The molecular formula C 5 H 8 is straight-chain as an alkane, an alkene or alkynes have to be classified. Concept Introduction: The formulas of alkanes are C n H 2n+2 , for n = 1 and higher. Each multiple bond removes two electrons. The formulas of alkenes are C n H 2n , for n = 2 and higher. The formulas Covalent Bonding of alkynes are C n H 2n-2 , for n = 2 and higher.
The molecular formula C 5 H 8 is straight-chain as an alkane, an alkene or alkynes have to be classified. Concept Introduction: The formulas of alkanes are C n H 2n+2 , for n = 1 and higher. Each multiple bond removes two electrons. The formulas of alkenes are C n H 2n , for n = 2 and higher. The formulas Covalent Bonding of alkynes are C n H 2n-2 , for n = 2 and higher.
Solution Summary: The author explains the formulas of alkanes and alkynes.
Definition Definition Simplest organic compounds that contain only single bonds between carbon – carbon atoms and carbon – hydrogen bonds. This means they are a series of saturated compounds with a general molecular formula, C n H 2n+2 .
Chapter 6, Problem 25QRT
(a)
Interpretation Introduction
Interpretation:
The molecular formula C5H8 is straight-chain as an alkane, an alkene or alkynes have to be classified.
Concept Introduction:
The formulas of alkanes are CnH2n+2, for n = 1 and higher. Each multiple bond removes two electrons.
The formulas of alkenes are CnH2n, for n = 2 and higher.
The formulas Covalent Bonding of alkynes are CnH2n-2, for n = 2 and higher.
(b)
Interpretation Introduction
Interpretation:
The molecular formula C24H50 is straight-chain as an alkane, an alkene or alkynes have to be classified.
Concept Introduction:
Refer to part (a).
(c)
Interpretation Introduction
Interpretation:
The molecular formula C7H14 is straight-chain as an alkane, an alkene or alkynes have to be classified.
For the four classes of hydrocarbons (Alkane, Alkene, Alkyne, Arene): Give a structural formula example of each, or identify the characteristic bond that is present.
The organic molecules shown here are derivatives of benzene in which six-membered rings are “fused” at the edges of the hexagons. (a) Determine the empirical formula of benzene and of these three compounds. (b) Suppose you are given a sample of one of the compounds. Could combustion analysis be used to determine unambiguously which of the three it is? (c) Naphthalene, the active ingredient in mothballs, is a white solid. Write a balanced equation for the combustion of naphthalene to CO2(g) and H2O(g). (d) Using the Lewis structure for naphthalene and the average bond enthalpies in Table 8.4, estimate the heat of combustion of naphthalene in kJ/mol. (e) Would you expect naphthalene, anthracene, and tetracene to have multiple resonance structures? If so, draw the additional resonance structures for naphthalene. (f) Benzene, naphthalene, and anthracene are colorless, but tetracene is orange. What does this imply…
Chapter 6 Solutions
OWLv2 for Moore/Stanitski's Chemistry: The Molecular Science, 5th Edition, [Instant Access], 1 term (6 months)