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(III) The drag force on large objects such as cars, planes, and sky divers moving through air is more nearly
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Chapter 5 Solutions
EP PHYSICS F/SCI.+ENG.W/MOD..-MOD.MAST.
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- Redo Example 5, assuming that there is no upward lift on the plane generated by its wings. Without such lift, the guideline slopes downward due to the weight of the plane. For purposes of significant figures, use 2.91 kg for the mass of the plane, 12.2 m for the length of the guideline, and 18.2 and 36.4 m/s for the speeds. (a) Number (b) Number Units Unitsarrow_forwardA car is travelling at 50.0 km/h on a flat highway. (a) If the coefficient of frictin between road and tires on a rainy day is 0.100 , what is the minimum distance in which tha car will stop? (b) What is the stopping distance when the surfaces is dry and the coefficient of friction is 0.600?arrow_forwardA certain car traveling at 97 km/h can stop in 46 m on a level road. Determine the coefficient of friction between the tires and the road. Assume that the car starts skidding the moment the driver hits the brakes.arrow_forward
- 7. The effects of atmospheric drag cannot be deglected, in general, on the dynamics of objects moving through the air. The drag force is found to be FD where p is the density of air, A is the cross sectional area of the object, v is the object's velocity, and Cp is the so called drag coefficient. For a baseball Cp is measured to be - .5ρA Cp υ?, .3. (a) If the baseball is launched vertically with a speed of 90 miles per hour, how high will it travel? How would the answer change ignoring air resistance? (b) What is the speed of the baseball when it comes back down? How would the answer change if there was no air resistance? (c) How long does it take for the baseball to go up? Down? How would the anwers change in the absence of air resistance?arrow_forwardA box weighing 1000 N is sitting in an inclined plane with an angle of 45°. Given the coefficient of friction of 0.25, calculate the horizontal force that can start the box the moving forward.arrow_forwardA 600 Kg car is moving on a level road at 30 m/s. (a) How large is the retarding force(assumed constant) is required to stop it in a distance of 70 m? (b) What is the minimum coefficient of friction between the tires and the roadway if this is possible ?arrow_forward
- Consider an object of mass m = 2kg moving up a ramp with an initial speed (vi) of 10m/s. Suppose that the ramp make an angle θ = 30◦ relative to the ground. Given that the coefficient of static friction and the coefficient of kinetic friction between the surfaces of the ramp and the object are μs = 0.6 and μk = 0.5 respectively. (a) Find the acceleration of the object as it slides up.(b) How far does the object move along the ramp?(c) Does the object move down the ramp after it reaches the maximum height (Justify your answer with calculation)?arrow_forward(1) Consider a medium with a quadratic drag force Farag = -cv². (a) Find an expression for the terminal velocity vT of a projectile in this medium. (b) Show that the equation of motion for vertical motion upwards can be written as i = -g[1+ (v/vr)³]. (c) As an intermediate step for part (d), use the chain rule of calculus to show that i = dv/dt can be written as i = v dv/dy. (d) Use the result from part (c) to write the equation of motion of part (b) in terms of dv/dy, and then use separation of variables to find an expression for v(y), i.e., the upwards velcity as a function of y. Assume the initial upwards speed to be vo and the initial position to be y = 0.arrow_forward(b) The coefficient of kinetic friction between a 40 kg crate and the ware- house floor is 70% of the corresponding coefficient of static friction. The crate falls off a forklift that is moving at 3 m/s and then slides along the warehouse floor for a distance of 2.5 m before coming to rest. What is the coefficient of static friction between the crate and the floor?arrow_forward
- Problem 1 ( ) A block of mass m=15 Kg with initial velocity m/s is sliding on a horizontal floor, where the coefficient of kinetic friction is equal to 0. 5. At the end, the block comes to a stop. (Take g=9.8 m/s²). ie g) ) Find FNet- FNet = < h) ( How long will it takes to the block to come to a stop? At =arrow_forwardA 50 kg box is pushed with a force of 200 N along a horizontal surface. If the coefficient of friction between the box and the surface is 0.3, calculate the acceleration of the box. (Note: The gravitational acceleration can be assumed to be 9.8 m/s² unless stated otherwise.)arrow_forwardThe terminal velocity of a human being is 200 km/hr, and it takes about 12 seconds to achieve this. This calculation considers for air friction of course. What would a person’s speed be if they free fell for 12 seconds instead (no air friction present)?arrow_forward
- Principles of Physics: A Calculus-Based TextPhysicsISBN:9781133104261Author:Raymond A. Serway, John W. JewettPublisher:Cengage Learning
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