COLLEGE PHYSICS-CONNECT ACCESS
COLLEGE PHYSICS-CONNECT ACCESS
5th Edition
ISBN: 9781260486834
Author: GIAMBATTISTA
Publisher: MCG
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Question
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Chapter 5, Problem 91P

(a)

To determine

The radial acceleration of an object at the equator.

(a)

Expert Solution
Check Mark

Answer to Problem 91P

The radial acceleration of an object at the equator is 0.0337m/s2_.

Explanation of Solution

Write the expression for the acceleration.

    ar=rω2        (I)

Here, ar is the radial acceleration, r is the radius of earth, ω is the angular velocity.

Write the expression for ω.

    ω=2πT        (II)

Here, T is the time period.

Use equation (II) in (I) to solve for a

    ar=r(2πT)2        (III)

Conclusion:

Substitute 6.378×108m for r, 24h for T in equation (III) to find ar.

    ar=(6.378×108m)(2πrad24h×3600s1h)2=0.0337m/s2

Therefore, the radial acceleration of an object at the equator is 0.0337m/s2_.

(b)

To determine

Whether the object’s apparent weight greater or lesser than its weight.

(b)

Expert Solution
Check Mark

Answer to Problem 91P

The apparent weight of the object is less than the weight of the object.

Explanation of Solution

Write the expression for the apparent weight of the object.

    W=mar        (IV)

Here, W is the apparent weight.

Write the expression for the actual weight of the object.

    W=mg        (V)

Here, W is the actual mass.

Since the obtained value for the radial acceleration is less than the gravitational field strength (ar<g). As a result, the apparent weight of the object is less than the weight of the object.

Conclusion:

Therefore, the apparent weight of the object is less than the weight of the object.

(c)

To determine

The percentage of apparent weight differ from the weight at the equator.

(c)

Expert Solution
Check Mark

Answer to Problem 91P

The percentage of apparent weight differ from the weight at the equator is 0.344%_.

Explanation of Solution

Write the expression for the percentage of apparent weight differ from the weight at the equator.

    percent between apparent weight and actual weight=WW×100        (VI)

Use equation (IV) and (V) in (VI) to solve for percentage of apparent weight differ from the weight at the equator.

    percent between apparent weight and actual weight=marmg×100=arg×100        (VII)

Conclusion:

Substitute 0.0337m/s2 for ar, 9.8m/s2 for g in equation (VII) to find the percentage of apparent weight differ from the weight at the equator.

    percent between apparent weight and actual weight=0.0337m/s29.8m/s2×100=0.344%

Therefore, the percentage of apparent weight differ from the weight at the equator is 0.344%_.

(d)

To determine

Whether the object’s apparent weight and the actual weight readings are equal on any place on earth.

(d)

Expert Solution
Check Mark

Answer to Problem 91P

The object’s apparent weight and the actual weight readings are equal on the poles of the earth.

Explanation of Solution

The position on the earth where the object’s apparent weight and the actual weight are equal, the ratio of radial acceleration to the force of gravity is unity.

    arg=1ar=g        (VIII)

The poles of the earth, north pole and the south pole have the same radial acceleration and the force of gravity. As a result, the object’s apparent weight and the actual weight readings are equal on the poles of the earth.

Conclusion:

Therefore, the object’s apparent weight and the actual weight readings are equal on the poles of the earth.

