Chapter 6, Problem 24SP

A force of 3.0 N acts through a distance of 12 m in the direction of the force. Find the work done.

To determine

The work done by a force of $3\text{ N}$ that acts through the distance of $12\text{ m}$ in the direction of force.

Answer to Problem 24SP

Solution:

$36\text{ J}$

Explanation of Solution

Given data:

The force applied is $3.0\text{ N}$.

The distance through which the force is applied is $12\text{ m}$.

Formula used:

The expression of work done is written as,

$W=Fs\cos \theta$

Here, $W$ is the work done, $F$ is the force, $\theta$ is the angle between force and displacement, and $s$ is the displacement.

Explanation:

Recall the expression of work done.

$W=Fs\cos \theta$

Understand that the force is acting in the direction of displacement. Therefore, $\theta =0°$

Substitute $3.0\text{ N}$ for $F$, $0°$ for $\theta$, and $12\text{ m}$ for $s$

$\begin{array}{c}W=\left(3.0\text{ N}\right)\left(12\text{ m}\right)\cos 0°\\ =36\text{ J}\end{array}$

Conclusion:

Therefore, the work done is $36\text{ J}$.