Holt Mcdougal Larson Pre-algebra: Student Edition 2012

1st Edition

ISBN: 9780547587776

Author: HOLT MCDOUGAL

Publisher: HOLT MCDOUGAL

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Question

Chapter 5.1, Problem 25E

To determine

To find: Rational form of −237 as a quotient of two integers.

Expert Solution & Answer

Answer to Problem 25E

−177 or 17−7 is the rational form of −237 as a quotient of two integers.

Explanation of Solution

Given: Consider, the number −237 provided in question

Calculation:

To convert number −237 as rational, it is needed to simplify the mixed number

Therefore, the obtained fraction is

⇒−237=−(7×2)+37⇒−237=−177⇒−237=−177 or 17−7

Hence,

−177 or 17−7 is the rational form of −237 as a quotient of two integers.

Chapter 5.1, Problem 24E

Chapter 5.1, Problem 26E

Chapter 5 Solutions

Holt Mcdougal Larson Pre-algebra: Student Edition 2012

Ch. 5.1 - Prob. 1C Ch. 5.1 - Prob. 2C Ch. 5.1 - Prob. 3C Ch. 5.1 - Prob. 4C Ch. 5.1 - Prob. 5C Ch. 5.1 - Prob. 1E Ch. 5.1 - Prob. 2E Ch. 5.1 - Prob. 3E Ch. 5.1 - Prob. 4E Ch. 5.1 - Prob. 5E