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Chapter 5 Solutions

COLLEGE PHYSICS-CONNECT ACCESS

Ch. 5.4 - Prob. 5.8PPCh. 5.4 - Prob. 5.4CPCh. 5.4 - Prob. 5.9PPCh. 5.4 - Prob. 5.10PPCh. 5.5 - Prob. 5.5CPCh. 5.5 - Prob. 5.11PPCh. 5.5 - Prob. 5.12PPCh. 5.6 - Prob. 5.6CPCh. 5.6 - Prob. 5.13PPCh. 5.7 - Prob. 5.14PPCh. 5 - Prob. 1CQCh. 5 - Two children ride on a merry-go-round. One is 2 m...Ch. 5 - Explain why the orbital radius and the speed of a...Ch. 5 - In uniform circular motion, is the velocity...Ch. 5 - In uniform circular motion, the net force is...Ch. 5 - The speed of a satellite in circular orbit around...Ch. 5 - A flywheel (a massive disk) rotates with constant...Ch. 5 - Explain why the force of gravity due to Earth does...Ch. 5 - When a roller coaster takes a sharp turn to the...Ch. 5 - Is there anywhere on Earth where a bathroom scale...Ch. 5 - A physics teacher draws a cutaway view of a car...Ch. 5 - A bridal party is at a rehearsal dinner. The best...Ch. 5 - A leopard starts from rest at t = 0 and runs in a...Ch. 5 - What is the direction of the satellite’s...Ch. 5 - Questions 1–4: A satellite in orbit travels around...Ch. 5 - What is the direction of the satellite’s...Ch. 5 - An object moving in a circle at a constant speed...Ch. 5 - A spider sits on a DVD that is rotating at a...Ch. 5 - Two satellites are in orbit around Mars with the...Ch. 5 - Questions 8–9: A boy swings in a tire swing....Ch. 5 - Prob. 9MCQCh. 5 - Prob. 10MCQCh. 5 - Prob. 11MCQCh. 5 - Prob. 12MCQCh. 5 - Prob. 1PCh. 5 - Prob. 2PCh. 5 - Prob. 3PCh. 5 - Prob. 4PCh. 5 - Prob. 5PCh. 5 - Prob. 6PCh. 5 - Prob. 7PCh. 5 - Dung beetles are renowned for building large...Ch. 5 - Prob. 9PCh. 5 - Prob. 10PCh. 5 - Prob. 11PCh. 5 - Prob. 12PCh. 5 - Prob. 13PCh. 5 - Prob. 14PCh. 5 - Prob. 15PCh. 5 - Prob. 16PCh. 5 - Prob. 17PCh. 5 - Prob. 18PCh. 5 - A child’s toy has a 0.100 kg ball attached to two...Ch. 5 - Prob. 20PCh. 5 - Prob. 21PCh. 5 - A curve in a stretch of highway has radius 512 m....Ch. 5 - Prob. 23PCh. 5 - Prob. 24PCh. 5 - Prob. 25PCh. 5 - Prob. 26PCh. 5 - A car drives around a curve with radius 410 m at a...Ch. 5 - Prob. 28PCh. 5 - A road with a radius of 75.0 m is banked so that...Ch. 5 - Prob. 30PCh. 5 - Prob. 31PCh. 5 - Prob. 32PCh. 5 - Prob. 33PCh. 5 - Prob. 34PCh. 5 - Prob. 35PCh. 5 - Prob. 36PCh. 5 - Prob. 37PCh. 5 - Prob. 38PCh. 5 - Prob. 39PCh. 5 - Prob. 40PCh. 5 - Prob. 41PCh. 5 - Prob. 42PCh. 5 - Prob. 43PCh. 5 - Prob. 44PCh. 5 - Prob. 45PCh. 5 - Prob. 46PCh. 5 - Prob. 47PCh. 5 - Prob. 48PCh. 5 - Prob. 49PCh. 5 - Prob. 50PCh. 5 - Prob. 51PCh. 5 - Prob. 52PCh. 5 - Prob. 53PCh. 5 - Prob. 54PCh. 5 - Prob. 56PCh. 5 - Prob. 57PCh. 5 - Prob. 58PCh. 5 - Prob. 59PCh. 5 - Prob. 60PCh. 5 - A person of mass M stands on a bathroom scale...Ch. 5 - Prob. 62PCh. 5 - Prob. 63PCh. 5 - Prob. 64PCh. 5 - Prob. 65PCh. 5 - Prob. 66PCh. 5 - Prob. 67PCh. 5 - Prob. 68PCh. 5 - Prob. 70PCh. 5 - Prob. 71PCh. 5 - A jogger runs counterclockwise around a path of...Ch. 5 - Prob. 73PCh. 5 - Prob. 74PCh. 5 - Prob. 75PCh. 5 - Prob. 76PCh. 5 - Prob. 77PCh. 5 - Prob. 78PCh. 5 - Prob. 79PCh. 5 - Prob. 81PCh. 5 - Prob. 82PCh. 5 - Prob. 83PCh. 5 - Prob. 84PCh. 5 - Prob. 86PCh. 5 - Prob. 87PCh. 5 - In Chapter 19 we will see that a charged particle...Ch. 5 - Prob. 89PCh. 5 - Prob. 90PCh. 5 - Prob. 91PCh. 5 - Prob. 92PCh. 5 - Prob. 93PCh. 5 - Prob. 94P
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