Chapter 6, Problem 20RE

Explanation of Solution

a. The given code:

//creating a variable “s”. “s” is initializing with “s”.

int s = 1;

creating a variable n and initializes with 1.

int n = 1;

//iterate while loop up to condition “s<10”

while (s < 10)

{

    //the variable x is changed to “x + s”

    s = s + n;

}

//incrementing the value of n by “1”.

n++;

Explanation:

The above snippet of code is used to demonstrate “while” loop. In the code,

• Scan for the value “n” using object of “Scanner” class.
• A double variable “x” is created and initialized with “0”.
• A double variable “s” is created.
• Iterate “while” loop up to the condition “s > 0.01”.
  • Variable “s” is assigned with “1.0 / (1 + n * n)”.
  • “n” is incremented by “1”.
  • The variable “x” is added with “s”.

Trace table for the code snippet:

s = 1 and n = 1 s = 2 and n = 1 s = 3 and n = 1 s = 4 and n = 1 s = 5 and n = 1 s = 6 and n = 1 s = 7 and n = 1 s = 8 and n = 1 s = 9 and n = 1 s = 10 and n = 1 s = 10 and n = 2

b. The given code:

// Creating a variable “s” and initializing with “1”.

int s = 1;

// iterating for loop up to “n<5”.

for (int n = 1; n < 5; n++)

{

    // the variable s is changed to “s+ n”

    s = s + n;

}

Explanation:

The above snippet of code is used to demonstrate “for” loop...