Concept explainers
(A)
Interpretation:
The number of moles of ions in
(A)
Explanation of Solution
The given balanced equation shows that one mole of
Therefore, the calculated moles of
Three moles of ions are dissolved in one mole
(B)
Interpretation:
The number of moles of ions in
(B)
Explanation of Solution
The given balanced equation shows that one mole of
Therefore, the calculated moles of
Three moles of ions are dissolved in one mole
(C)
Interpretation:
The number of moles of ions that dissolve in
(C)
Explanation of Solution
The given balanced equation shows that one mole of
Therefore, the calculated moles of
(D)
Interpretation:
The number of moles of ions in
(D)
Explanation of Solution
The given balanced equation shows that one mole of
Therefore, the calculated moles of
Three moles of ions are dissolved in one mole
(E)
Interpretation:
The number of moles of ions in
(E)
Explanation of Solution
The given balanced equation shows that one mole of
Therefore, the calculated moles of
Three moles of ions are dissolved in one mole
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Chapter 6 Solutions
INTRO TO CHEMISTRY
- Carbon dioxide from the atmosphere weathers, or dissolves, limestone (CaCO3) by the reaction CaCO3(s)+CO2(g)+H2O(l)Ca2(aq)+2HCO3(aq) Obtain H for this reaction. See Table 6.2 for the data.arrow_forwardAn aqueous sample is known to contain either Pb2+ or Fe3+ ions. Treatment of the sample with Na2SO4 produces a precipitate. Use the solubility rules (see Table 4.1) to determine which cation is present. TABLE 4.1 Solubility Rules for Ionic Compounds in Waterarrow_forwardThere are many ionic compounds that dissolve in water to a very small extent. One example is lead(II) chloride. When it dissolves an equilibrium is established between the solid salt and its component ions. Suppose you stir some solid PbCl2 into water. Explain how you would prove that the compound dissolves but to a small extent? Is the dissolving process product-favored or reactant-favored? pbcl2(s)pb2+(aq)+2cl(aq)arrow_forward
- Nickel(II) sulfide, NiS, occurs naturally as the relatively rare mineral millerite. One of its occurrences is in meteorites. To analyze a mineral sample for the quantity of NiS, the sample is dissolved in nitric add to form a solution of Ni(NO3)2. NiS(s) + 4 HNO3(aq) Ni(NO3)2(aq) + 2 NO2(g) + 2 H2O(l) + S(s) The aqueous solution of Ni(NO3)2 is then reacted with the organic compound dimethylglyoxime (C4H8N2O2) to give the red solid Ni((C4H7N2O2)2. Ni(NO3)2(aq) + 2 (C4H8N2O2)(aq) Ni(C4H7N2O2)2 + 2 HNO3(aq) Suppose a 0.468-g sample containing millerite produces 0.206 g of red, solid Ni(C4H7N2O2)2 What is the mass percent of NiS in the sample?arrow_forwardlist at least three quantities that must be conserved in chemical reactions.arrow_forwardSodium thiosulfate, Na2S2O3, is used as a fixer in black-and-white photography. Suppose you have a bottle of sodium thiosulfate and want to determine its purity. The thiosulfate ion can be oxidized with I2 according to the balanced, net ionic equation I2(aq) + 2 S2O32(aq) 2 I(aq) + S4O62 (aq) If you use 40.21 mL of 0.246 M I2 in a titration, what is the weight percent of Na2S2O3 in a 3.232-g sample of impure material?arrow_forward
- The carbon dioxide exhaled in the breath of astronauts is often removed from the spacecraft by reaction with lithium hydroxide 2LiOH(s)+CO2(g)Li2CO3(s)+H2O(l) Estimate the grams of lithium hydroxide required per astronaut per day. Assume that each astronaut requires 2.50 103 kcal of energy per day. Further assume that this energy can be equated to the heat of combustion of a quantity of glucose, C6H12O6, to CO2(g) and H2O(l). From the amount of glucose required to give 2.50 103 kcal of heat, calculate the amount of CO2 produced and hence the amount of LiOH required. The H for glucose(s) is 1273 kJ/mol.arrow_forwardLet us explore a reaction with a limiting reactant. Here, zinc metal is added to a flask containing aqueous HCl, and H2 gas is a product. Zn(s) + 2 HCl(aq) ZnCl2(aq) + H2(g) The three flasks each contain 0.100 mol of HCl. Zinc is added to each flask in the following quantities. When the reactants are combined, the H2 inflates the balloon attached to the flask. The results are as follows: Flask 1: Balloon inflates completely, but some Zn remains when inflation ceases. Flask 2: Balloon inflates completely. No Zn remains. Flask 3: Balloon does not inflate completely. No Zn remains. Explain these results. Perform calculations that support your explanation.arrow_forward
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