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Math
GeometryElementary Geometry for College Students6th Edition

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Chapter 5.1, Problem 38E
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Elementary Geometry for College St...

6th Edition
Daniel C. Alexander + 1 other
ISBN: 9781285195698

Solutions

Chapter
Section
Problem 1E
Problem 2E
Problem 3E
Problem 4E
Problem 5E
Problem 6E
Problem 7E
Problem 8E
Problem 9E
Problem 10E
Problem 11E
Problem 12E
Problem 13E
Problem 14E
Problem 15E
Problem 16E
Problem 17E
Problem 18E
Problem 19E
Problem 20E
Problem 21E
Problem 22E
Problem 23E
Problem 24E
Problem 25E
Problem 26E
Problem 27E
Problem 28E
Problem 29E
Problem 30E
Problem 31E
Problem 32E
Problem 33E
Problem 34E
Problem 35E
Problem 36E
Problem 37E
Problem 38E
Problem 39E
Problem 40E
Problem 41E
BuyFindarrow_forward

Elementary Geometry for College St...

6th Edition
Daniel C. Alexander + 1 other
ISBN: 9781285195698
Textbook Problem
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To find the golden ratio (see the Discover activity on page 215), solve the equation 1 L = L − 1 L for L.

(HINT: You will need the Quadratic Formula.)

Chapter 5.1, Problem 38E, To find the golden ratio see the Discover activity on page 215, solve the equation 1L=L1L for L.

To determine

To find:

The solution of L.

Explanation

According to the quadratic formula, the solutions of ax2 + bx + c = 0 are given by

x=−b+b2−4ac2a, −b−b2−4ac2a

Calculation:

Consider, 1L=L−11

⇒L(L−1)=1⋅1⇒L2−L=1⇒L2−L−1=0

Use the quadratic formula in L2−L−1=0

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