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In each part, use the substitution to replace the given
(a)
(b)
(c)
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Chapter 5 Solutions
EBK CALCULUS EARLY TRANSCENDENTALS
Additional Math Textbook Solutions
Calculus and Its Applications (11th Edition)
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- combine the integrals into one integral, then evaluate the integral. L (7x + 4)dx + L (7x + 5)dxarrow_forwardEvaluate the integral (2x + 6) (x² + 6x + 7) ²dx by making the substitution u = x² + 6x + 7. + C NOTE: Your answer should be in terms of a and not u.arrow_forwardEvaluate the complex integral if a = 10, b = 17, c = 20, x = 2, and y = 4. Then, find the imaginary component of the result.arrow_forward
- Use substitution to find the indefinite integral. 6x +5 xp- 3 (9x² + 15x) ** 6x +5 3 (9x? +1 + 15x)arrow_forwardFind the indefinite integral. (Vx +8 xp. Vx +8 -dx = 5 Vx xp.arrow_forwardWrite the integral in terms of u and du. Then evaluate. (8х + 19)-2 dx, и 3 8х + 19 (Use symbolic notation and fractions where needed.) 1 (8x + 19)-2 dx = 8 ( 8x + 19) Incorrect Question Source: Rogawski 4e Calculus Early Transcendentals publisher: W.H. Freemanarrow_forward
- Use the table of integrals, or a computer or calculator with symbolic integration capabilities, to find each indefinite integral. -3 x(8x+3)² Click here to view page 1 of the table of integrals. Click here to view page 2 of the table of integrals. - 3 2 x(8x+3)² -dx -dxarrow_forwardUse substitution to find the indefinite integral. x + 3x dx 6x2 - 1 x* + s+arrow_forwardStep 1 When evaluating Integrals of the form tutx))"u'x) de- du, (n -1), we use an extension of the Powers of x Formula. This formula is called the Power Rule for Integration. + C, (n -1) n+1 Therefore, any Integrand that we can rewrite as the product of a power of a function of x times the derivative of that function can be integrated using this formula. Notice that the Integrand, (8x + 16)*(24x), includes a power of u(x) - Bx+ 16. Let u- + 16, then du = 8 + 16 dx. Thus, we can use the Power Rule for Integration with the power n -4 Submit Skin (you cannot.come.back)arrow_forward
- Calculus: Early TranscendentalsCalculusISBN:9781285741550Author:James StewartPublisher:Cengage LearningThomas' Calculus (14th Edition)CalculusISBN:9780134438986Author:Joel R. Hass, Christopher E. Heil, Maurice D. WeirPublisher:PEARSONCalculus: Early Transcendentals (3rd Edition)CalculusISBN:9780134763644Author:William L. Briggs, Lyle Cochran, Bernard Gillett, Eric SchulzPublisher:PEARSON
- Calculus: Early TranscendentalsCalculusISBN:9781319050740Author:Jon Rogawski, Colin Adams, Robert FranzosaPublisher:W. H. FreemanCalculus: Early Transcendental FunctionsCalculusISBN:9781337552516Author:Ron Larson, Bruce H. EdwardsPublisher:Cengage Learning
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