.111.126 | 192.168.111.127 |
8 | 192.168.111.128 | 192.168.111.129 - 192.168.111.142 | 192.168.111.143 |
9 | 192.168.111.144 | 192.168.111.145 - 192.168.111.158 | 192.168.111.159 |
10 | 192.168.111.160 | 192.168.111.161 - 192.168.111.174 | 192.168.111.175 |
11 | 192.168.111.176 | 192.168.111.177 - 192.168.111.190 | 192.168.111.191 |
12 | 192.168.111.192 | 192.168.111.193 - 192.168.111.206 | 192.168.111.207 |
13 | 192.168.111.208 | 192.168.111.209 - 192.168.111.222 | 192.168.111.223 |
14 | 192.168.111.224 | 192.168.111.225 - 192.168.111.238 | 192.168.111.239 |
15 | 192.168.111.240 | 192.168.111.241 - 192.168.111.254 | 192.168.111.255 |
Explanation:
- The user is assigned with192.168.111.129/28 and the given address belongs to class C network address.
- For class C network, the byte allocation is network.network.netwok.host.
- The prefix given in class C network address is 28.
- As class C address is given, the user uses 3 bytes for subnet field.
- However, because of a prefix given as 28, the user needs 4 more additional bits to create subnet field...
Expert Solution & Answer
Want to see the full answer?
Check out a sample textbook solutionChapter 5 Solutions
BUSINESS DATA COMMUNICATIONS AND NETWORK
Ch. 5 - Prob. 1QCh. 5 - Prob. 2QCh. 5 - Prob. 3QCh. 5 - Prob. 4QCh. 5 - Prob. 5QCh. 5 - Prob. 6QCh. 5 - Prob. 7QCh. 5 - Prob. 8QCh. 5 - Prob. 9QCh. 5 - Prob. 10Q
Ch. 5 - Prob. 11QCh. 5 - Prob. 12QCh. 5 - Prob. 13QCh. 5 - Prob. 14QCh. 5 - Prob. 15QCh. 5 - Prob. 16QCh. 5 - Prob. 17QCh. 5 - Prob. 18QCh. 5 - Prob. 19QCh. 5 - Prob. 20QCh. 5 - Prob. 21QCh. 5 - Prob. 22QCh. 5 - Prob. 23QCh. 5 - Prob. 24QCh. 5 - Prob. 25QCh. 5 - Prob. 26QCh. 5 - Prob. 27QCh. 5 - Prob. 28QCh. 5 - Prob. 1ECh. 5 - Prob. 4ECh. 5 - Prob. 5ECh. 5 - Prob. 1MCCh. 5 - Prob. 2MCCh. 5 - Prob. 3MCCh. 5 - Prob. 4MCCh. 5 - Prob. 1P1HA1Ch. 5 - Prob. 2P1HA1Ch. 5 - Prob. 1P2HA1Ch. 5 - Prob. 2P2HA1Ch. 5 - Prob. 1P3HA1Ch. 5 - Prob. 2P3HA1Ch. 5 - Prob. 1P4HA1Ch. 5 - Prob. 1P5HA1Ch. 5 - Prob. 2P5HA1Ch. 5 - Prob. 3P5HA1Ch. 5 - Prob. 1P1HA3Ch. 5 - Prob. 1P2HA3Ch. 5 - Prob. 1HA4Ch. 5 - Prob. 2HA4Ch. 5 - Prob. 3HA4Ch. 5 - Prob. 1HA5Ch. 5 - Prob. 2HA5Ch. 5 - Prob. 3HA5Ch. 5 - Prob. 4HA5Ch. 5 - Prob. 5HA5Ch. 5 - Prob. 6HA5Ch. 5 - Prob. 7HA5Ch. 5 - Prob. 1HA6Ch. 5 - Prob. 2HA6
Knowledge Booster
Recommended textbooks for you
- Computer Networking: A Top-Down Approach (7th Edi...Computer EngineeringISBN:9780133594140Author:James Kurose, Keith RossPublisher:PEARSONComputer Organization and Design MIPS Edition, Fi...Computer EngineeringISBN:9780124077263Author:David A. Patterson, John L. HennessyPublisher:Elsevier ScienceNetwork+ Guide to Networks (MindTap Course List)Computer EngineeringISBN:9781337569330Author:Jill West, Tamara Dean, Jean AndrewsPublisher:Cengage Learning
- Concepts of Database ManagementComputer EngineeringISBN:9781337093422Author:Joy L. Starks, Philip J. Pratt, Mary Z. LastPublisher:Cengage LearningPrelude to ProgrammingComputer EngineeringISBN:9780133750423Author:VENIT, StewartPublisher:Pearson EducationSc Business Data Communications and Networking, T...Computer EngineeringISBN:9781119368830Author:FITZGERALDPublisher:WILEY
Computer Networking: A Top-Down Approach (7th Edi...
Computer Engineering
ISBN:9780133594140
Author:James Kurose, Keith Ross
Publisher:PEARSON
Computer Organization and Design MIPS Edition, Fi...
Computer Engineering
ISBN:9780124077263
Author:David A. Patterson, John L. Hennessy
Publisher:Elsevier Science
Network+ Guide to Networks (MindTap Course List)
Computer Engineering
ISBN:9781337569330
Author:Jill West, Tamara Dean, Jean Andrews
Publisher:Cengage Learning
Concepts of Database Management
Computer Engineering
ISBN:9781337093422
Author:Joy L. Starks, Philip J. Pratt, Mary Z. Last
Publisher:Cengage Learning
Prelude to Programming
Computer Engineering
ISBN:9780133750423
Author:VENIT, Stewart
Publisher:Pearson Education
Sc Business Data Communications and Networking, T...
Computer Engineering
ISBN:9781119368830
Author:FITZGERALD
Publisher:WILEY