Explanation Given: s ( t ) = 1 2 a t 2 + v 0 t + s 0 , s ( 1 ) = − 7 , s ( 2 ) = 12 and s ( 3 ) = 37 Calculation: s ( t ) = 1 2 a t 2 + v 0 t + s 0 Substitute s ( 1 ) = − 7 , s ( 2 ) = 12 and s ( 3 ) = 37 in the above equation to get the following equations. − 7 = 1 2 a ( 1 ) 2 + v 0 ( t ) + s 0 → A − 7 = 1 2 a + v 0 + s 0 12 = 1 2 a ( 2 ) 2 + v 0 ( 2 ) + s 0 → B 12 = 2 a + 2 v 0 + s 0 37 = 1 2 a ( 3 ) 2 + v 0 ( 3 ) + s 0 → C 37 = 9 2 a + 3 v 0 + s 0 Eliminate variable s 0 from equations A and B and from equations B and C A − 7 = 1 2 a + v 0 + s 0 → M u l t i p l y b y − 1 7 = − 1 2 a − v 0 − s 0 B 12 = 2 a + 2 v 0 + s 0 → 12 = 2 a + 2 v 0 + s 0 19 = 3 2 a + v 0 ¯ D B 12 = 2 a + 2 v 0 + s 0 → M u l t i p l y b y − 1 − 12 = − 2 a − 2 v 0 − s 0 C 37 = 9 2 a + 3 v 0 + s 0 → 37 = 9 2 a + 3 v 0 + s 0

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Author: Julie Miller

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Chapter 5.2, Problem 54PE

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To calculate: The values of a,v0 and s0, if s(t)=12at2+v0t+s0, s(1)=−7,s(2)=12 and s(3)=37

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Chapter 5.2, Problem 53PE

Chapter 5.2, Problem 55PE

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The values of a , v 0 and s 0 , if s ( t ) = 1 2 a t 2 + v 0 t + s 0 , s ( 1 ) = − 7 , s ( 2 ) = 12 and s ( 3 ) = 37

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To calculate: The values of a,v0 and s0, if s(t)=12at2+v0t+s0, s(1)=−7,s(2)=12 and s(3)=37

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