Ch. 5.1 - Prob. 6E Ch. 5.1 - Prob. 7E Ch. 5.1 - Prob. 8E Ch. 5.1 - Prob. 9E Ch. 5.1 - Prob. 10E Ch. 5.1 - Prob. 11E Ch. 5.1 - Prob. 12E Ch. 5.1 - Prob. 13E Ch. 5.1 - Prob. 14E Ch. 5.1 - Prob. 15E Ch. 5.1 - Prob. 16E Ch. 5.1 - Prob. 17E Ch. 5.1 - Prob. 18E Ch. 5.1 - Prob. 19E Ch. 5.1 - Prob. 20E Ch. 5.1 - Prob. 21E Ch. 5.1 - Prob. 22E Ch. 5.1 - Prob. 23E Ch. 5.1 - Prob. 24E Ch. 5.1 - Prob. 25E Ch. 5.1 - Prob. 26E Ch. 5.1 - Prob. 27E Ch. 5.1 - Prob. 28E Ch. 5.1 - Prob. 29E Ch. 5.1 - Prob. 30E Ch. 5.1 - Prob. 31E Ch. 5.1 - Prob. 32E Ch. 5.1 - Prob. 33E Ch. 5.1 - Prob. 34E Ch. 5.1 - Prob. 35E Ch. 5.1 - Prob. 36E Ch. 5.1 - Prob. 37E Ch. 5.1 - Prob. 38E Ch. 5.1 - Prob. 39E Ch. 5.1 - Prob. 40E Ch. 5.1 - Prob. 41E Ch. 5.1 - Prob. 42E Ch. 5.1 - Prob. 43E Ch. 5.1 - Prob. 44E Ch. 5.1 - Prob. 45E Ch. 5.1 - Prob. 46E Ch. 5.1 - Prob. 47E Ch. 5.1 - Prob. 48E Ch. 5.1 - Prob. 49E Ch. 5.1 - Prob. 50E Ch. 5.1 - Prob. 51E Ch. 5.1 - Prob. 52E Ch. 5.1 - Prob. 53E Ch. 5.1 - Prob. 54E Ch. 5.1 - Prob. 55E Ch. 5.1 - 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Prob. 23E Ch. 5.5 - Prob. 24E Ch. 5.5 - Prob. 25E Ch. 5.5 - Prob. 26E Ch. 5.5 - Prob. 27E Ch. 5.5 - Prob. 28E Ch. 5.5 - Prob. 29E Ch. 5.5 - Prob. 30E Ch. 5.5 - Prob. 31E Ch. 5.5 - Prob. 32E Ch. 5.5 - Prob. 33E Ch. 5.5 - Prob. 34E Ch. 5.5 - Prob. 35E Ch. 5.5 - Prob. 36E Ch. 5.5 - Prob. 37E Ch. 5.5 - Prob. 38E Ch. 5.5 - Prob. 39E Ch. 5.5 - Prob. 40E Ch. 5.5 - Prob. 41E Ch. 5.5 - Prob. 42E Ch. 5.5 - Prob. 43E Ch. 5.5 - Prob. 44E Ch. 5.5 - Prob. 45E Ch. 5.5 - Prob. 46E Ch. 5.5 - Prob. 47E Ch. 5.5 - Prob. 48E Ch. 5.5 - Prob. 49E Ch. 5.5 - Prob. 50E Ch. 5.6 - Prob. 1C Ch. 5.6 - Prob. 2C Ch. 5.6 - Prob. 3C Ch. 5.6 - Prob. 1E Ch. 5.6 - Prob. 2E Ch. 5.6 - Prob. 3E Ch. 5.6 - Prob. 4E Ch. 5.6 - Prob. 5E Ch. 5.6 - Prob. 6E Ch. 5.6 - Prob. 7E Ch. 5.6 - Prob. 8E Ch. 5.6 - Prob. 9E Ch. 5.6 - Prob. 10E Ch. 5.6 - Prob. 11E Ch. 5.6 - Prob. 12E Ch. 5.6 - Prob. 13E Ch. 5.6 - Prob. 14E Ch. 5.6 - Prob. 15E Ch. 5.6 - Prob. 16E Ch. 5.6 - Prob. 17E Ch. 5.6 - Prob. 18E Ch. 5.6 - Prob. 19E Ch. 5.6 - Prob. 20E Ch. 5.6 - Prob. 21E Ch. 5.6 - Prob. 22E Ch. 5.6 - Prob. 23E Ch. 5.6 - Prob. 24E Ch. 5.6 - Prob. 25E Ch. 5.6 - Prob. 26E Ch. 5.6 - Prob. 27E Ch. 5.6 - Prob. 28E Ch. 5.6 - Prob. 29E Ch. 5.6 - Prob. 30E Ch. 5.6 - Prob. 31E Ch. 5.6 - Prob. 32E Ch. 5.6 - Prob. 33E Ch. 5.6 - Prob. 34E Ch. 5.6 - Prob. 35E Ch. 5.6 - Prob. 36E Ch. 5.6 - Prob. 37E Ch. 5.6 - Prob. 38E Ch. 5.6 - Prob. 39E Ch. 5.6 - Prob. 40E Ch. 5.6 - Prob. 41E Ch. 5.6 - Prob. 42E Ch. 5.6 - Prob. 43E Ch. 5.6 - Prob. 44E Ch. 5.7 - Prob. 1C Ch. 5.7 - Prob. 2C Ch. 5.7 - Prob. 3C Ch. 5.7 - Prob. 1E Ch. 5.7 - Prob. 2E Ch. 5.7 - Prob. 3E Ch. 5.7 - Prob. 4E Ch. 5.7 - Prob. 5E Ch. 5.7 - Prob. 6E Ch. 5.7 - Prob. 7E Ch. 5.7 - Prob. 8E Ch. 5.7 - Prob. 9E Ch. 5.7 - Prob. 10E Ch. 5.7 - Prob. 11E Ch. 5.7 - Prob. 12E Ch. 5.7 - Prob. 13E Ch. 5.7 - Prob. 14E Ch. 5.7 - Prob. 15E Ch. 5.7 - Prob. 16E Ch. 5.7 - Prob. 17E Ch. 5.7 - Prob. 18E Ch. 5.7 - Prob. 19E Ch. 5.7 - Prob. 20E Ch. 5.7 - Prob. 21E Ch. 5.7 - Prob. 22E Ch. 5.7 - Prob. 23E Ch. 5.7 - Prob. 24E Ch. 5.7 - Prob. 25E Ch. 5.7 - Prob. 26E Ch. 5.7 - Prob. 27E Ch. 5.7 - Prob. 28E Ch. 5.7 - Prob. 29E Ch. 5.7 - Prob. 30E Ch. 5.7 - Prob. 