A+ Guide To It Technical Support
10th Edition
ISBN: 9780357108291
Author: ANDREWS, Jean.
Publisher: Cengage,
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Chapter 5, Problem 8TC
Explanation of Solution
Given: A DVD that has a size of 4.7 GB as marketed by the manufactures, whereas, in explorer, the size is displayed as 4.3 GB.
To find: The reason why manufacturer′s advertisement of the size of the DVD is different than displayed in the explorer...
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Explain how a DVD manufacturer can advertise that a DVD can hold 4.7 GB, but Explorer reports theDVD capacity as 4,706,074,624 bytes or 4.38 GB.a. Manufacturers are allowed to overadvertise their products.b. The manufacturer measures capacity in decimal and the OS measures capacity in binary.c. The actual capacity is 4.7 GB, but the OS requires overhead to manage the DVD and the overheadis not included in the reported DVD capacity.d. The DVD was formatted to have a capacity of 4.38 GB, but it could have been formatted to have acapacity of 4.7 GB.
Q] Consider a disk with a sector size of 512 bytes, 2000 tracks per surface, 50 sectorsPer track, five double-sided platters, and average seek time of 10 msec.a) What is the capacity of a track in bytes?b) What is the capacity of each surface?c) What is the capacity of the disk?d) How many cylinders does the disk have?e) Give examples of valid block sizes. Is 256 bytes a valid block size? 2048?51200?f) If the disk platters rotate at 5400 rpm (revolutions per minute), what is theMaximum rotational delay?
There are many parameters that could be used to describe disk performance;
Which of the following statements is most true?
Note: none of the statements may be true exactly, but one will always be much closer to the truth than the other three. Also note: you should assume all dimensions and parameters of the disk are unchanged except for the ones mentioned.
a) If you double the number of sectors per block, then you halve the capacity of the disk.
b) If you double the rotational speed of the disk, then you halve the average rotational latency.
c) If you divide tracks into half as many blocks, then you double the read time for a block.
d) If you double the number of bits per track, then you double the average rotational latency.
Chapter 5 Solutions
A+ Guide To It Technical Support
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- A) Computer storage manufacturers market their drives in terms of decimal (base 10) capacity like '8TB' of the above PCS product. If you pay $400 for this product, you are buying 8 terabyte (TB) or 8,000,000,000,000 bytes personal cloud storage drive. However, when it is connected to and used by your computer of Windows or some older versions of Mac OS, the operating system will display its capacity in terms of binary (base 2). For example, if Windows or Mac OS (older ones) reports/displays a storage drive's capacity as 5KB, it means 5 x 210 bytes, which is 5 x 1024 or 5120 bytes, not 5000 bytes. In other words, when you read the capacity of a storage which is labeled as 5KB by the manufacturer, your computer will show only 5000/1024 KB or 4.883 KB capacity. This explains why a storage capacity often appears to be less than advertised when displaying in Windows or some Mac operating systems. If you understand this, what actual capacity (in the form of x.xxx TB) would you see in Windows…arrow_forwardFor example, we mentioned in our explanation of the physical elements of disk performance that upgrading from 7,200rpm disks to 10,000rpm disks may result in a performance increase ranging from 10% to 50%. What might possibly cause a 10% increase in performance? Is it possible that there will be no improvement at all? Explain. (Hint: Rotational delay is not the only element that influences the performance of a hard drive.)arrow_forwardConsider a disk with the following characteristics: block size 512 bytes, number of blocks per track=20, number of tracks per surface=400. A disk pack consists of 15 double sided disks. Suppose the disk drive rotates the disk pack at an average speed of 2400 rpm (revolutions per minute) i) How much time in (msec) does one disk revolution take? ii) Using the total capacity of the track as 10240 bytes how many bytes will be transferred from the track in 1 msec (ie transfer rate in bytes/sec)arrow_forward
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- 5.Find out how many parts are there in a floppy disk? Suppose a 3.5 inches floppy disk contained 80 tracks, each of which is divided into sectors capable of holding 512 characters. How many characters will the disk hold if each track is divided into 9 sectors? What if each track contains 18 sectors? How does these capacities compare to the size of 400-page novel in which each page contains 3500 characters?arrow_forwardConsider a disk with the following characteristics: block size 512 bytes, number of blocks per track=20, number of tracks per surface=400. A disk pack consists of 15 double sided disks. i) What is the total capacity of a track? ii) How many cylinders are there? iii) What is the total capacity of a cylinder?arrow_forwardIn our discussion of the physical aspects of disk performance, we stated that replacing 7,200rpm disks with 10,000rpm disks can bring a 10% to 50% performance improvement. Why would an improvement of only 10% occur? Could it be that no improvement at all would occur? Explain. (Hint: Rotational latency is not the only determining factor of disk performance.)arrow_forward
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