Explanation Given Information: The mass of skid steel loader is 1.18 Mg and positioned at G 1 . The mass of stone in the bucket is 300 kg and positioned at G 2 . Convert the mass into weight using the relation: W = m g (1) Here, the mass is m and the acceleration due to gravity is g . Refer to Equation (1): The weight of skid steel loader is ( 1 , 180 × 9.81 ) N . The weight of tone in the bucket is ( 300 × 9.81 ) N . Entire System: Show the free body diagram of the entire system as in Figure (1). Using Figure (1), Moment about point A : Determine the normal reaction at point B by taking moment about point A . ∑ M A = 0 ( 300 × 9.81 × 1.5 ) − ( 1 , 180 × 9.81 × 0.6 ) + N B ( 0.75 ) = 0 4 , 414.5 − 6 , 945.48 + 0.75 N B = 0 0.75 N B = 2 , 530.98 (2) Along the vertical direction: Determine the normal reaction at point A by resolving the vertical component of forces. ∑ F y = 0 N A + N B − ( 300 × 9.81 ) − ( 1 , 180 × 9.81 ) = 0 (3) Conclusion: Solve Equation (2). N B = 2 , 530.98 0.75 = 3 , 374.64 N × ( 1 kN 1,000 N ) = 3.37 kN ( Both wheels ) Thus, the normal reaction at point B , N B is 3.37 kN ( Both wheels ) _ . Substitute 3,374.64 N for N B in Equation (3). N A + 3 , 374.64 − ( 300 × 9.81 ) − ( 1 , 180 × 9.81 ) = 0 N A + 3 , 374.64 − 2 , 943 − 11 , 575.8 = 0 N A = 11 , 144.16 N × ( 1 kN 1,000 N ) = 11.14 kN ( Both wheels ) Thus, the normal reaction at point A , N A is 11.14 kN ( Both wheels ) _ . Upper member: Show the free body diagram of the upper member as in Figure (2). Using Figure (2), Moment about point E : Determine the force in the member CD by taking moment about point E . ∑ M E = 0 300 × 9.81 × 2.75 − F C D sin 30 ° ( 1.25 ) = 0 (4) Along the horizontal direction: Determine the horizontal reaction at point E by resolving the horizontal component of forces. ∑ F x = 0 E x − F C D cos 30 ° = 0 (5) Along the vertical direction: Determine the vertical reaction at point E by resolving the vertical component of forces

Statics and Mechanics of Materials, Student Value Edition (5th Edition)

5th Edition

ISBN: 9780134382890

Author: Russell C. Hibbeler

Publisher: PEARSON

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Chapter 5.5, Problem 55P

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Find the reactions of each pair of wheels A and B on the ground and the force in the hydraulic cylinder CD and at the pin E.

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Chapter 5.5, Problem 54P

Chapter 5.5, Problem 56P

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Statics and Mechanics of Materials, Student Value Edition (5th Edition)

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Find the reactions of each pair of wheels A and B on the ground and the force in the hydraulic cylinder CD and at the pin E .

Solution Summary: The author shows the free body diagram of the entire system as in Figure (1).

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Find the reactions of each pair of wheels A and B on the ground and the force in the hydraulic cylinder CD and at the pin E.

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