31E Ch. 5.7 - Prob. 32E Ch. 5.7 - Prob. 33E Ch. 5.7 - Prob. 34E Ch. 5.7 - Prob. 35E Ch. 5.7 - Prob. 36E Ch. 5.7 - Prob. 37E Ch. 5.7 - Prob. 38E Ch. 5.7 - Prob. 39E Ch. 5.7 - Prob. 40E Ch. 5.7 - Prob. 41E Ch. 5.7 - Prob. 42E Ch. 5.7 - Prob. 43E Ch. 5.7 - Prob. 44E Ch. 5.7 - Prob. 45E Ch. 5.7 - Prob. 46E Ch. 5.7 - Prob. 47E Ch. 5.7 - Prob. 48E Ch. 5.7 - Prob. 49E Ch. 5.7 - Prob. 50E Ch. 5.7 - Prob. 51E Ch. 5.7 - Prob. 52E Ch. 5.7 - Prob. 53E Ch. 5.7 - Prob. 54E Ch. 5.7 - Prob. 55E Ch. 5.7 - Prob. 56E Ch. 5.7 - Prob. 57E Ch. 5 - Prob. 1PSQ Ch. 5 - Prob. 2PSQ Ch. 5 - Prob. 3PSQ Ch. 5 - Prob. 4PSQ Ch. 5 - Prob. 5PSQ Ch. 5 - Prob. 6PSQ Ch. 5 - Prob. 7PSQ Ch. 5 - Prob. 8PSQ Ch. 5 - Prob. 9PSQ Ch. 5 - Prob. 10PSQ Ch. 5 - Prob. 11PSQ Ch. 5 - Prob. 12PSQ Ch. 5 - Prob. 13PSQ Ch. 5 - Prob. 14PSQ Ch. 5 - Prob. 15PSQ Ch. 5 - Prob. 16PSQ Ch. 5 - Prob. 17PSQ Ch. 5 - Prob. 1MCQ Ch. 5 - Prob. 2MCQ Ch. 5 - Prob. 3MCQ Ch. 5 - Prob. 4MCQ Ch. 5 - Prob. 5MCQ Ch. 5 - Prob. 6MCQ Ch. 5 - Prob. 7MCQ Ch. 5 - Prob. 8MCQ Ch. 5 - Prob. 9MCQ Ch. 5 - Prob. 10MCQ Ch. 5 - Prob. 11MCQ Ch. 5 - Prob. 12MCQ Ch. 5 - Prob. 13MCQ Ch. 5 - Prob. 14MCQ Ch. 5 - Prob. 15MCQ Ch. 5 - Prob. 16MCQ Ch. 5 - Prob. 17MCQ Ch. 5 - Prob. 18MCQ Ch. 5 - Prob. 19MCQ Ch. 5 - Prob. 20MCQ Ch. 5 - Prob. 21MCQ Ch. 5 - Prob. 22MCQ Ch. 5 - Prob. 23MCQ Ch. 5 - Prob. 24MCQ Ch. 5 - Prob. 25MCQ Ch. 5 - Prob. 1CR Ch. 5 - Prob. 2CR Ch. 5 - Prob. 3CR Ch. 5 - Prob. 4CR Ch. 5 - Prob. 5CR Ch. 5 - Prob. 6CR Ch. 5 - Prob. 7CR Ch. 5 - Prob. 8CR Ch. 5 - Prob. 9CR Ch. 5 - Prob. 10CR Ch. 5 - Prob. 11CR Ch. 5 - Prob. 12CR Ch. 5 - Prob. 13CR Ch. 5 - Prob. 14CR Ch. 5 - Prob. 15CR Ch. 5 - Prob. 16CR Ch. 5 - Prob. 17CR Ch. 5 - Prob. 18CR Ch. 5 - Prob. 19CR Ch. 5 - Prob. 20CR Ch. 5 - Prob. 21CR Ch. 5 - Prob. 22CR Ch. 5 - Prob. 23CR Ch. 5 - Prob. 24CR Ch. 5 - Prob. 25CR Ch. 5 - Prob. 26CR Ch. 5 - Prob. 27CR Ch. 5 - Prob. 28CR Ch. 5 - Prob. 29CR Ch. 5 - Prob. 30CR Ch. 5 - Prob. 31CR Ch. 5 - Prob. 32CR Ch. 5 - Prob. 33CR Ch. 5 - Prob. 34CR Ch. 5 - Prob. 35CR Ch. 5 - Prob. 36CR Ch. 5 - Prob. 37CR Ch. 5 - Prob. 38CR Ch. 5 - Prob. 39CR Ch. 5 - Prob. 40CR Ch. 5 - Prob. 1CT Ch. 5 - Prob. 2CT Ch. 5 - Prob. 3CT Ch. 5 - Prob. 4CT Ch. 5 - Prob. 5CT Ch. 5 - Prob. 6CT Ch. 5 - Prob. 7CT Ch. 5 - Prob. 8CT Ch. 5 - Prob. 9CT Ch. 5 - Prob. 10CT Ch. 5 - Prob. 11CT Ch. 5 - Prob. 12CT Ch. 5 - Prob. 13CT Ch. 5 - Prob. 14CT Ch. 5 - Prob. 15CT Ch. 5 - Prob. 16CT Ch. 5 - Prob. 17CT Ch. 5 - Prob. 18CT Ch. 5 - Prob. 19CT Ch. 5 - Prob. 20CT Ch. 5 - Prob. 21CT Ch. 5 - Prob. 22CT Ch. 5 - Prob. 23CT Ch. 5 - Prob. 24CT Ch. 5 - Prob. 25CT Ch. 5 - Prob. 26CT Ch. 5 - Prob. 27CT Ch. 5 - Prob. 28CT Ch. 5 - Prob. 29CT Ch. 5 - Prob. 30CT Ch. 5 - Prob. 31CT Ch. 5 - Prob. 32CT Ch. 5 - Prob. 33CT Ch. 5 - Prob. 34CT Ch. 5 - Prob. 35CT Ch. 5 - Prob. 1CST Ch. 5 - Prob. 2CST Ch. 5 - Prob. 3CST Ch. 5 - Prob. 4CST Ch. 5 - Prob. 5CST Ch. 5 - Prob. 6CST Ch. 5 - Prob. 7CST Ch. 5 - Prob. 8CST Ch. 5 - 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Rational form of − 2 3 7 as a quotient of two integers.

Videos

To find: Rational form of −237 as a quotient of two integers.

Answer to Problem 25E

Explanation of Solution

Chapter 5 Solutions

Additional Math Textbook Solutions