Chapter 6, Problem 116AE

### Chemistry

10th Edition
Steven S. Zumdahl + 2 others
ISBN: 9781305957404

Chapter
Section

### Chemistry

10th Edition
Steven S. Zumdahl + 2 others
ISBN: 9781305957404
Textbook Problem

# Given the following data Fe 2 O 3 ( s ) + 3 CO ( g ) → 2 Fe ( s ) + 3 CO 2 ( g ) Δ H ° = − 23   KJ 3 Fe 2 O 3 ( s ) + CO ( g ) → 2 Fe 3 O 4 ( s ) + CO 2 ( g ) Δ H ° = − 39   KJ Fe 3 O 4 ( s ) + CO ( g ) → 3 FeO ( s ) + CO 2 ( g ) Δ H ° = 18   KJ Calculate ∆H° for this reaction FeO ( s ) + CO ( g ) → Fe ( s ) + CO 2 ( g )

Interpretation Introduction

Interpretation:  Standard enthalpy change to be calculate by using given data.

Concept introduction

Standard Enthalpy change ( ΔH0 ): The heat change when molar quantities of reactants as specified by chemical equation to form a product at standard conditions.

Standard condition: 250C and 1 atmosphere  pressure.

Explanation

Explanation

The standard enthalpy changes for given reactions are

Fe2O3(s)+3CO(g)â†’2Fe(s)+3CO2(g) Â Î”H0=Â -23kJ

3Fe2O3(s)+CO(g)â†’2Fe3O4(s)+CO2(g) Â Â Â Â Â Â  Â Î”H0=Â -39kJ

Fe3O4(s)+CO(g)â†’3FeO(s)+CO2(g) Â Î”H0=Â 18kJ

6FeO+2CO2â†’2FeO3+42CO Â Â Â Â Â Â Â Â Â Â Â Â Â  Â Î”H0=Â -2(18kJ)

2Fe3O4+CO2â†’2Fe2O3+CO Â Î”H0=Â -(-39kJ)

3Fe2O3+9COâ†’6Fe+9CO2(g) Â Î”H0=Â 3(-23kJ)

6FeO(s)+6CO(g)â†’6Fe(s)+6CO2(g) Â Î”H0=Â -66kJ

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